问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
function mdiv(dividend, divisor) {
return [ Math.floor(dividend/divisor), dividend % divisor ];
}
// pass in milliseconds, gained by Date1.getTime() - Date2.getTime()
// if max_units is two, the result will be, for example
// 2years 12months ago, or 2hours 38minutes ago
// return formated period
function readable_period(ms, max_units=2){
let [yy, yr] = mdiv(ms, 3.154e10);
let [mm, mr] = mdiv(yr, 2.628e9);
let [dd, dr] = mdiv(mr, 8.64e7);
let [hh, hr] = mdiv(dr, 3.6e6);
let [tt, ss] = mdiv(hr, 6e4);
var ymdht = ['year', 'month', 'day', 'hour', 'minute'];
let res = [];
[yy, mm, dd, hh, tt].forEach((tis, ii)=>{
if(res.length === max_units){return};
if(tis !== 0){
res.push(tis === 1 ? `${tis}${ymdht[ii]}` : `${tis}${ymdht[ii]}s`);
}
});
return res.length === 0 ? '' : res.join(' ') + ' ago';
}
其他回答
function timeSince(date) { var seconds = Math.floor((new Date() - date) / 1000); var interval = seconds / 31536000; if (interval > 1) { return Math.floor(interval) + " years"; } interval = seconds / 2592000; if (interval > 1) { return Math.floor(interval) + " months"; } interval = seconds / 86400; if (interval > 1) { return Math.floor(interval) + " days"; } interval = seconds / 3600; if (interval > 1) { return Math.floor(interval) + " hours"; } interval = seconds / 60; if (interval > 1) { return Math.floor(interval) + " minutes"; } return Math.floor(seconds) + " seconds"; } var aDay = 24*60*60*1000; console.log(timeSince(new Date(Date.now()-aDay))); console.log(timeSince(new Date(Date.now()-aDay*2)));
我用js和python写了一个,在两个项目中使用,非常漂亮和简单:一个简单的库(少于2kb),用于*** time ago语句格式化日期。
简单,小巧,易于使用,并且经过良好测试。
NPM安装timeago.js 从timeago.js导入timeago;//或使用脚本标签 使用API格式。
示例:
var timeagoIns = timeago();
timeagoIns .format('2016-06-12');
你也可以实时渲染。
var timeagoIns = timeago();
timeagoIns.render(document.querySelectorAll('time'));
这是一个简化版的@sky-sanders的回答。
function timeSince(date) {
var seconds = Math.floor((new Date() - date) / 1000);
var divisors = [31536000, 2592000, 86400, 3600, 60, 1]
var description = ["years", "months", "days", "hours", "minutes", "seconds"]
var result = [];
var interval = seconds;
for (i = 0; i < divisors.length; i++) {
interval = Math.floor(seconds / divisors[i])
if (interval > 1) {
result.push(interval + " " + description[i])
}
seconds -= interval * divisors[i]
}
return result.join(" ")
}
可读性强且跨浏览器兼容的代码:
@Travis给出的
var DURATION_IN_SECONDS = { epochs: ['year', 'month', 'day', 'hour', 'minute'], year: 31536000, month: 2592000, day: 86400, hour: 3600, minute: 60 }; function getDuration(seconds) { var epoch, interval; for (var i = 0; i < DURATION_IN_SECONDS.epochs.length; i++) { epoch = DURATION_IN_SECONDS.epochs[i]; interval = Math.floor(seconds / DURATION_IN_SECONDS[epoch]); if (interval >= 1) { return { interval: interval, epoch: epoch }; } } }; function timeSince(date) { var seconds = Math.floor((new Date() - new Date(date)) / 1000); var duration = getDuration(seconds); var suffix = (duration.interval > 1 || duration.interval === 0) ? 's' : ''; return duration.interval + ' ' + duration.epoch + suffix; }; alert(timeSince('2015-09-17T18:53:23'));
也可以使用dayjs的relativeTime插件来解决这个问题。
import * as dayjs from 'dayjs';
import * as relativeTime from 'dayjs/plugin/relativeTime';
dayjs.extend(relativeTime);
dayjs(dayjs('1990')).fromNow(); // x years ago