使用这个

WITH tblTemp as
(
SELECT ROW_NUMBER() Over(PARTITION BY Name,Department ORDER BY Name)
   As RowNumber,* FROM <table_name>
)
DELETE FROM tblTemp where RowNumber >1

我想我应该分享我的解决方案，因为它在特殊情况下是有效的。 在我的例子中，有重复值的表没有外键(因为这些值是从另一个db复制的)。

begin transaction
-- create temp table with identical structure as source table
Select * Into #temp From tableName Where 1 = 2

-- insert distinct values into temp
insert into #temp 
select distinct * 
from  tableName

-- delete from source
delete from tableName 

-- insert into source from temp
insert into tableName 
select * 
from #temp

rollback transaction
-- if this works, change rollback to commit and execute again to keep you changes!!

PS:在处理这样的事情时，我总是使用事务，这不仅确保了所有事情都作为一个整体执行，而且还允许我在没有任何风险的情况下进行测试。但是当然你应该做个备份，以防万一……

创建具有相同结构的新空白表 像这样执行查询 插入tc_category1 SELECT * 从tc_category GROUP BY category_id, application_id count(*) > 然后执行这个查询 插入tc_category1 SELECT * 从tc_category GROUP BY category_id, application_id count(*) = 1

如果您想预览要删除的行，并控制要保留的重复行。参见http://developer.azurewebsites.net/2014/09/better-sql-group-by-find-duplicate-data/

with MYCTE as (
  SELECT ROW_NUMBER() OVER (
    PARTITION BY DuplicateKey1
                ,DuplicateKey2 -- optional
    ORDER BY CreatedAt -- the first row among duplicates will be kept, other rows will be removed
  ) RN
  FROM MyTable
)
DELETE FROM MYCTE
WHERE RN > 1

对于表结构

MyTable

RowID int not null identity(1,1) primary key,
Col1 varchar(20) not null,
Col2 varchar(2048) not null,
Col3 tinyint not null

删除重复项的查询:

DELETE t1
FROM MyTable t1
INNER JOIN MyTable t2
WHERE t1.RowID > t2.RowID
  AND t1.Col1 = t2.Col1
  AND t1.Col2=t2.Col2
  AND t1.Col3=t2.Col3;

我假设RowID是一种自动递增，其余列有重复的值。

在postgresql中删除重复行的一个非常简单的方法。

DELETE FROM table1 a
USING table1 b
WHERE a.id < b.id
AND a.column1 = b.column1
AND a.column2 = b.column2;