我需要从一个相当大的SQL Server表(即300,000+行)中删除重复的行。
当然,由于RowID标识字段的存在,这些行不会完全重复。
MyTable
RowID int not null identity(1,1) primary key,
Col1 varchar(20) not null,
Col2 varchar(2048) not null,
Col3 tinyint not null
我该怎么做呢?
我需要从一个相当大的SQL Server表(即300,000+行)中删除重复的行。
当然,由于RowID标识字段的存在,这些行不会完全重复。
MyTable
RowID int not null identity(1,1) primary key,
Col1 varchar(20) not null,
Col2 varchar(2048) not null,
Col3 tinyint not null
我该怎么做呢?
当前回答
创建具有相同结构的新空白表 像这样执行查询 插入tc_category1 SELECT * 从tc_category GROUP BY category_id, application_id count(*) > 然后执行这个查询 插入tc_category1 SELECT * 从tc_category GROUP BY category_id, application_id count(*) = 1
其他回答
我想这会很有帮助。这里,ROW_NUMBER() OVER(分区由res1。Title ORDER BY res1.Id)作为num来区分重复的行。
delete FROM
(SELECT res1.*,ROW_NUMBER() OVER(PARTITION BY res1.Title ORDER BY res1.Id)as num
FROM
(select * from [dbo].[tbl_countries])as res1
)as res2
WHERE res2.num > 1
快速和脏删除精确重复的行(小表):
select distinct * into t2 from t1;
delete from t1;
insert into t1 select * from t2;
drop table t2;
CREATE TABLE car(Id int identity(1,1), PersonId int, CarId int)
INSERT INTO car(PersonId,CarId)
VALUES(1,2),(1,3),(1,2),(2,4)
--SELECT * FROM car
;WITH CTE as(
SELECT ROW_NUMBER() over (PARTITION BY personid,carid order by personid,carid) as rn,Id,PersonID,CarId from car)
DELETE FROM car where Id in(SELECT Id FROM CTE WHERE rn>1)
另一种基于两列删除重复项的方法
我发现这个查询更容易阅读和替换。
DELETE
FROM
TABLE_NAME
WHERE FIRST_COLUMNS
IN(
SELECT * FROM
( SELECT MIN(FIRST_COLUMNS)
FROM TABLE_NAME
GROUP BY
FIRST_COLUMNS,
SECOND_COLUMNS
HAVING COUNT(FIRST_COLUMNS) > 1
) temp
)
注意:在运行查询之前最好模拟查询。
DELETE
FROM MyTable
WHERE NOT EXISTS (
SELECT min(RowID)
FROM Mytable
WHERE (SELECT RowID
FROM Mytable
GROUP BY Col1, Col2, Col3
))
);