delete t1
from table t1, table t2
where t1.columnA = t2.columnA
and t1.rowid>t2.rowid

邮政：

delete
from table t1
using table t2
where t1.columnA = t2.columnA
and t1.rowid > t2.rowid

使用CTE。这个想法是连接一个或多个列，形成一个重复的记录，然后删除你喜欢的:

;with cte as (
    select 
        min(PrimaryKey) as PrimaryKey
        UniqueColumn1,
        UniqueColumn2
    from dbo.DuplicatesTable 
    group by
        UniqueColumn1, UniqueColumn1
    having count(*) > 1
)
delete d
from dbo.DuplicatesTable d 
inner join cte on 
    d.PrimaryKey > cte.PrimaryKey and
    d.UniqueColumn1 = cte.UniqueColumn1 and 
    d.UniqueColumn2 = cte.UniqueColumn2;

哦,当然。使用临时表。如果你想要一个“工作”的单一的、性能不太好的语句，你可以使用:

DELETE FROM MyTable WHERE NOT RowID IN
    (SELECT 
        (SELECT TOP 1 RowID FROM MyTable mt2 
        WHERE mt2.Col1 = mt.Col1 
        AND mt2.Col2 = mt.Col2 
        AND mt2.Col3 = mt.Col3) 
    FROM MyTable mt)

基本上，对于表中的每一行，子选择将查找与所考虑行的完全相同的所有行的顶部RowID。因此，您最终会得到一个表示“原始”非重复行的RowIDs列表。

alter table MyTable add sno int identity(1,1)
    delete from MyTable where sno in
    (
    select sno from (
    select *,
    RANK() OVER ( PARTITION BY RowID,Col3 ORDER BY sno DESC )rank
    From MyTable
    )T
    where rank>1
    )

    alter table MyTable 
    drop  column sno

获取重复的行:

SELECT
name, email, COUNT(*)
FROM 
users
GROUP BY
name, email
HAVING COUNT(*) > 1

删除重复的行。

DELETE users 
WHERE rowid NOT IN 
(SELECT MIN(rowid)
FROM users
GROUP BY name, email);      

在postgresql中删除重复行的一个非常简单的方法。

DELETE FROM table1 a
USING table1 b
WHERE a.id < b.id
AND a.column1 = b.column1
AND a.column2 = b.column2;