我有一个应用程序,我正在寻找一个文本文件,如果对文件做了任何更改,我使用OnChanged事件处理程序来处理事件。我正在使用NotifyFilters。LastWriteTime,但是事件仍然被触发两次。这是代码。

public void Initialize()
{
   FileSystemWatcher _fileWatcher = new FileSystemWatcher();
  _fileWatcher.Path = "C:\\Folder";
  _fileWatcher.NotifyFilter = NotifyFilters.LastWrite;
  _fileWatcher.Filter = "Version.txt";
  _fileWatcher.Changed += new FileSystemEventHandler(OnChanged);
  _fileWatcher.EnableRaisingEvents = true;
}

private void OnChanged(object source, FileSystemEventArgs e)
{
   .......
}

在我的情况下,OnChanged被调用两次,当我改变文本文件version.txt并保存它。


当前回答

我的场景是,我有一个虚拟机,其中有一个Linux服务器。我正在Windows主机上开发文件。当我在主机上的一个文件夹中更改某些内容时,我希望所有的更改都被上传,并通过Ftp同步到虚拟服务器上。这是我如何消除重复更改事件当我写入一个文件(这标志着包含文件要修改的文件夹):

private Hashtable fileWriteTime = new Hashtable();

private void fsw_sync_Changed(object source, FileSystemEventArgs e)
{
    string path = e.FullPath.ToString();
    string currentLastWriteTime = File.GetLastWriteTime( e.FullPath ).ToString();

    // if there is no path info stored yet
    // or stored path has different time of write then the one now is inspected
    if ( !fileWriteTime.ContainsKey(path) ||
         fileWriteTime[path].ToString() != currentLastWriteTime
    )
    {
        //then we do the main thing
        log( "A CHANGE has occured with " + path );

        //lastly we update the last write time in the hashtable
        fileWriteTime[path] = currentLastWriteTime;
    }
}

我主要创建一个哈希表来存储文件写时间信息。然后,如果哈希表有被修改的文件路径,并且它的时间值与当前通知的文件更改相同,那么我就知道它是事件的副本,并忽略它。

其他回答

这个代码对我有用。

        private void OnChanged(object source, FileSystemEventArgs e)
    {

        string fullFilePath = e.FullPath.ToString();
        string fullURL = buildTheUrlFromStudyXML(fullFilePath);

        System.Diagnostics.Process.Start("iexplore", fullURL);

        Timer timer = new Timer();
        ((FileSystemWatcher)source).Changed -= new FileSystemEventHandler(OnChanged);
        timer.Interval = 1000;
        timer.Elapsed += new ElapsedEventHandler(t_Elapsed);
        timer.Start();
    }

    private void t_Elapsed(object sender, ElapsedEventArgs e)
    {
        ((Timer)sender).Stop();
        theWatcher.Changed += new FileSystemEventHandler(OnChanged);
    }

我知道这是一个老问题,但我遇到了同样的问题,上面的解决方案都没有真正解决我所面临的问题。我已经创建了一个字典,它将文件名与LastWriteTime映射。因此,如果文件不在字典中,将继续执行该进程,否则将检查最后一次修改时间是什么时候,如果与字典中的时间不同,则运行代码。

    Dictionary<string, DateTime> dateTimeDictionary = new Dictionary<string, DateTime>(); 

        private void OnChanged(object source, FileSystemEventArgs e)
            {
                if (!dateTimeDictionary.ContainsKey(e.FullPath) || (dateTimeDictionary.ContainsKey(e.FullPath) && System.IO.File.GetLastWriteTime(e.FullPath) != dateTimeDictionary[e.FullPath]))
                {
                    dateTimeDictionary[e.FullPath] = System.IO.File.GetLastWriteTime(e.FullPath);

                    //your code here
                }
            }

一直在寻找答案,但我想到了一个肮脏的解决方案。因为我的事件触发了两次,所以第二个动作什么也不做。

       $count = 1
       $action = { 
            if($count -eq 1){                  
                #DO SOMETHING
                $count = 2 
            }else{
                $count = 1
            }
        }  

很抱歉挖了坟墓,但我已经与这个问题斗争了一段时间,终于想出了一种方法来处理这些多重发射事件。我想要感谢这篇文章中的每一个人,因为我在与这个问题作斗争时已经在许多参考文献中使用了它。

这是我的完整代码。它使用字典来跟踪文件最后一次写入的日期和时间。它比较该值,如果值相同,则抑制事件。然后在启动新线程后设置该值。

using System.Threading; // used for backgroundworker
using System.Diagnostics; // used for file information
private static IDictionary<string, string> fileModifiedTable = new Dictionary<string, string>(); // used to keep track of our changed events

private void fswFileWatch_Changed( object sender, FileSystemEventArgs e )
    {
        try
        {
           //check if we already have this value in our dictionary.
            if ( fileModifiedTable.TryGetValue( e.FullPath, out sEmpty ) )
            {              
                //compare timestamps      
                if ( fileModifiedTable[ e.FullPath ] != File.GetLastWriteTime( e.FullPath ).ToString() )
                {        
                    //lock the table                
                    lock ( fileModifiedTable )
                    {
                        //make sure our file is still valid
                        if ( File.Exists( e.FullPath ) )
                        {                               
                            // create a new background worker to do our task while the main thread stays awake. Also give it do work and work completed handlers
                            BackgroundWorker newThreadWork = new BackgroundWorker();
                            newThreadWork.DoWork += new DoWorkEventHandler( bgwNewThread_DoWork );
                            newThreadWork.RunWorkerCompleted += new RunWorkerCompletedEventHandler( bgwNewThread_RunWorkerCompleted );

                            // capture the path
                            string eventFilePath = e.FullPath;
                            List<object> arguments = new List<object>();

                            // add arguments to pass to the background worker
                            arguments.Add( eventFilePath );
                            arguments.Add( newEvent.File_Modified );

                            // start the new thread with the arguments
                            newThreadWork.RunWorkerAsync( arguments );

                            fileModifiedTable[ e.FullPath ] = File.GetLastWriteTime( e.FullPath ).ToString(); //update the modified table with the new timestamp of the file.
                            FILE_MODIFIED_FLAG.WaitOne(); // wait for the modified thread to complete before firing the next thread in the event multiple threads are being worked on.
                        }
                    }
                }
            }
        }
        catch ( IOException IOExcept )
        {
            //catch any errors
            postError( IOExcept, "fswFileWatch_Changed" );
        }
    }

我在这里有一个非常快速和简单的解决方法,它对我来说确实有效,无论事件偶尔会被触发一次或两次或多次,检查它:

private int fireCount = 0;
private void inputFileWatcher_Changed(object sender, FileSystemEventArgs e)
    {
       fireCount++;
       if (fireCount == 1)
        {
            MessageBox.Show("Fired only once!!");
            dowork();
        }
        else
        {
            fireCount = 0;
        }
    }
}