你不能在一个PHP类中放入两个具有唯一参数签名的__construct函数。我想这样做:
class Student
{
protected $id;
protected $name;
// etc.
public function __construct($id){
$this->id = $id;
// other members are still uninitialized
}
public function __construct($row_from_database){
$this->id = $row_from_database->id;
$this->name = $row_from_database->name;
// etc.
}
}
PHP中最好的方法是什么?
在创建具有不同签名的多个构造函数时,我也面临着同样的问题,但不幸的是,PHP没有提供直接的方法来这样做。然而,我发现了一个技巧来克服它。希望也适用于你们所有人。
<?PHP
class Animal
{
public function __construct()
{
$arguments = func_get_args();
$numberOfArguments = func_num_args();
if (method_exists($this, $function = '__construct'.$numberOfArguments)) {
call_user_func_array(array($this, $function), $arguments);
}
}
public function __construct1($a1)
{
echo('__construct with 1 param called: '.$a1.PHP_EOL);
}
public function __construct2($a1, $a2)
{
echo('__construct with 2 params called: '.$a1.','.$a2.PHP_EOL);
}
public function __construct3($a1, $a2, $a3)
{
echo('__construct with 3 params called: '.$a1.','.$a2.','.$a3.PHP_EOL);
}
}
$o = new Animal('sheep');
$o = new Animal('sheep','cat');
$o = new Animal('sheep','cat','dog');
// __construct with 1 param called: sheep
// __construct with 2 params called: sheep,cat
// __construct with 3 params called: sheep,cat,dog
让我在这里加一粒沙子
我个人喜欢将构造函数作为返回类(对象)实例的静态函数添加。代码示例如下:
class Person
{
private $name;
private $email;
public static function withName($name)
{
$person = new Person();
$person->name = $name;
return $person;
}
public static function withEmail($email)
{
$person = new Person();
$person->email = $email;
return $person;
}
}
注意,现在你可以像这样创建Person类的实例:
$person1 = Person::withName('Example');
$person2 = Person::withEmail('yo@mi_email.com');
我的代码来自:
http://alfonsojimenez.com/post/30377422731/multiple-constructors-in-php
我知道我在这方面非常晚,但我提出了一个相当灵活的模式,应该允许一些真正有趣和通用的实现。
像往常一样设置类,使用您喜欢的任何变量。
class MyClass{
protected $myVar1;
protected $myVar2;
public function __construct($obj = null){
if($obj){
foreach (((object)$obj) as $key => $value) {
if(isset($value) && in_array($key, array_keys(get_object_vars($this)))){
$this->$key = $value;
}
}
}
}
}
When you make your object just pass an associative array with the keys of the array the same as the names of your vars, like so...
$sample_variable = new MyClass([
'myVar2'=>123,
'i_dont_want_this_one'=> 'This won\'t make it into the class'
]);
print_r($sample_variable);
The print_r($sample_variable); after this instantiation yields the following:
MyClass Object ( [myVar1:protected] => [myVar2:protected] => 123 )
Because we've initialize $group to null in our __construct(...), it is also valid to pass nothing whatsoever into the constructor as well, like so...
$sample_variable = new MyClass();
print_r($sample_variable);
Now the output is exactly as expected:
MyClass Object ( [myVar1:protected] => [myVar2:protected] => )
The reason I wrote this was so that I could directly pass the output of json_decode(...) to my constructor, and not worry about it too much.
This was executed in PHP 7.1. Enjoy!
正如这里已经展示的,在PHP中有许多方法来声明多个构造函数,但是没有一种方法是正确的(因为PHP技术上不允许这样做)。
但这并不能阻止我们破解这个功能……
下面是另一个例子:
<?php
class myClass {
public function __construct() {
$get_arguments = func_get_args();
$number_of_arguments = func_num_args();
if (method_exists($this, $method_name = '__construct'.$number_of_arguments)) {
call_user_func_array(array($this, $method_name), $get_arguments);
}
}
public function __construct1($argument1) {
echo 'constructor with 1 parameter ' . $argument1 . "\n";
}
public function __construct2($argument1, $argument2) {
echo 'constructor with 2 parameter ' . $argument1 . ' ' . $argument2 . "\n";
}
public function __construct3($argument1, $argument2, $argument3) {
echo 'constructor with 3 parameter ' . $argument1 . ' ' . $argument2 . ' ' . $argument3 . "\n";
}
}
$object1 = new myClass('BUET');
$object2 = new myClass('BUET', 'is');
$object3 = new myClass('BUET', 'is', 'Best.');
使用和理解多个构造函数的最简单方法:
希望这能有所帮助。:)
另一种选择是像这样在构造函数中使用默认参数
class Student {
private $id;
private $name;
//...
public function __construct($id, $row=array()) {
$this->id = $id;
foreach($row as $key => $value) $this->$key = $value;
}
}
这意味着你需要实例化一行像这样:$student = new student ($row['id'], $row),但保持你的构造函数漂亮和干净。
另一方面,如果你想利用多态性,那么你可以创建两个类,像这样:
class Student {
public function __construct($row) {
foreach($row as $key => $value) $this->$key = $value;
}
}
class EmptyStudent extends Student {
public function __construct($id) {
parent::__construct(array('id' => $id));
}
}