晚不过，简单回答

let prop = 'name';
let value = 'sampath';
this.obj = {
   ...this.obj,
   [prop]: value
};

试试这个:

export interface QueryParams {
    page?: number,
    limit?: number,
    name?: string,
    sort?: string,
    direction?: string
}

然后使用它

const query = {
    name: 'abc'
}
query.page = 1

如果你正在使用Typescript，你可能想要使用类型安全;在这种情况下，naked Object和'any'是相反的。

最好不要使用Object或{}，而是使用一些命名类型;或者您可能正在使用具有特定类型的API，您需要使用自己的字段进行扩展。我发现这个方法很有效:

class Given { ... }  // API specified fields; or maybe it's just Object {}

interface PropAble extends Given {
    props?: string;  // you can cast any Given to this and set .props
    // '?' indicates that the field is optional
}
let g:Given = getTheGivenObject();
(g as PropAble).props = "value for my new field";

// to avoid constantly casting: 
let k = getTheGivenObject() as PropAble;
k.props = "value for props";

为了保证类型是Object(即键值对)，使用:

const obj: {[x: string]: any} = {}
obj.prop = 'cool beans'

案例1:

var car = {type: "BMW", model: "i8", color: "white"};
car['owner'] = "ibrahim"; // You can add a property:

案例2:

var car:any = {type: "BMW", model: "i8", color: "white"};
car.owner = "ibrahim"; // You can set a property: use any type

我倾向于把任何放在另一边，即var foo:IFoo = <任何>{};所以这样的东西仍然是类型安全的:

interface IFoo{
    bar:string;
    baz:string;
    boo:string;     
}

// How I tend to intialize 
var foo:IFoo = <any>{};

foo.bar = "asdf";
foo.baz = "boo";
foo.boo = "boo";

// the following is an error, 
// so you haven't lost type safety
foo.bar = 123; 

或者你可以将这些属性标记为可选:

interface IFoo{
    bar?:string;
    baz?:string;
    boo?:string;    
}

// Now your simple initialization works
var foo:IFoo = {};

在网上试试