首先，您可以使用MIN()和Group By选择最小RowId。我们将保留这些行。

   SELECT MIN(RowId) as RowId
   FROM MyTable 
   GROUP BY Col1, Col2, Col3

删除那些不在最小RowId使用范围内的RowId

DELETE FROM MyTable WHERE RowId Not IN()

最后的查询:

DELETE FROM MyTable WHERE RowId Not IN(

    SELECT MIN(RowId) as RowId
    FROM MyTable 
    GROUP BY Col1, Col2, Col3
)

你也可以在SQL Fiddle中检查我的答案

对于表结构

MyTable

RowID int not null identity(1,1) primary key,
Col1 varchar(20) not null,
Col2 varchar(2048) not null,
Col3 tinyint not null

删除重复项的查询:

DELETE t1
FROM MyTable t1
INNER JOIN MyTable t2
WHERE t1.RowID > t2.RowID
  AND t1.Col1 = t2.Col1
  AND t1.Col2=t2.Col2
  AND t1.Col3=t2.Col3;

我假设RowID是一种自动递增，其余列有重复的值。

delete t1
from table t1, table t2
where t1.columnA = t2.columnA
and t1.rowid>t2.rowid

邮政：

delete
from table t1
using table t2
where t1.columnA = t2.columnA
and t1.rowid > t2.rowid

通过使用下面的查询，我们可以基于单列或多列删除重复的记录。下面的查询是基于两列进行删除。表名为:testing，列名为empno,empname

DELETE FROM testing WHERE empno not IN (SELECT empno FROM (SELECT empno, ROW_NUMBER() OVER (PARTITION BY empno ORDER BY empno) 
AS [ItemNumber] FROM testing) a WHERE ItemNumber > 1)
or empname not in
(select empname from (select empname,row_number() over(PARTITION BY empno ORDER BY empno) 
AS [ItemNumber] FROM testing) a WHERE ItemNumber > 1)

另一种基于两列删除重复项的方法

我发现这个查询更容易阅读和替换。

DELETE 
FROM 
 TABLE_NAME 
 WHERE FIRST_COLUMNS 
 IN( 
       SELECT * FROM 
           ( SELECT MIN(FIRST_COLUMNS) 
             FROM TABLE_NAME 
             GROUP BY 
                      FIRST_COLUMNS,
                      SECOND_COLUMNS 
             HAVING COUNT(FIRST_COLUMNS) > 1 
            ) temp 
   )

注意:在运行查询之前最好模拟查询。

使用这个

WITH tblTemp as
(
SELECT ROW_NUMBER() Over(PARTITION BY Name,Department ORDER BY Name)
   As RowNumber,* FROM <table_name>
)
DELETE FROM tblTemp where RowNumber >1