二进制信号量和互斥量之间有区别吗?或者它们本质上是相同的?
当前回答
互斥锁用于阻塞关键区域,而信号量用于计数。
其他回答
互斥锁用于“锁定机制”。每次只有一个进程可以使用共享资源
而
信号量用于“信号机制” 比如“我完成了,现在可以继续了”
厕所的例子是一个有趣的类比:
Mutex: Is a key to a toilet. One person can have the key - occupy the toilet - at the time. When finished, the person gives (frees) the key to the next person in the queue. Officially: "Mutexes are typically used to serialise access to a section of re-entrant code that cannot be executed concurrently by more than one thread. A mutex object only allows one thread into a controlled section, forcing other threads which attempt to gain access to that section to wait until the first thread has exited from that section." Ref: Symbian Developer Library (A mutex is really a semaphore with value 1.) Semaphore: Is the number of free identical toilet keys. Example, say we have four toilets with identical locks and keys. The semaphore count - the count of keys - is set to 4 at beginning (all four toilets are free), then the count value is decremented as people are coming in. If all toilets are full, ie. there are no free keys left, the semaphore count is 0. Now, when eq. one person leaves the toilet, semaphore is increased to 1 (one free key), and given to the next person in the queue. Officially: "A semaphore restricts the number of simultaneous users of a shared resource up to a maximum number. Threads can request access to the resource (decrementing the semaphore), and can signal that they have finished using the resource (incrementing the semaphore)." Ref: Symbian Developer Library
互斥锁
Until recently, the only sleeping lock in the kernel was the semaphore. Most users of semaphores instantiated a semaphore with a count of one and treated them as a mutual exclusion lock—a sleeping version of the spin-lock. Unfortunately, semaphores are rather generic and do not impose any usage constraints. This makes them useful for managing exclusive access in obscure situations, such as complicated dances between the kernel and userspace. But it also means that simpler locking is harder to do, and the lack of enforced rules makes any sort of automated debugging or constraint enforcement impossible. Seeking a simpler sleeping lock, the kernel developers introduced the mutex.Yes, as you are now accustomed to, that is a confusing name. Let’s clarify.The term “mutex” is a generic name to refer to any sleeping lock that enforces mutual exclusion, such as a semaphore with a usage count of one. In recent Linux kernels, the proper noun “mutex” is now also a specific type of sleeping lock that implements mutual exclusion.That is, a mutex is a mutex.
互斥锁的简单性和效率来自于它在信号量要求之外强加给用户的附加约束。信号量是按照Dijkstra的原始设计来实现最基本的行为,而互斥锁则不同,它的用例更严格、更窄: n一次只能有一个任务持有互斥锁。也就是说,互斥锁的使用计数总是1。
Whoever locked a mutex must unlock it. That is, you cannot lock a mutex in one context and then unlock it in another. This means that the mutex isn’t suitable for more complicated synchronizations between kernel and user-space. Most use cases, however, cleanly lock and unlock from the same context. Recursive locks and unlocks are not allowed. That is, you cannot recursively acquire the same mutex, and you cannot unlock an unlocked mutex. A process cannot exit while holding a mutex. A mutex cannot be acquired by an interrupt handler or bottom half, even with mutex_trylock(). A mutex can be managed only via the official API: It must be initialized via the methods described in this section and cannot be copied, hand initialized, or reinitialized.
[1] Linux内核开发,第三版Robert Love
互斥锁控制对单个共享资源的访问。它提供了获取()对资源的访问并在完成后释放()资源的操作。
信号量控制对共享资源池的访问。它提供Wait()操作,直到池中的一个资源可用,并提供Signal()操作,当它返回池时。
当一个信号量保护的资源数量大于1时,它被称为计数信号量。当它控制一个资源时,它被称为布尔信号量。布尔信号量相当于互斥量。
因此,信号量是比互斥量更高级别的抽象。互斥锁可以用信号量来实现,但不能用信号量来实现。
互斥量是任何想要解决临界区问题的算法都必须遵循的标准,而二进制信号量本身是一个可以取0和1值的变量。
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