if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
        lblVersion.text = "Version \(version)"

    }

斯威夫特4

func getAppVersion() -> String {
    return "\(Bundle.main.infoDictionary!["CFBundleShortVersionString"] ?? "")"
}

Bundle.main.infoDictionary！[“CFBundleShortVersionString”]

快速旧语法

let appVer: AnyObject? = NSBundle.mainBundle().infoDictionary!["CFBundleShortVersionString"]

if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
        lblVersion.text = "Version \(version)"

    }

针对Swift 2.0

//First get the nsObject by defining as an optional anyObject

let nsObject: AnyObject? = NSBundle.mainBundle().infoDictionary!["CFBundleShortVersionString"]
let version = nsObject as! String

针对Swift 4.0

let version = Bundle.main.infoDictionary!["CFBundleShortVersionString"]!
let build = Bundle.main.infoDictionary!["CFBundleVersion"]!

我知道这个问题已经有人回答了，但我个人认为这个问题更清晰一些:

斯威夫特3.0:

 if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
    self.labelVersion.text = version
}

斯威夫特< 2.3

if let version = NSBundle.mainBundle().infoDictionary?["CFBundleShortVersionString"] as? String {
    self.labelVersion.text = version
}

这样，if let版本就负责条件处理(在我的例子中设置标签文本)，如果infoDictionary或CFBundleShortVersionString为nil，则可选的展开将导致代码被跳过。