我想从纬度和经度在安卓得到以下值
街道地址 城市/州 邮政编码 完整的地址
如何做到这一点?
我想从纬度和经度在安卓得到以下值
街道地址 城市/州 邮政编码 完整的地址
如何做到这一点?
当前回答
用这个对我有用:D
检索纬度和经度的json数据。
https://maps.googleapis.com/maps/api/geocode/json?key=AIzaSyAr29XeWWAeWZcrOgjjfs3iSnqkWtAz4No&latlng=2.1812,102.4266&sensor=true
用你自己的地方改变纬度、经度。
https://maps.googleapis.com/maps/api/geocode/json?key= < \ API_KEY_HERE > &latlng =“纬度,经度”&sensor = true
您可以使用自己的密钥更改<\API_KEY_HERE>。
需要在谷歌控制台为新的api密钥启用api服务。
D选项是正确答案
其他回答
Geocoder geocoder =new Geocoder(mContext, Locale.getDefault());
// Get the current location from the input parameter list
Location loc = params[0];
// Create a list to contain the result address
List<Address> addresses = null;
try {
addresses = geocoder.getFromLocation(loc.getLatitude(),
loc.getLongitude(), 10);
} catch (IOException e1) {
Log.e("LocationSampleActivity","IO Exception in getFromLocation()");
e1.printStackTrace();
} catch (IllegalArgumentException e2) {
// Error message to post in the log
String errorString = "Illegal arguments " +
Double.toString(loc.getLatitude()) +
" , " +
Double.toString(loc.getLongitude()) +
" passed to address service";
Log.e("LocationSampleActivity", errorString);
e2.printStackTrace();
}
Address address=null;
String zip=null;
String city=null;
String state=null;
StringBuffer st=new StringBuffer();
// If the reverse geocode returned an address
if (addresses != null && addresses.size() > 0) {
String add=addresses.get(0).getAddressLine(0)+","
+addresses.get(0).getSubAdminArea()+","
+addresses.get(0).getSubLocality();
city=addresses.get(0).getLocality();
state=addresses.get(0).getAdminArea();
// Get the first address
for(int i=0 ;i<addresses.size();i++){
address = addresses.get(i);
if(address.getPostalCode()!=null){
zip=address.getPostalCode();
break;
}
}
尝试使用geocoder使用下面的代码:
Geocoder gcd = new Geocoder(MainActivity.this, Locale.getDefault());
List<Address> geoAddresses = geoAddresses = gcd.getFromLocation(location.getLatitude(), location.getLongitude(), 1);
if (geoAddresses.size() > 0) {
String mUserLocation = "";
for (int i = 0; i < 4; i++) { //Since it return only four value we declare this as static.
mUserLocation = mUserLocation + geoAddresses.get(0).getAddressLine(i).replace(",", "") + ", ";
}
}
接受的答案在kotlin格式
private fun getAddressInfo(latitude:Double, longitude:Double){
val geocoder = Geocoder(this, Locale.getDefault())
val addresses: List<Address> = geocoder.getFromLocation(latitude, longitude, 1)
val address: String = addresses[0].getAddressLine(0)
val city: String = addresses[0].locality
val state: String = addresses[0].adminArea
val country: String = addresses[0].countryName
val postalCode: String = addresses[0].postalCode
val knownName: String = addresses[0].featureName
}
只要用这个方法,把你的背,长。
public static void getAddress(Context context, double LATITUDE, double LONGITUDE{
//Set Address
try {
Geocoder geocoder = new Geocoder(context, Locale.getDefault());
List<Address> addresses = geocoder.getFromLocation(LATITUDE, LONGITUDE, 1);
if (addresses != null && addresses.size() > 0) {
String address = addresses.get(0).getAddressLine(0); // If any additional address line present than only, check with max available address lines by getMaxAddressLineIndex()
String city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName(); // Only if available else return NULL
Log.d(TAG, "getAddress: address" + address);
Log.d(TAG, "getAddress: city" + city);
Log.d(TAG, "getAddress: state" + state);
Log.d(TAG, "getAddress: postalCode" + postalCode);
Log.d(TAG, "getAddress: knownName" + knownName);
}
} catch (IOException e) {
e.printStackTrace();
}
return;
}
试试这个,我的朋友
private String getCompleteAddressString(double LATITUDE, double LONGITUDE) {
String strAdd = "";
Geocoder geocoder = new Geocoder(this, Locale.getDefault());
try {
List<Address> addresses = geocoder.getFromLocation(LATITUDE, LONGITUDE, 1);
if (addresses != null) {
Address returnedAddress = addresses.get(0);
StringBuilder strReturnedAddress = new StringBuilder("");
for (int i = 0; i <= returnedAddress.getMaxAddressLineIndex(); i++) {
strReturnedAddress.append(returnedAddress.getAddressLine(i)).append("\n");
}
strAdd = strReturnedAddress.toString();
Log.w("My Current loction address", strReturnedAddress.toString());
} else {
Log.w("My Current loction address", "No Address returned!");
}
} catch (Exception e) {
e.printStackTrace();
Log.w("My Current loction address", "Canont get Address!");
}
return strAdd;
}