二进制信号量和互斥量之间有区别吗?或者它们本质上是相同的?
当前回答
互斥对象有所有权,不像信号量。尽管在互斥量范围内的任何线程都可以获得一个未锁定的互斥量,并锁定对同一关键代码段的访问,但只有锁定了互斥量的线程才应该解锁它。
其他回答
互斥锁用于阻塞关键区域,而信号量用于计数。
互斥对象有所有权,不像信号量。尽管在互斥量范围内的任何线程都可以获得一个未锁定的互斥量,并锁定对同一关键代码段的访问,但只有锁定了互斥量的线程才应该解锁它。
既然上面的答案都不能消除困惑,这里有一个答案可以消除我的困惑。
Strictly speaking, a mutex is a locking mechanism used to synchronize access to a resource. Only one task (can be a thread or process based on OS abstraction) can acquire the mutex. It means there will be ownership associated with mutex, and only the owner can release the lock (mutex). Semaphore is signaling mechanism (“I am done, you can carry on” kind of signal). For example, if you are listening songs (assume it as one task) on your mobile and at the same time your friend called you, an interrupt will be triggered upon which an interrupt service routine (ISR) will signal the call processing task to wakeup.
来源:http://www.geeksforgeeks.org/mutex-vs-semaphore/
在Windows上,互斥量和二进制信号量之间有两个区别:
互斥锁只能由拥有所有权的线程释放,即之前调用Wait函数的线程(或在创建互斥锁时获得所有权的线程)。任何线程都可以释放信号量。 线程可以在互斥锁上重复调用等待函数而不会阻塞。但是,如果你在一个二进制信号量上调用了两次等待函数,而中间没有释放信号量,线程就会阻塞。
Mutex is used to protect the sensitive code and data, semaphore is used to synchronization.You also can have practical use with protect the sensitive code, but there might be a risk that release the protection by the other thread by operation V.So The main difference between bi-semaphore and mutex is the ownership.For instance by toilet , Mutex is like that one can enter the toilet and lock the door, no one else can enter until the man get out, bi-semaphore is like that one can enter the toilet and lock the door, but someone else could enter by asking the administrator to open the door, it's ridiculous.
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