OP同时要求版本号和版本号。不幸的是，大多数答案都不提供这两个选项。另外，还有一些添加了不必要的扩展方法。这里有一个非常简单的方法，可以解决OP的问题:

// Example output: "1.0 (234)"
private func versionAndBuildNumber() -> String {
  let versionNumber = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String
  let buildNumber = Bundle.main.infoDictionary?["CFBundleVersion"] as? String
  if let versionNumber = versionNumber, let buildNumber = buildNumber {
    return "\(versionNumber) (\(buildNumber))"
  } else if let versionNumber = versionNumber {
    return versionNumber
  } else if let buildNumber = buildNumber {
    return buildNumber
  } else {
    return ""
  }
}

斯威夫特3:

版本号

if let versionNumberString = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String { // do something }

建立数

if let buildNumberString = Bundle.main.infoDictionary?["CFBundleVersion"] as? String { // do something }

EDIT

Swift 4.2更新

let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String

EDIT

正如@azdev在Xcode的新版本上指出的那样，你会得到一个编译错误，尝试我以前的解决方案，要解决这个问题，只需编辑它，建议使用一个打开包字典!

let nsObject: AnyObject? = Bundle.main.infoDictionary!["CFBundleShortVersionString"]

最后编辑

使用与Objective-C中相同的逻辑，但有一些小的变化

//First get the nsObject by defining as an optional anyObject
let nsObject: AnyObject? = NSBundle.mainBundle().infoDictionary["CFBundleShortVersionString"]

//Then just cast the object as a String, but be careful, you may want to double check for nil
let version = nsObject as! String

if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
        lblVersion.text = "Version \(version)"

    }

Xcode 8, Swift 3:

let gAppVersion = Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") ?? "0"
let gAppBuild = Bundle.main.object(forInfoDictionaryKey: "CFBundleVersion") ?? "0"

对于Swift 5.0:

let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as! String