问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。

e.g.

1分钟前 1小时前 1天前 1个月前 一年前


当前回答

由@user1012181提供的ES6版本代码:

const epochs = [
    ['year', 31536000],
    ['month', 2592000],
    ['day', 86400],
    ['hour', 3600],
    ['minute', 60],
    ['second', 1]
];

const getDuration = (timeAgoInSeconds) => {
    for (let [name, seconds] of epochs) {
        const interval = Math.floor(timeAgoInSeconds / seconds);
        if (interval >= 1) {
            return {
                interval: interval,
                epoch: name
            };
        }
    }
};

const timeAgo = (date) => {
    const timeAgoInSeconds = Math.floor((new Date() - new Date(date)) / 1000);
    const {interval, epoch} = getDuration(timeAgoInSeconds);
    const suffix = interval === 1 ? '' : 's';
    return `${interval} ${epoch}${suffix} ago`;
};

由@ibe-vanmeenen编辑建议。(谢谢!)

其他回答

我的尝试是基于其他的答案。

function timeSince(date) {
    let minute = 60;
    let hour   = minute * 60;
    let day    = hour   * 24;
    let month  = day    * 30;
    let year   = day    * 365;

    let suffix = ' ago';

    let elapsed = Math.floor((Date.now() - date) / 1000);

    if (elapsed < minute) {
        return 'just now';
    }

    // get an array in the form of [number, string]
    let a = elapsed < hour  && [Math.floor(elapsed / minute), 'minute'] ||
            elapsed < day   && [Math.floor(elapsed / hour), 'hour']     ||
            elapsed < month && [Math.floor(elapsed / day), 'day']       ||
            elapsed < year  && [Math.floor(elapsed / month), 'month']   ||
            [Math.floor(elapsed / year), 'year'];

    // pluralise and append suffix
    return a[0] + ' ' + a[1] + (a[0] === 1 ? '' : 's') + suffix;
}

在这种情况下可能有点过头了,但如果有机会,moment.js真的很棒!

js是一个javascript datetime库,在这种情况下使用它,你需要做:

moment(yourdate).fromNow()

http://momentjs.com/docs/#/displaying/fromnow/

2018附录:Luxon是一个新的现代图书馆,可能值得一看!

2022年附录:Day.js是一个较新的库,比Luxon轻80%左右,具有类似的功能。

function timeSince(date) { var seconds = Math.floor((new Date() - date) / 1000); var interval = seconds / 31536000; if (interval > 1) { return Math.floor(interval) + " years"; } interval = seconds / 2592000; if (interval > 1) { return Math.floor(interval) + " months"; } interval = seconds / 86400; if (interval > 1) { return Math.floor(interval) + " days"; } interval = seconds / 3600; if (interval > 1) { return Math.floor(interval) + " hours"; } interval = seconds / 60; if (interval > 1) { return Math.floor(interval) + " minutes"; } return Math.floor(seconds) + " seconds"; } var aDay = 24*60*60*1000; console.log(timeSince(new Date(Date.now()-aDay))); console.log(timeSince(new Date(Date.now()-aDay*2)));

这是一个简化版的@sky-sanders的回答。

function timeSince(date) {

  var seconds = Math.floor((new Date() - date) / 1000);
  var divisors = [31536000, 2592000, 86400, 3600, 60, 1]
  var description = ["years", "months", "days", "hours", "minutes", "seconds"]
  var result = [];

  var interval = seconds;

  for (i = 0; i < divisors.length; i++) {
    interval = Math.floor(seconds / divisors[i])
    if (interval > 1) {
      result.push(interval + " " + description[i])
    }
    seconds -= interval * divisors[i]
  }

  return result.join(" ")
}
const createdAt = moment(created_at).fromNow()

量身定制的解决方案


        const duration = moment.duration(moment().diff(moment(created_at)))
        const createdAt = duration.as('week') >= 1
          ? `${Math.floor(duration.as('week'))} week(s)`
          : duration.as('day') >= 1
            ? `${Math.floor(duration.as('day'))} day(s)`
            : duration.as('hour') >= 1
              ? `${Math.floor(duration.as('hour'))} hour(s)`
              : `${Math.floor(duration.as('minute'))} minute(s)`