问题是如何将JavaScript Date格式化为一个字符串,声明时间经过,类似于您在Stack Overflow上看到的时间显示方式。

e.g.

1分钟前 1小时前 1天前 1个月前 一年前


当前回答

这是对国际的另一种看法。RelativeTimeFormat

支持过去日期和将来日期 同时接受字符串和日期 易于添加自定义范围(编辑范围) 可以很容易地翻译为Intl.RelativeTimeFormat('ua')

console.log(timeAgo('2021-08-09T15:29:01+0000')); function timeAgo(input) { const date = (input instanceof Date) ? input : new Date(input); const formatter = new Intl.RelativeTimeFormat('en'); const ranges = { years: 3600 * 24 * 365, months: 3600 * 24 * 30, weeks: 3600 * 24 * 7, days: 3600 * 24, hours: 3600, minutes: 60, seconds: 1 }; const secondsElapsed = (date.getTime() - Date.now()) / 1000; for (let key in ranges) { if (ranges[key] < Math.abs(secondsElapsed)) { const delta = secondsElapsed / ranges[key]; return formatter.format(Math.round(delta), key); } } }

https://jsfiddle.net/tv9701uf

其他回答

function calDateAgo(dString=null){
    //var dString = "2021-04-1 12:00:00";
     
    var d1 = new Date(dString);
    var d2 = new Date();
    var t2 = d2.getTime();
    var t1 = d1.getTime();
    var d1Y = d1.getFullYear();
    var d2Y = d2.getFullYear();
    var d1M = d1.getMonth();
    var d2M = d2.getMonth();
     
    var time_obj = {};
    time_obj.year = d2.getFullYear()-d1.getFullYear();
    time_obj.month = (d2M+12*d2Y)-(d1M+12*d1Y);
    time_obj.week = parseInt((t2-t1)/(24*3600*1000*7));
    time_obj.day = parseInt((t2-t1)/(24*3600*1000));
    time_obj.hour = parseInt((t2-t1)/(3600*1000));
    time_obj.minute = parseInt((t2-t1)/(60*1000));
    time_obj.second = parseInt((t2-t1)/(1000));

    for (const obj_key in time_obj) {
        if(time_obj[obj_key] == 0){
            delete time_obj[obj_key];
        }
    }
    var ago_text = 'just now';

    if(typeof Object.keys(time_obj)[0] != 'undefined'){
        var time_key = Object.keys(time_obj)[0];
        var time_val = time_obj[Object.keys(time_obj)[0]];
        time_key += (time_val > 1) ? 's':'';
        ago_text = time_val+' '+time_key+' ago'; 
    }
    
    return ago_text;
}

下面是我所做的(对象返回时间单位及其值):

function timeSince(post_date, reference) { var reference = reference ? new Date(reference) : new Date(), diff = reference - new Date(post_date + ' GMT-0000'), date = new Date(diff), object = { unit: null, value: null }; if (diff < 86400000) { var secs = date.getSeconds(), mins = date.getMinutes(), hours = date.getHours(), array = [ ['second', secs], ['minute', mins], ['hour', hours] ]; } else { var days = date.getDate(), weeks = Math.floor(days / 7), months = date.getMonth(), years = date.getFullYear() - 1970, array = [ ['day', days], ['week', weeks], ['month', months], ['year', years] ]; } for (var i = 0; i < array.length; i++) { array[i][0] += array[i][1] != 1 ? 's' : ''; object.unit = array[i][1] >= 1 ? array[i][0] : object.unit; object.value = array[i][1] >= 1 ? array[i][1] : object.value; } return object; }

如果你已经在使用date-fns,你可以使用内置的formatDistance(以前是distanceInWords):

const date1 = new Date(2014, 6, 2);
const date2 = new Date(2015, 0, 1);
const options = { addSuffix: true }
const result = formatDistance(date1, date2, options);
//=> '6 months ago'

回复@Stas Parshin的答案,这是最好的答案,代码更少,但它在与typescript一起使用时有bug, Intl的.format函数需要2个输入

number, Units - i.e of type 'RelativeTimeFormatUnit' so if you pass a object key typescript will through error saying unit must be of type RelativeTimeFormatUnit and not of type string, so the work-around for this is to use the type to make another list of same type and rest you can have look at code... Happy coding. console.log(timeAgo('2021-08-09T15:29:01+0000')); function timeAgo(input) { const date = (input instanceof Date) ? input : new Date(input); const formatter = new Intl.RelativeTimeFormat('en'); const ranges = { years: 3600 * 24 * 365, months: 3600 * 24 * 30, weeks: 3600 * 24 * 7, days: 3600 * 24, hours: 3600, minutes: 60, seconds: 1 }; type RelativeTimeFormatUnit = | "year" | "years" | "quarter" | "quarters" | "month" | "months" | "week" | "weeks" | "day" | "days" | "hour" | "hours" | "minute" | "minutes" | "second" | "seconds" ; const units: RelativeTimeFormatUnit[] = ["years", "months", "weeks", "days", "hours", "minutes", "seconds"]; // order matters here. const secondsElapsed = (date.getTime() - Date.now()) / 1000; for (let key in ranges) { let i = 0; if (ranges[key] < Math.abs(secondsElapsed)) { const delta = secondsElapsed / ranges[key]; return formatter.format(Math.round(delta), units[i++]); } } }

我使用这个包:javascript-time-ago

设置TimeAgo 导入TimeAgo 从javascript-time-ago/locale/en.json导入en TimeAgo.addDefaultLocale (en) 写一个函数 // twitter-now是twitter风格。查看文档以获得更多选项 const clockToDateString = (timestamp) => timeAgo。format(new Date(timestamp.toNumber() * 1000), 'twitter-now') 在dom中使用它 < div > {clockToDateString (post.postTime)} < / div >