我有一个表，需要保存不重复的行。 我不确定速度和效率。

DELETE FROM myTable WHERE RowID IN (
  SELECT MIN(RowID) AS IDNo FROM myTable
  GROUP BY Col1, Col2, Col3
  HAVING COUNT(*) = 2 )

有时使用软删除机制，其中记录日期以指示删除的日期。在这种情况下，可以使用UPDATE语句根据重复的条目更新该字段。

UPDATE MY_TABLE
   SET DELETED = getDate()
 WHERE TABLE_ID IN (
    SELECT x.TABLE_ID
      FROM MY_TABLE x
      JOIN (SELECT min(TABLE_ID) id, COL_1, COL_2, COL_3
              FROM MY_TABLE d
             GROUP BY d.COL_1, d.COL_2, d.COL_3
            HAVING count(*) > 1) AS d ON d.COL_1 = x.COL_1
                                     AND d.COL_2 = x.COL_2
                                     AND d.COL_3 = x.COL_3
                                     AND d.TABLE_ID <> x.TABLE_ID
             /*WHERE x.COL_4 <> 'D' -- Additional filter*/)

对于包含大约3000万行、重复量有高有低的中等数据表，这种方法非常适用。

快速和脏删除精确重复的行(小表):

select  distinct * into t2 from t1;
delete from t1;
insert into t1 select *  from t2;
drop table t2;

alter table MyTable add sno int identity(1,1)
    delete from MyTable where sno in
    (
    select sno from (
    select *,
    RANK() OVER ( PARTITION BY RowID,Col3 ORDER BY sno DESC )rank
    From MyTable
    )T
    where rank>1
    )

    alter table MyTable 
    drop  column sno

CREATE TABLE car(Id int identity(1,1), PersonId int, CarId int)

INSERT INTO car(PersonId,CarId)
VALUES(1,2),(1,3),(1,2),(2,4)

--SELECT * FROM car

;WITH CTE as(
SELECT ROW_NUMBER() over (PARTITION BY personid,carid order by personid,carid) as rn,Id,PersonID,CarId from car)

DELETE FROM car where Id in(SELECT Id FROM CTE WHERE rn>1)

另一个简单的解决方案可以在这里粘贴的链接中找到。这个方法很容易掌握，似乎对大多数类似的问题都很有效。虽然它是为SQL Server，但所使用的概念是可以接受的。

以下是链接页面的相关部分:

考虑以下数据:

EMPLOYEE_ID ATTENDANCE_DATE
A001    2011-01-01
A001    2011-01-01
A002    2011-01-01
A002    2011-01-01
A002    2011-01-01
A003    2011-01-01

那么我们如何删除这些重复的数据呢?

首先，使用以下代码在表中插入一个标识列:

ALTER TABLE dbo.ATTENDANCE ADD AUTOID INT IDENTITY(1,1)  

使用下面的代码来解决它:

DELETE FROM dbo.ATTENDANCE WHERE AUTOID NOT IN (SELECT MIN(AUTOID) _
    FROM dbo.ATTENDANCE GROUP BY EMPLOYEE_ID,ATTENDANCE_DATE)