如何格式化时间自xxx例如“4分钟前”类似于堆栈交换网站

问题是如何将JavaScript Date格式化为一个字符串，声明时间经过，类似于您在Stack Overflow上看到的时间显示方式。

e.g.

1分钟前 1小时前 1天前 1个月前一年前

当前回答

我使用了可能11的旧答案，并添加了Intl。用于翻译的RelativeTimeFormat。

https://stackoverflow.com/a/73331658/673809

function timeAgo (value) { const seconds = Math.floor((new Date().getTime() - new Date(value).getTime()) / 1000) let interval = seconds / 31536000 const rtf = new Intl.RelativeTimeFormat("en", { numeric: 'auto' }) if (interval > 1) { return rtf.format(-Math.floor(interval), 'year') } interval = seconds / 2592000 if (interval > 1) { return rtf.format(-Math.floor(interval), 'month') } interval = seconds / 86400 if (interval > 1) { return rtf.format(-Math.floor(interval), 'day') } interval = seconds / 3600 if (interval > 1) { return rtf.format(-Math.floor(interval), 'hour') } interval = seconds / 60 if (interval > 1) { return rtf.format(-Math.floor(interval), 'minute') } return rtf.format(-Math.floor(interval), 'second') } console.log(timeAgo('2022-08-12 20:50:20'))

2022-12-14 11:32:39

其他回答

function dateToHowManyAgo(stringDate){
    var currDate = new Date();
    var diffMs=currDate.getTime() - new Date(stringDate).getTime();
    var sec=diffMs/1000;
    if(sec<60)
        return parseInt(sec)+' second'+(parseInt(sec)>1?'s':'')+' ago';
    var min=sec/60;
    if(min<60)
        return parseInt(min)+' minute'+(parseInt(min)>1?'s':'')+' ago';
    var h=min/60;
    if(h<24)
        return parseInt(h)+' hour'+(parseInt(h)>1?'s':'')+' ago';
    var d=h/24;
    if(d<30)
        return parseInt(d)+' day'+(parseInt(d)>1?'s':'')+' ago';
    var m=d/30;
    if(m<12)
        return parseInt(m)+' month'+(parseInt(m)>1?'s':'')+' ago';
    var y=m/12;
    return parseInt(y)+' year'+(parseInt(y)>1?'s':'')+' ago';
}
console.log(dateToHowManyAgo('2019-11-07 19:17:06'));

2019-11-07 19:50:47

从现在开始，Unix时间戳参数

function timeSince(ts){
    now = new Date();
    ts = new Date(ts*1000);
    var delta = now.getTime() - ts.getTime();

    delta = delta/1000; //us to s

    var ps, pm, ph, pd, min, hou, sec, days;

    if(delta<=59){
        ps = (delta>1) ? "s": "";
        return delta+" second"+ps
    }

    if(delta>=60 && delta<=3599){
        min = Math.floor(delta/60);
        sec = delta-(min*60);
        pm = (min>1) ? "s": "";
        ps = (sec>1) ? "s": "";
        return min+" minute"+pm+" "+sec+" second"+ps;
    }

    if(delta>=3600 && delta<=86399){
        hou = Math.floor(delta/3600);
        min = Math.floor((delta-(hou*3600))/60);
        ph = (hou>1) ? "s": "";
        pm = (min>1) ? "s": "";
        return hou+" hour"+ph+" "+min+" minute"+pm;
    } 

    if(delta>=86400){
        days = Math.floor(delta/86400);
        hou =  Math.floor((delta-(days*86400))/60/60);
        pd = (days>1) ? "s": "";
        ph = (hou>1) ? "s": "";
        return days+" day"+pd+" "+hou+" hour"+ph;
    }

}

2012-11-10 15:03:46

将上面的函数更改为

function timeSince(date) {

    var seconds = Math.floor(((new Date().getTime()/1000) - date)),
    interval = Math.floor(seconds / 31536000);

    if (interval > 1) return interval + "y";

    interval = Math.floor(seconds / 2592000);
    if (interval > 1) return interval + "m";

    interval = Math.floor(seconds / 86400);
    if (interval >= 1) return interval + "d";

    interval = Math.floor(seconds / 3600);
    if (interval >= 1) return interval + "h";

    interval = Math.floor(seconds / 60);
    if (interval > 1) return interval + "m ";

    return Math.floor(seconds) + "s";
}

否则它会显示“75分钟”(介于1到2小时之间)。它现在还假定输入日期是Unix时间戳。

2011-11-23 18:13:53

以下是对Sky Sander的解决方案的轻微修改，允许日期作为字符串输入，并能够显示像“1分钟”而不是“73秒”这样的跨度

2014-04-24 03:30:12

如果你已经在使用date-fns，你可以使用内置的formatDistance(以前是distanceInWords):

const date1 = new Date(2014, 6, 2);
const date2 = new Date(2015, 0, 1);
const options = { addSuffix: true }
const result = formatDistance(date1, date2, options);
//=> '6 months ago'

2022-07-26 22:59:22

如何格式化时间自xxx例如“4分钟前”类似于堆栈交换网站

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