问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
简单易读版本:
const relativeTimePeriods = [
[31536000, 'year'],
[2419200, 'month'],
[604800, 'week'],
[86400, 'day'],
[3600, 'hour'],
[60, 'minute'],
[1, 'second']
];
function relativeTime(date, isUtc=true) {
if (!(date instanceof Date)) date = new Date(date * 1000);
const seconds = (new Date() - date) / 1000;
for (let [secondsPer, name] of relativeTimePeriods) {
if (seconds >= secondsPer) {
const amount = Math.floor(seconds / secondsPer);
return `${amount} ${name}${amount ? 's' : ''}s ago`;
}
}
return 'Just now';
}
其他回答
function timeSince(date) { var seconds = Math.floor((new Date() - date) / 1000); var interval = seconds / 31536000; if (interval > 1) { return Math.floor(interval) + " years"; } interval = seconds / 2592000; if (interval > 1) { return Math.floor(interval) + " months"; } interval = seconds / 86400; if (interval > 1) { return Math.floor(interval) + " days"; } interval = seconds / 3600; if (interval > 1) { return Math.floor(interval) + " hours"; } interval = seconds / 60; if (interval > 1) { return Math.floor(interval) + " minutes"; } return Math.floor(seconds) + " seconds"; } var aDay = 24*60*60*1000; console.log(timeSince(new Date(Date.now()-aDay))); console.log(timeSince(new Date(Date.now()-aDay*2)));
可读性强且跨浏览器兼容的代码:
@Travis给出的
var DURATION_IN_SECONDS = { epochs: ['year', 'month', 'day', 'hour', 'minute'], year: 31536000, month: 2592000, day: 86400, hour: 3600, minute: 60 }; function getDuration(seconds) { var epoch, interval; for (var i = 0; i < DURATION_IN_SECONDS.epochs.length; i++) { epoch = DURATION_IN_SECONDS.epochs[i]; interval = Math.floor(seconds / DURATION_IN_SECONDS[epoch]); if (interval >= 1) { return { interval: interval, epoch: epoch }; } } }; function timeSince(date) { var seconds = Math.floor((new Date() - new Date(date)) / 1000); var duration = getDuration(seconds); var suffix = (duration.interval > 1 || duration.interval === 0) ? 's' : ''; return duration.interval + ' ' + duration.epoch + suffix; }; alert(timeSince('2015-09-17T18:53:23'));
简单易读版本:
const relativeTimePeriods = [
[31536000, 'year'],
[2419200, 'month'],
[604800, 'week'],
[86400, 'day'],
[3600, 'hour'],
[60, 'minute'],
[1, 'second']
];
function relativeTime(date, isUtc=true) {
if (!(date instanceof Date)) date = new Date(date * 1000);
const seconds = (new Date() - date) / 1000;
for (let [secondsPer, name] of relativeTimePeriods) {
if (seconds >= secondsPer) {
const amount = Math.floor(seconds / secondsPer);
return `${amount} ${name}${amount ? 's' : ''}s ago`;
}
}
return 'Just now';
}
由@user1012181提供的ES6版本代码:
const epochs = [
['year', 31536000],
['month', 2592000],
['day', 86400],
['hour', 3600],
['minute', 60],
['second', 1]
];
const getDuration = (timeAgoInSeconds) => {
for (let [name, seconds] of epochs) {
const interval = Math.floor(timeAgoInSeconds / seconds);
if (interval >= 1) {
return {
interval: interval,
epoch: name
};
}
}
};
const timeAgo = (date) => {
const timeAgoInSeconds = Math.floor((new Date() - new Date(date)) / 1000);
const {interval, epoch} = getDuration(timeAgoInSeconds);
const suffix = interval === 1 ? '' : 's';
return `${interval} ${epoch}${suffix} ago`;
};
由@ibe-vanmeenen编辑建议。(谢谢!)
这是我的版本,它既适用于过去的日期,也适用于未来的日期。 它使用Intl。RelativeTimeFormat提供本地化字符串,而不是硬编码字符串。 您可以将日期作为时间戳、日期对象或可解析的日期字符串传递。
/** * Human readable elapsed or remaining time (example: 3 minutes ago) * @param {Date|Number|String} date A Date object, timestamp or string parsable with Date.parse() * @param {Date|Number|String} [nowDate] A Date object, timestamp or string parsable with Date.parse() * @param {Intl.RelativeTimeFormat} [trf] A Intl formater * @return {string} Human readable elapsed or remaining time * @author github.com/victornpb * @see https://stackoverflow.com/a/67338038/938822 */ function fromNow(date, nowDate = Date.now(), rft = new Intl.RelativeTimeFormat(undefined, { numeric: "auto" })) { const SECOND = 1000; const MINUTE = 60 * SECOND; const HOUR = 60 * MINUTE; const DAY = 24 * HOUR; const WEEK = 7 * DAY; const MONTH = 30 * DAY; const YEAR = 365 * DAY; const intervals = [ { ge: YEAR, divisor: YEAR, unit: 'year' }, { ge: MONTH, divisor: MONTH, unit: 'month' }, { ge: WEEK, divisor: WEEK, unit: 'week' }, { ge: DAY, divisor: DAY, unit: 'day' }, { ge: HOUR, divisor: HOUR, unit: 'hour' }, { ge: MINUTE, divisor: MINUTE, unit: 'minute' }, { ge: 30 * SECOND, divisor: SECOND, unit: 'seconds' }, { ge: 0, divisor: 1, text: 'just now' }, ]; const now = typeof nowDate === 'object' ? nowDate.getTime() : new Date(nowDate).getTime(); const diff = now - (typeof date === 'object' ? date : new Date(date)).getTime(); const diffAbs = Math.abs(diff); for (const interval of intervals) { if (diffAbs >= interval.ge) { const x = Math.round(Math.abs(diff) / interval.divisor); const isFuture = diff < 0; return interval.unit ? rft.format(isFuture ? x : -x, interval.unit) : interval.text; } } }
// examples
fromNow('2020-01-01') // 9 months ago
fromNow(161651684156) // 4 days ago
fromNow(new Date()-1) // just now
fromNow(30000 + Date.now()) // in 30 seconds
fromNow(Date.now() + (1000*60*60*24)) // in 1 day
fromNow(new Date('2029-12-01Z00:00:00.000')) // in 9 years
不使用Intl的替代方法。RelativeTimeFormat
/** * Human readable elapsed or remaining time (example: 3 minutes ago) * @param {Date|Number|String} date A Date object, timestamp or string parsable with Date.parse() * @return {string} Human readable elapsed or remaining time * @author github.com/victornpb * @see https://stackoverflow.com/a/67338038/938822 */ function fromNow(date) { const SECOND = 1000; const MINUTE = 60 * SECOND; const HOUR = 60 * MINUTE; const DAY = 24 * HOUR; const WEEK = 7 * DAY; const MONTH = 30 * DAY; const YEAR = 365 * DAY; const units = [ { max: 30 * SECOND, divisor: 1, past1: 'just now', pastN: 'just now', future1: 'just now', futureN: 'just now' }, { max: MINUTE, divisor: SECOND, past1: 'a second ago', pastN: '# seconds ago', future1: 'in a second', futureN: 'in # seconds' }, { max: HOUR, divisor: MINUTE, past1: 'a minute ago', pastN: '# minutes ago', future1: 'in a minute', futureN: 'in # minutes' }, { max: DAY, divisor: HOUR, past1: 'an hour ago', pastN: '# hours ago', future1: 'in an hour', futureN: 'in # hours' }, { max: WEEK, divisor: DAY, past1: 'yesterday', pastN: '# days ago', future1: 'tomorrow', futureN: 'in # days' }, { max: 4 * WEEK, divisor: WEEK, past1: 'last week', pastN: '# weeks ago', future1: 'in a week', futureN: 'in # weeks' }, { max: YEAR, divisor: MONTH, past1: 'last month', pastN: '# months ago', future1: 'in a month', futureN: 'in # months' }, { max: 100 * YEAR, divisor: YEAR, past1: 'last year', pastN: '# years ago', future1: 'in a year', futureN: 'in # years' }, { max: 1000 * YEAR, divisor: 100 * YEAR, past1: 'last century', pastN: '# centuries ago', future1: 'in a century', futureN: 'in # centuries' }, { max: Infinity, divisor: 1000 * YEAR, past1: 'last millennium', pastN: '# millennia ago', future1: 'in a millennium', futureN: 'in # millennia' }, ]; const diff = Date.now() - (typeof date === 'object' ? date : new Date(date)).getTime(); const diffAbs = Math.abs(diff); for (const unit of units) { if (diffAbs < unit.max) { const isFuture = diff < 0; const x = Math.round(Math.abs(diff) / unit.divisor); if (x <= 1) return isFuture ? unit.future1 : unit.past1; return (isFuture ? unit.futureN : unit.pastN).replace('#', x); } } };