Xcode 8, Swift 3:

let gAppVersion = Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") ?? "0"
let gAppBuild = Bundle.main.object(forInfoDictionaryKey: "CFBundleVersion") ?? "0"

我在捆绑上做了一个扩展

extension Bundle {

    var appName: String {
        return infoDictionary?["CFBundleName"] as! String
    }

    var bundleId: String {
        return bundleIdentifier!
    }

    var versionNumber: String {
        return infoDictionary?["CFBundleShortVersionString"] as! String 
    }

    var buildNumber: String {
        return infoDictionary?["CFBundleVersion"] as! String
    }

}

然后使用它

versionLabel.text = "\(Bundle.main.appName) v \(Bundle.main.versionNumber) (Build \(Bundle.main.buildNumber))"

鉴于Swift一直在发展，我的回答(截至2015年8月):

let version = NSBundle.mainBundle().infoDictionary!["CFBundleVersion"] as! String

看过文档后，我认为以下内容更清晰:

let version = 
NSBundle.mainBundle().objectForInfoDictionaryKey("CFBundleShortVersionString") 
as? String

来源: 使用此方法优于其他访问方法，因为它在键可用时返回键的本地化值。

EDIT

Swift 4.2更新

let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String

EDIT

正如@azdev在Xcode的新版本上指出的那样，你会得到一个编译错误，尝试我以前的解决方案，要解决这个问题，只需编辑它，建议使用一个打开包字典!

let nsObject: AnyObject? = Bundle.main.infoDictionary!["CFBundleShortVersionString"]

最后编辑

使用与Objective-C中相同的逻辑，但有一些小的变化

//First get the nsObject by defining as an optional anyObject
let nsObject: AnyObject? = NSBundle.mainBundle().infoDictionary["CFBundleShortVersionString"]

//Then just cast the object as a String, but be careful, you may want to double check for nil
let version = nsObject as! String

简单的实用函数返回应用程序版本为Int

func getAppVersion() -> Int {

        if let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {

            let appVersionClean = appVersion.replacingOccurrences(of: ".", with: "", options: NSString.CompareOptions.literal, range:nil)

            if let appVersionNum = Int(appVersionClean) {
                return appVersionNum
            }
        }
        return 0
    }