我有一个带有Azure后端的IOS应用程序,想要记录某些事件,如登录和应用程序用户正在运行的版本。
如何使用Swift返回版本和构建号?
我有一个带有Azure后端的IOS应用程序,想要记录某些事件,如登录和应用程序用户正在运行的版本。
如何使用Swift返回版本和构建号?
当前回答
以下是Swift 3.2的更新版本:
extension UIApplication
{
static var appVersion:String
{
if let appVersion = Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString")
{
return "\(appVersion)"
}
return ""
}
static var buildNumber:String
{
if let buildNum = Bundle.main.object(forInfoDictionaryKey: kCFBundleVersionKey as String)
{
return "\(buildNum)"
}
return ""
}
static var versionString:String
{
return "\(appVersion).\(buildNumber)"
}
}
其他回答
对于任何感兴趣的人,在github上有一个漂亮而整洁的库叫做SwifterSwift,它也有完整的swift版本文档(参见swifterswift.com)。
使用这个库,读取应用版本和构建号就像这样简单:
import SwifterSwift
let buildNumber = SwifterSwift.appBuild
let version = SwifterSwift.appVersion
Swift 5作为UIApplication扩展
extension UIApplication {
static var release: String {
return Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") as! String? ?? "x.x"
}
static var build: String {
return Bundle.main.object(forInfoDictionaryKey: "CFBundleVersion") as! String? ?? "x"
}
static var version: String {
return "\(release).\(build)"
}
}
使用示例:
print("release: \(UIApplication.release)")
print("build: \(UIApplication.build)")
print("version: \(UIApplication.version)")
以下是Swift 3.2的更新版本:
extension UIApplication
{
static var appVersion:String
{
if let appVersion = Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString")
{
return "\(appVersion)"
}
return ""
}
static var buildNumber:String
{
if let buildNum = Bundle.main.object(forInfoDictionaryKey: kCFBundleVersionKey as String)
{
return "\(buildNum)"
}
return ""
}
static var versionString:String
{
return "\(appVersion).\(buildNumber)"
}
}
Xcode 9.4.1 Swift 4.1
注意,使用localizedInfoDictionary来获取包显示名称的正确语言版本。
var displayName: String?
var version: String?
var build: String?
override func viewDidLoad() {
super.viewDidLoad()
// Get display name, version and build
if let displayName = Bundle.main.localizedInfoDictionary?["CFBundleDisplayName"] as? String {
self.displayName = displayName
}
if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
self.version = version
}
if let build = Bundle.main.infoDictionary?["CFBundleVersion"] as? String {
self.build = build
}
}
EDIT
Swift 4.2更新
let appVersion = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String
EDIT
正如@azdev在Xcode的新版本上指出的那样,你会得到一个编译错误,尝试我以前的解决方案,要解决这个问题,只需编辑它,建议使用一个打开包字典!
let nsObject: AnyObject? = Bundle.main.infoDictionary!["CFBundleShortVersionString"]
最后编辑
使用与Objective-C中相同的逻辑,但有一些小的变化
//First get the nsObject by defining as an optional anyObject
let nsObject: AnyObject? = NSBundle.mainBundle().infoDictionary["CFBundleShortVersionString"]
//Then just cast the object as a String, but be careful, you may want to double check for nil
let version = nsObject as! String