OP同时要求版本号和版本号。不幸的是，大多数答案都不提供这两个选项。另外，还有一些添加了不必要的扩展方法。这里有一个非常简单的方法，可以解决OP的问题:

// Example output: "1.0 (234)"
private func versionAndBuildNumber() -> String {
  let versionNumber = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String
  let buildNumber = Bundle.main.infoDictionary?["CFBundleVersion"] as? String
  if let versionNumber = versionNumber, let buildNumber = buildNumber {
    return "\(versionNumber) (\(buildNumber))"
  } else if let versionNumber = versionNumber {
    return versionNumber
  } else if let buildNumber = buildNumber {
    return buildNumber
  } else {
    return ""
  }
}

针对Swift 3.0更新

在Swift 3.0中，ns前缀已经没有了，一些属性/方法的名称已经更改为更Swifty。这是现在的样子:

extension Bundle {
    var releaseVersionNumber: String? {
        return infoDictionary?["CFBundleShortVersionString"] as? String
    }
    var buildVersionNumber: String? {
        return infoDictionary?["CFBundleVersion"] as? String
    }
}

Bundle.main.releaseVersionNumber
Bundle.main.buildVersionNumber

更新答案

I've been working with Frameworks a lot since my original answer, so I wanted to update my solution to something that is both simpler and much more useful in a multi-bundle environment: extension NSBundle { var releaseVersionNumber: String? { return self.infoDictionary?["CFBundleShortVersionString"] as? String } var buildVersionNumber: String? { return self.infoDictionary?["CFBundleVersion"] as? String } } Now this extension will be useful in apps to identify both the main bundle and any other included bundles (such as a shared framework for extension programming or third frameworks like AFNetworking), like so: NSBundle.mainBundle().releaseVersionNumber NSBundle.mainBundle().buildVersionNumber // or... NSBundle(URL: someURL)?.releaseVersionNumber NSBundle(URL: someURL)?.buildVersionNumber

原来的答案

I wanted to improve on some of the answers already posted. I wrote a class extension that can be added to your tool chain to handle this in a more logical fashion. extension NSBundle { class var applicationVersionNumber: String { if let version = NSBundle.mainBundle().infoDictionary?["CFBundleShortVersionString"] as? String { return version } return "Version Number Not Available" } class var applicationBuildNumber: String { if let build = NSBundle.mainBundle().infoDictionary?["CFBundleVersion"] as? String { return build } return "Build Number Not Available" } } So now you can access this easily by: let versionNumber = NSBundle.applicationVersionNumber

简单的实用函数返回应用程序版本为Int

func getAppVersion() -> Int {

        if let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {

            let appVersionClean = appVersion.replacingOccurrences(of: ".", with: "", options: NSString.CompareOptions.literal, range:nil)

            if let appVersionNum = Int(appVersionClean) {
                return appVersionNum
            }
        }
        return 0
    }

OP同时要求版本号和版本号。不幸的是，大多数答案都不提供这两个选项。另外，还有一些添加了不必要的扩展方法。这里有一个非常简单的方法，可以解决OP的问题:

// Example output: "1.0 (234)"
private func versionAndBuildNumber() -> String {
  let versionNumber = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String
  let buildNumber = Bundle.main.infoDictionary?["CFBundleVersion"] as? String
  if let versionNumber = versionNumber, let buildNumber = buildNumber {
    return "\(versionNumber) (\(buildNumber))"
  } else if let versionNumber = versionNumber {
    return versionNumber
  } else if let buildNumber = buildNumber {
    return buildNumber
  } else {
    return ""
  }
}

斯威夫特5.3

let infoDictionaryKey = kCFBundleVersionKey as String
guard let currentVersion = Bundle.main.object(forInfoDictionaryKey: infoDictionaryKey) as? String
else { fatalError("Expected to find a bundle version in the info dictionary") }

斯威夫特4

func getAppVersion() -> String {
    return "\(Bundle.main.infoDictionary!["CFBundleShortVersionString"] ?? "")"
}

Bundle.main.infoDictionary！[“CFBundleShortVersionString”]

快速旧语法

let appVer: AnyObject? = NSBundle.mainBundle().infoDictionary!["CFBundleShortVersionString"]