你可以用这个:

this.model = Object.assign(this.model, { newProp: 0 });

既然你不能这样做:

obj.prop = 'value';

如果你的TS编译器和linter没有严格要求你，你可以这样写:

obj['prop'] = 'value';

如果你的TS编译器或linter是严格的，另一个答案将是类型转换:

var obj = {};
obj = obj as unknown as { prop: string };
obj.prop = "value";

通过将任何类型的对象类型转换为'any'来存储任何新属性:

var extend = <any>myObject;
extend.NewProperty = anotherObject;

稍后，你可以通过将扩展对象转换回'any'来检索它:

var extendedObject = <any>myObject;
var anotherObject = <AnotherObjectType>extendedObject.NewProperty;

我倾向于把任何放在另一边，即var foo:IFoo = <任何>{};所以这样的东西仍然是类型安全的:

interface IFoo{
    bar:string;
    baz:string;
    boo:string;     
}

// How I tend to intialize 
var foo:IFoo = <any>{};

foo.bar = "asdf";
foo.baz = "boo";
foo.boo = "boo";

// the following is an error, 
// so you haven't lost type safety
foo.bar = 123; 

或者你可以将这些属性标记为可选:

interface IFoo{
    bar?:string;
    baz?:string;
    boo?:string;    
}

// Now your simple initialization works
var foo:IFoo = {};

在网上试试

为了保证类型是Object(即键值对)，使用:

const obj: {[x: string]: any} = {}
obj.prop = 'cool beans'

晚不过，简单回答

let prop = 'name';
let value = 'sampath';
this.obj = {
   ...this.obj,
   [prop]: value
};