是否有一种方法来获得Java中当前正在执行的方法的名称?


当前回答

这可以使用StackWalker自Java 9。

public static String getCurrentMethodName() {
    return StackWalker.getInstance()
                      .walk(s -> s.skip(1).findFirst())
                      .get()
                      .getMethodName();
}

public static String getCallerMethodName() {
    return StackWalker.getInstance()
                      .walk(s -> s.skip(2).findFirst())
                      .get()
                      .getMethodName();
}

StackWalker被设计成懒惰的,所以它可能比Thread更有效。getStackTrace,它为整个调用堆栈急切地创建一个数组。更多信息请参见JEP。

其他回答

public static String getCurrentMethodName() {
        return Thread.currentThread().getStackTrace()[2].getClassName() + "." + Thread.currentThread().getStackTrace()[2].getMethodName();
    }

Util.java:

public static String getCurrentClassAndMethodNames() {
    final StackTraceElement e = Thread.currentThread().getStackTrace()[2];
    final String s = e.getClassName();
    return s.substring(s.lastIndexOf('.') + 1, s.length()) + "." + e.getMethodName();
}

SomeClass.java:

public class SomeClass {
    public static void main(String[] args) {
        System.out.println(Util.getCurrentClassAndMethodNames()); // output: SomeClass.main
    }
}

这种方法的错误之处在于:

class Example {
    FileOutputStream fileOutputStream;

    public Example() {
        //System.out.println("Example.Example()");

        debug("Example.Example()",false); // toggle

        try {
            fileOutputStream = new FileOutputStream("debug.txt");
        } catch (Exception exception) {
             debug(exception + Calendar.getInstance().getTime());
        }
    }

    private boolean was911AnInsideJob() {
        System.out.println("Example.was911AnInsideJob()");
        return true;
    }

    public boolean shouldGWBushBeImpeached(){
        System.out.println("Example.shouldGWBushBeImpeached()");
        return true;
    }

    public void setPunishment(int yearsInJail){
        debug("Server.setPunishment(int yearsInJail=" + yearsInJail + ")",true);
    }
}

在人们疯狂地使用System.out.println(…)之前,你总是可以,也应该,创建一些方法,这样输出就可以被重定向,例如:

    private void debug (Object object) {
        debug(object,true);
    }

    private void dedub(Object object, boolean debug) {
        if (debug) {
            System.out.println(object);

            // you can also write to a file but make sure the output stream
            // ISN'T opened every time debug(Object object) is called

            fileOutputStream.write(object.toString().getBytes());
        }
    }
MethodHandles.lookup().lookupClass().getEnclosingMethod().getName();

这里的大多数答案似乎都是错的。

    public static String getCurrentMethod() {
            return getCurrentMethod(1);
    }
    public static String getCurrentMethod(int skip) {
            return Thread.currentThread().getStackTrace()[1 + 1 + skip].getMethodName();
    }

例子:

    public static void main(String[] args) {
            aaa();
    }

    public static void aaa() {
            System.out.println("aaa  -> "  + getCurrentMethod( ) );
            System.out.println("aaa  -> "  + getCurrentMethod(0) );
            System.out.println("main -> "  + getCurrentMethod(1) );
    }

输出:

aaa  -> aaa
aaa  -> aaa
main -> main