二进制信号量和互斥量之间有区别吗?或者它们本质上是相同的?
当前回答
http://www.geeksforgeeks.org/archives/9102将详细讨论。
互斥是一种锁机制,用于同步对资源的访问。 信号量是一种信号机制。
如果他/她想使用二进制信号量来代替互斥量,这取决于程序员。
其他回答
关于这个主题的好文章:
互斥量与信号量——第1部分:信号量 互斥量与信号量——第2部分:互斥量 互斥量与信号量——第3部分(最后一部分):互斥问题
来自第二部分:
The mutex is similar to the principles of the binary semaphore with one significant difference: the principle of ownership. Ownership is the simple concept that when a task locks (acquires) a mutex only it can unlock (release) it. If a task tries to unlock a mutex it hasn’t locked (thus doesn’t own) then an error condition is encountered and, most importantly, the mutex is not unlocked. If the mutual exclusion object doesn't have ownership then, irrelevant of what it is called, it is not a mutex.
它们不是一回事。它们有不同的用途! 虽然这两种类型的信号量都有一个满/空状态,并且使用相同的API,但它们的用法非常不同。
互斥信号量 互斥信号量用于保护共享资源(数据结构、文件等)。
互斥信号量由接收它的任务“拥有”。如果Task B尝试semGive一个当前由Task a持有的互斥锁,Task B的调用将返回一个错误并失败。
互斥对象总是使用以下顺序:
- SemTake - Critical Section - SemGive
这里有一个简单的例子:
Thread A Thread B Take Mutex access data ... Take Mutex <== Will block ... Give Mutex access data <== Unblocks ... Give Mutex
二进制信号量 二进制信号量解决了一个完全不同的问题:
任务B被挂起等待某些事情发生(例如传感器被绊倒)。 传感器跳闸和中断服务程序运行。它需要通知任务的行程。 任务B应运行并对传感器跳闸采取适当的操作。然后继续等待。
Task A Task B
... Take BinSemaphore <== wait for something
Do Something Noteworthy
Give BinSemaphore do something <== unblocks
注意,对于二进制信号量,B获取信号量,a给出信号量是可以的。 同样,二进制信号量不能保护资源不被访问。信号量的给予和获取从根本上是分离的。 对于同一个任务来说,对同一个二进制信号量的给予和获取通常没有什么意义。
互斥锁用于“锁定机制”。每次只有一个进程可以使用共享资源
而
信号量用于“信号机制” 比如“我完成了,现在可以继续了”
“二进制信号量”是一种编程语言规避使用«信号量»,如«互斥量»。显然有两个非常大的区别:
你称呼他们的方式。 标识符的最大长度。
厕所的例子是一个有趣的类比:
Mutex: Is a key to a toilet. One person can have the key - occupy the toilet - at the time. When finished, the person gives (frees) the key to the next person in the queue. Officially: "Mutexes are typically used to serialise access to a section of re-entrant code that cannot be executed concurrently by more than one thread. A mutex object only allows one thread into a controlled section, forcing other threads which attempt to gain access to that section to wait until the first thread has exited from that section." Ref: Symbian Developer Library (A mutex is really a semaphore with value 1.) Semaphore: Is the number of free identical toilet keys. Example, say we have four toilets with identical locks and keys. The semaphore count - the count of keys - is set to 4 at beginning (all four toilets are free), then the count value is decremented as people are coming in. If all toilets are full, ie. there are no free keys left, the semaphore count is 0. Now, when eq. one person leaves the toilet, semaphore is increased to 1 (one free key), and given to the next person in the queue. Officially: "A semaphore restricts the number of simultaneous users of a shared resource up to a maximum number. Threads can request access to the resource (decrementing the semaphore), and can signal that they have finished using the resource (incrementing the semaphore)." Ref: Symbian Developer Library
推荐文章
- Trap和中断的区别是什么?
- 互斥实例/教程?
- 为什么Linux被称为单片内核?
- 如何检查Python的操作系统?
- 在Swift中,什么相当于Objective-C的“@synchronized”?
- 信号量和监视器——有什么不同?
- 如何使用JavaScript找到操作系统的详细信息?
- 我如何检查操作系统与预处理器指令?
- 如何在没有操作系统的情况下运行程序?
- 线程之间共享哪些资源?
- Windows、Mac OS X和Linux是用什么语言编写的?
- 什么时候应该使用自旋锁而不是互斥锁?
- context . start前台服务()没有调用service . start前台()
- 在c#中使用全局互斥锁的好模式是什么?
- 什么是信号量?