我有一个应用程序,我正在寻找一个文本文件,如果对文件做了任何更改,我使用OnChanged事件处理程序来处理事件。我正在使用NotifyFilters。LastWriteTime,但是事件仍然被触发两次。这是代码。

public void Initialize()
{
   FileSystemWatcher _fileWatcher = new FileSystemWatcher();
  _fileWatcher.Path = "C:\\Folder";
  _fileWatcher.NotifyFilter = NotifyFilters.LastWrite;
  _fileWatcher.Filter = "Version.txt";
  _fileWatcher.Changed += new FileSystemEventHandler(OnChanged);
  _fileWatcher.EnableRaisingEvents = true;
}

private void OnChanged(object source, FileSystemEventArgs e)
{
   .......
}

在我的情况下,OnChanged被调用两次,当我改变文本文件version.txt并保存它。


当前回答

如果你注册了OnChanged事件,那么在修改之前删除被监视的文件可能会起作用,只要你只需要监视OnChange事件。

其他回答

以下是我的解决方案,帮助我阻止事件被提出两次:

watcher.NotifyFilter = NotifyFilters.FileName | NotifyFilters.Size;

这里我只设置了文件名和大小的NotifyFilter属性。 watcher是FileSystemWatcher的对象。希望这能有所帮助。

一直在寻找答案,但我想到了一个肮脏的解决方案。因为我的事件触发了两次,所以第二个动作什么也不做。

       $count = 1
       $action = { 
            if($count -eq 1){                  
                #DO SOMETHING
                $count = 2 
            }else{
                $count = 1
            }
        }  

代码可自定义禁用阻止第二个观察者升起的时间间隔,如果他们存在,则不阻止观察者:

    namespace Watcher
    {
        class Static
        {
            public static DateTime lastDomain { get; set; }
            public static string lastDomainStr { get; set; }
        }
        public partial class Form1 : Form
       {
            int minMs = 20;//time for blocking in ms
            public Form1()
            {
                InitializeComponent();
                Static.lastDomain = new DateTime(1970, 1, 1, 0, 0, 0);
                Static.lastDomainStr = "";  
                Start();
            }
             private void Start()//Start watcher
             {
                //...
                domain.Changed += new FileSystemEventHandler(Domain);
                domain.EnableRaisingEvents = true;
                //...you second unblocked watchers
                second.Changed += new FileSystemEventHandler(Second);
                second.EnableRaisingEvents = true;
             }
             private void Domain(object source, FileSystemEventArgs e)
             {
                if (now.Subtract(Static.lastDomain).TotalMilliseconds < minMs && Static.lastDomainStr == e.FullPath)return;
                 //...you code here
                 /* if you need form access
                 this.Invoke(new MethodInvoker(() =>{ textBox1.Text = "...";}));
                 */
                 Static.lastDomain = DateTime.Now;
                 Static.lastDomainStr = e.FullPath;
             }
             private void Second(object source, FileSystemEventArgs e)
             {
                  //...Second rised
             }
       }
    }

恐怕这是FileSystemWatcher类的一个众所周知的错误/特性。这是来自类的文档:

You may notice in certain situations that a single creation event generates multiple Created events that are handled by your component. For example, if you use a FileSystemWatcher component to monitor the creation of new files in a directory, and then test it by using Notepad to create a file, you may see two Created events generated even though only a single file was created. This is because Notepad performs multiple file system actions during the writing process. Notepad writes to the disk in batches that create the content of the file and then the file attributes. Other applications may perform in the same manner. Because FileSystemWatcher monitors the operating system activities, all events that these applications fire will be picked up.

现在这段文本是关于Created事件的,但同样的事情也适用于其他文件事件。在一些应用程序中,您可能能够通过使用NotifyFilter属性来解决这个问题,但我的经验是,有时您还必须进行一些手动重复过滤(hacks)。

前段时间我书签了一个页面,里面有一些FileSystemWatcher技巧。你可能会想去看看。

我只想对最后一个事件做出反应,以防万一,也对linux文件更改,它似乎在第一次调用时文件是空的,然后在下一个调用时再次填充,不介意浪费一些时间,以防操作系统决定做一些文件/属性更改。

我在这里使用。net async来帮助我做线程。

    private static int _fileSystemWatcherCounts;
    private async void OnChanged(object sender, FileSystemEventArgs e)
    {
        // Filter several calls in short period of time
        Interlocked.Increment(ref _fileSystemWatcherCounts);
        await Task.Delay(100);
        if (Interlocked.Decrement(ref _fileSystemWatcherCounts) == 0)
            DoYourWork();
    }