问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。
e.g.
1分钟前 1小时前 1天前 1个月前 一年前
当前回答
由@user1012181提供的ES6版本代码:
const epochs = [
['year', 31536000],
['month', 2592000],
['day', 86400],
['hour', 3600],
['minute', 60],
['second', 1]
];
const getDuration = (timeAgoInSeconds) => {
for (let [name, seconds] of epochs) {
const interval = Math.floor(timeAgoInSeconds / seconds);
if (interval >= 1) {
return {
interval: interval,
epoch: name
};
}
}
};
const timeAgo = (date) => {
const timeAgoInSeconds = Math.floor((new Date() - new Date(date)) / 1000);
const {interval, epoch} = getDuration(timeAgoInSeconds);
const suffix = interval === 1 ? '' : 's';
return `${interval} ${epoch}${suffix} ago`;
};
由@ibe-vanmeenen编辑建议。(谢谢!)
其他回答
下面是我所做的(对象返回时间单位及其值):
function timeSince(post_date, reference) { var reference = reference ? new Date(reference) : new Date(), diff = reference - new Date(post_date + ' GMT-0000'), date = new Date(diff), object = { unit: null, value: null }; if (diff < 86400000) { var secs = date.getSeconds(), mins = date.getMinutes(), hours = date.getHours(), array = [ ['second', secs], ['minute', mins], ['hour', hours] ]; } else { var days = date.getDate(), weeks = Math.floor(days / 7), months = date.getMonth(), years = date.getFullYear() - 1970, array = [ ['day', days], ['week', weeks], ['month', months], ['year', years] ]; } for (var i = 0; i < array.length; i++) { array[i][0] += array[i][1] != 1 ? 's' : ''; object.unit = array[i][1] >= 1 ? array[i][0] : object.unit; object.value = array[i][1] >= 1 ? array[i][1] : object.value; } return object; }
I achieve this by following method
timeAgo = (date) => {
var ms = (new Date()).getTime() - date.getTime();
var seconds = Math.floor(ms / 1000);
var minutes = Math.floor(seconds / 60);
var hours = Math.floor(minutes / 60);
var days = Math.floor(hours / 24);
var months = Math.floor(days / 30);
var years = Math.floor(months / 12);
if (ms === 0) {
return 'Just now';
} if (seconds < 60) {
return seconds + ' seconds Ago';
} if (minutes < 60) {
return minutes + ' minutes Ago';
} if (hours < 24) {
return hours + ' hours Ago';
} if (days < 30) {
return days + ' days Ago';
} if (months < 12) {
return months + ' months Ago';
} else {
return years + ' years Ago';
}
}
console.log(timeAgo(new Date()));
console.log(timeAgo(new Date('Jun 27 2020 10:12:19')));
console.log(timeAgo(new Date('Jun 27 2020 00:12:19')));
console.log(timeAgo(new Date('May 28 2020 13:12:19')));
console.log(timeAgo(new Date('May 28 2017 13:12:19')));
要使用这个,只需复制所有这些代码,并将其导入到你的组件或任何地方,并将你的ISOstring()日期放在:showTimeAgo("2022-06-20T13:42:29-05:00"),你将获得每个场景的自动时间更新。
旁注:我为这个https://www.npmjs.com/package/showtimeago做了一个npm包
export const showTimeAgo = () => {
const MONTH_NAMES = [
'January',
'February',
'March',
'April',
'May',
'June',
'July',
'August',
'September',
'October',
'November',
'December',
];
function getOrdinalNum() {
return (
n +
(n > 0
? ['th', 'st', 'nd', 'rd'][
(n > 3 && n < 21) || n % 10 > 3 ? 0 : n % 10
]
: '')
);
}
function getFormattedDate(
date,
preformattedDate = false,
hideYear = false
) {
const day = date.getDate();
const month = MONTH_NAMES[date.getMonth()];
const year = date.getFullYear();
let hours = date.getHours();
let minutes = date.getMinutes();
let ampm = hours >= 12 ? 'pm' : 'am';
switch(true){
case (hours > 12):
hours = hours - 12;
break;
case (hours === 0):
hours = 12;
break;
case(minutes < 10):
minutes = `0${minutes}`;
break;
case(preformattedDate):
// Today at 10:20am
// Yesterday at 10:20am
return `${preformattedDate} at ${hours}:${minutes} ${ampm}`;
case(hideYear):
// January 10th at 10:20pm
return `${month} ${getOrdinalNum(
day
)}, at ${hours}:${minutes} ${ampm}`;
default:
// January 10th 2022 at 10:20pm
return `${month} ${getOrdinalNum(
day
)}, ${year} at ${hours}:${minutes} ${ampm}`;
}
}
// --- Main function
function timeAgo(dateParam) {
if (!dateParam) {
return null;
}
const date =
typeof dateParam === 'object' ? dateParam : new Date(dateParam);
const DAY_IN_MS = 86400000; // 24 * 60 * 60 * 1000
const today = new Date();
const yesterday = new Date(today - DAY_IN_MS);
const seconds = Math.round((today - date) / 1000);
const minutes = Math.round(seconds / 60);
const hour = Math.round(seconds / 3600);
const day = Math.round(seconds / 86400);
const month = Math.round(seconds / 2629800);
const year = Math.floor(seconds / 31536000);
const isToday = today.toDateString() === date.toDateString();
const isYesterday =
yesterday.toDateString() === date.toDateString();
const isThisYear = today.getFullYear() === date.getFullYear();
switch(true){
case (seconds < 5):
return 'now';
case (seconds < 60):
return `${seconds} seconds ago`;
case (seconds < 90):
return 'about a minute ago';
case (minutes < 60):
return `${minutes} minutes ago`;
case (hour === 1 && hour < 2):
return `${hour} hour ago`; // 1 hour ago
case (hour > 1 && hour <= 12):
return `${hour} hours ago`; // 2 hours ago
case (isToday):
return getFormattedDate(date, 'Today'); // Today at 10:20am
case (isYesterday):
return getFormattedDate(date, 'Yesterday'); // Yesterday at 10:20am
case(day > 1 && day <= 30):
return `${day} days ago`; // 2 days ago
case (isThisYear):
return getFormattedDate(date, false, true); // January 10th at 10:20pm
case (day > 30 && month <= 1):
return `${hour} month ago`; // 1 month ago
case (month > 1 && month <= 12):
return `${month} months ago`; // 2 months ago
case (year === 1):
return `${year} year ago`; // 1 year ago
case (year > 1):
return `${year} years ago`; // 2 years ago
default:
return getFormattedDate(date); // January 10th 2022 at 10:20pm
}
}
return timeAgo(date);
};
console.log(showTimeAgo("2022-06-20T13:42:29-05:00"));-05:00"))
以下是对Sky Sander的解决方案的轻微修改,允许日期作为字符串输入,并能够显示像“1分钟”而不是“73秒”这样的跨度
var timeSince = function(date) { if (typeof date !== 'object') { date = new Date(date); } var seconds = Math.floor((new Date() - date) / 1000); var intervalType; var interval = Math.floor(seconds / 31536000); if (interval >= 1) { intervalType = 'year'; } else { interval = Math.floor(seconds / 2592000); if (interval >= 1) { intervalType = 'month'; } else { interval = Math.floor(seconds / 86400); if (interval >= 1) { intervalType = 'day'; } else { interval = Math.floor(seconds / 3600); if (interval >= 1) { intervalType = "hour"; } else { interval = Math.floor(seconds / 60); if (interval >= 1) { intervalType = "minute"; } else { interval = seconds; intervalType = "second"; } } } } } if (interval > 1 || interval === 0) { intervalType += 's'; } return interval + ' ' + intervalType; }; var aDay = 24 * 60 * 60 * 1000; console.log(timeSince(new Date(Date.now() - aDay))); console.log(timeSince(new Date(Date.now() - aDay * 2)));
回复@Stas Parshin的答案,这是最好的答案,代码更少,但它在与typescript一起使用时有bug, Intl的.format函数需要2个输入
number, Units - i.e of type 'RelativeTimeFormatUnit' so if you pass a object key typescript will through error saying unit must be of type RelativeTimeFormatUnit and not of type string, so the work-around for this is to use the type to make another list of same type and rest you can have look at code... Happy coding. console.log(timeAgo('2021-08-09T15:29:01+0000')); function timeAgo(input) { const date = (input instanceof Date) ? input : new Date(input); const formatter = new Intl.RelativeTimeFormat('en'); const ranges = { years: 3600 * 24 * 365, months: 3600 * 24 * 30, weeks: 3600 * 24 * 7, days: 3600 * 24, hours: 3600, minutes: 60, seconds: 1 }; type RelativeTimeFormatUnit = | "year" | "years" | "quarter" | "quarters" | "month" | "months" | "week" | "weeks" | "day" | "days" | "hour" | "hours" | "minute" | "minutes" | "second" | "seconds" ; const units: RelativeTimeFormatUnit[] = ["years", "months", "weeks", "days", "hours", "minutes", "seconds"]; // order matters here. const secondsElapsed = (date.getTime() - Date.now()) / 1000; for (let key in ranges) { let i = 0; if (ranges[key] < Math.abs(secondsElapsed)) { const delta = secondsElapsed / ranges[key]; return formatter.format(Math.round(delta), units[i++]); } } }