案例1:

var car = {type: "BMW", model: "i8", color: "white"};
car['owner'] = "ibrahim"; // You can add a property:

案例2:

var car:any = {type: "BMW", model: "i8", color: "white"};
car.owner = "ibrahim"; // You can set a property: use any type

案例1:

var car = {type: "BMW", model: "i8", color: "white"};
car['owner'] = "ibrahim"; // You can add a property:

案例2:

var car:any = {type: "BMW", model: "i8", color: "white"};
car.owner = "ibrahim"; // You can set a property: use any type

你可以用这个:

this.model = Object.assign(this.model, { newProp: 0 });

可以使用展开操作符在旧对象的基础上创建新对象

interface MyObject {
    prop1: string;
}

const myObj: MyObject = {
    prop1: 'foo',
}

const newObj = {
    ...myObj,
    prop2: 'bar',
}

console.log(newObj.prop2); // 'bar'

TypeScript会推断出原始对象的所有字段，VSCode会自动补全，等等。

尽管编译器抱怨它仍然应该按照你的要求输出它。然而，这是可行的。

const s = {};
s['prop'] = true;

既然你不能这样做:

obj.prop = 'value';

如果你的TS编译器和linter没有严格要求你，你可以这样写:

obj['prop'] = 'value';

如果你的TS编译器或linter是严格的，另一个答案将是类型转换:

var obj = {};
obj = obj as unknown as { prop: string };
obj.prop = "value";