这些答案大多不能解释复数(例如:复数)。当我们想要“1分钟前”时，用“1分钟前”)

const MINUTE = 60;
const HOUR = MINUTE * 60;
const DAY = HOUR * 24;
const WEEK = DAY * 7;
const MONTH = DAY * 30;
const YEAR = DAY * 365;

function getTimeAgo(date) {
  const secondsAgo = Math.round((Date.now() - Number(date)) / 1000);

  if (secondsAgo < MINUTE) {
    return secondsAgo + ` second${secondsAgo !== 1 ? "s" : ""} ago`;
  }

  let divisor;
  let unit = "";

  if (secondsAgo < HOUR) {
    [divisor, unit] = [MINUTE, "minute"];
  } else if (secondsAgo < DAY) {
    [divisor, unit] = [HOUR, "hour"];
  } else if (secondsAgo < WEEK) {
    [divisor, unit] = [DAY, "day"];
  } else if (secondsAgo < MONTH) {
    [divisor, unit] = [WEEK, "week"];
  } else if (secondsAgo < YEAR) {
    [divisor, unit] = [MONTH, "month"];
  } else {
    [divisor, unit] = [YEAR, "year"];
  }

  const count = Math.floor(secondsAgo / divisor);
  return `${count} ${unit}${count > 1 ? "s" : ""} ago`;
}

然后你可以这样使用它:

const date = new Date();
console.log(getTimeAgo(date));
// 1 second ago
// 2 seconds ago
// 1 minute ago
// 2 minutes ago
// ...

可读性强且跨浏览器兼容的代码:

@Travis给出的

var DURATION_IN_SECONDS = { epochs: ['year', 'month', 'day', 'hour', 'minute'], year: 31536000, month: 2592000, day: 86400, hour: 3600, minute: 60 }; function getDuration(seconds) { var epoch, interval; for (var i = 0; i < DURATION_IN_SECONDS.epochs.length; i++) { epoch = DURATION_IN_SECONDS.epochs[i]; interval = Math.floor(seconds / DURATION_IN_SECONDS[epoch]); if (interval >= 1) { return { interval: interval, epoch: epoch }; } } }; function timeSince(date) { var seconds = Math.floor((new Date() - new Date(date)) / 1000); var duration = getDuration(seconds); var suffix = (duration.interval > 1 || duration.interval === 0) ? 's' : ''; return duration.interval + ' ' + duration.epoch + suffix; }; alert(timeSince('2015-09-17T18:53:23'));

这应该正确地处理任何有效的时间戳，包括Date.now()、单数单位和未来日期。我漏掉了月份，但是这些月份应该很容易加进去。我尽量保持它的可读性。

function getTimeInterval(date) { let seconds = Math.floor((Date.now() - date) / 1000); let unit = "second"; let direction = "ago"; if (seconds < 0) { seconds = -seconds; direction = "from now"; } let value = seconds; if (seconds >= 31536000) { value = Math.floor(seconds / 31536000); unit = "year"; } else if (seconds >= 86400) { value = Math.floor(seconds / 86400); unit = "day"; } else if (seconds >= 3600) { value = Math.floor(seconds / 3600); unit = "hour"; } else if (seconds >= 60) { value = Math.floor(seconds / 60); unit = "minute"; } if (value != 1) unit = unit + "s"; return value + " " + unit + " " + direction; } console.log(getTimeInterval(Date.now())); // 0 seconds ago console.log(getTimeInterval(Date.now() + 1000)); // 1 second from now console.log(getTimeInterval(Date.now() - 1000)); // 1 second ago console.log(getTimeInterval(Date.now() + 60000)); // 1 minute from now console.log(getTimeInterval(Date.now() - 120000)); // 2 minutes ago console.log(getTimeInterval(Date.now() + 120000)); // 2 minutes from now console.log(getTimeInterval(Date.now() + 3600000)); // 1 hour from now console.log(getTimeInterval(Date.now() + 360000000000)); // 11 years from now console.log(getTimeInterval(0)); // 49 years ago

 I achieve this by following method

   timeAgo = (date) => {
            var ms = (new Date()).getTime() - date.getTime();
            var seconds = Math.floor(ms / 1000);
            var minutes = Math.floor(seconds / 60);
        var hours = Math.floor(minutes / 60);
        var days = Math.floor(hours / 24);
        var months = Math.floor(days / 30);
        var years = Math.floor(months / 12);
    
        if (ms === 0) {
            return 'Just now';
        } if (seconds < 60) {
            return seconds + ' seconds Ago';
        } if (minutes < 60) {
            return minutes + ' minutes Ago';
        } if (hours < 24) {
            return hours + ' hours Ago';
        } if (days < 30) {
            return days + ' days Ago';
        } if (months < 12) {
            return months + ' months Ago';
        } else {
            return years + ' years Ago';
        }
    
    }
    
        console.log(timeAgo(new Date()));
        console.log(timeAgo(new Date('Jun 27 2020 10:12:19')));
        console.log(timeAgo(new Date('Jun 27 2020 00:12:19')));
        console.log(timeAgo(new Date('May 28 2020 13:12:19')));
        console.log(timeAgo(new Date('May 28 2017 13:12:19')));

我使用了可能11的旧答案，并添加了Intl。用于翻译的RelativeTimeFormat。

https://stackoverflow.com/a/73331658/673809

function timeAgo (value) { const seconds = Math.floor((new Date().getTime() - new Date(value).getTime()) / 1000) let interval = seconds / 31536000 const rtf = new Intl.RelativeTimeFormat("en", { numeric: 'auto' }) if (interval > 1) { return rtf.format(-Math.floor(interval), 'year') } interval = seconds / 2592000 if (interval > 1) { return rtf.format(-Math.floor(interval), 'month') } interval = seconds / 86400 if (interval > 1) { return rtf.format(-Math.floor(interval), 'day') } interval = seconds / 3600 if (interval > 1) { return rtf.format(-Math.floor(interval), 'hour') } interval = seconds / 60 if (interval > 1) { return rtf.format(-Math.floor(interval), 'minute') } return rtf.format(-Math.floor(interval), 'second') } console.log(timeAgo('2022-08-12 20:50:20'))

将上面的函数更改为

function timeSince(date) {

    var seconds = Math.floor(((new Date().getTime()/1000) - date)),
    interval = Math.floor(seconds / 31536000);

    if (interval > 1) return interval + "y";

    interval = Math.floor(seconds / 2592000);
    if (interval > 1) return interval + "m";

    interval = Math.floor(seconds / 86400);
    if (interval >= 1) return interval + "d";

    interval = Math.floor(seconds / 3600);
    if (interval >= 1) return interval + "h";

    interval = Math.floor(seconds / 60);
    if (interval > 1) return interval + "m ";

    return Math.floor(seconds) + "s";
}

否则它会显示“75分钟”(介于1到2小时之间)。它现在还假定输入日期是Unix时间戳。