假设没有空值，您GROUP BY唯一的列，并选择最小(或最大)RowId作为要保留的行。然后，删除所有没有行id的内容:

DELETE FROM MyTable
LEFT OUTER JOIN (
   SELECT MIN(RowId) as RowId, Col1, Col2, Col3 
   FROM MyTable 
   GROUP BY Col1, Col2, Col3
) as KeepRows ON
   MyTable.RowId = KeepRows.RowId
WHERE
   KeepRows.RowId IS NULL

如果您使用的是GUID而不是整数，则可以进行替换

MIN(RowId)

with

CONVERT(uniqueidentifier, MIN(CONVERT(char(36), MyGuidColumn)))

这将删除重复的行，除了第一行

DELETE
FROM
    Mytable
WHERE
    RowID NOT IN (
        SELECT
            MIN(RowID)
        FROM
            Mytable
        GROUP BY
            Col1,
            Col2,
            Col3
    )

引用(http://www.codeproject.com/Articles/157977/Remove-Duplicate-Rows-from-a-Table-in-SQL-Server)

我更喜欢子查询\having count(*) > 1解决方案内部连接，因为我发现它更容易阅读，它很容易变成一个SELECT语句来验证什么将被删除，然后再运行它。

--DELETE FROM table1 
--WHERE id IN ( 
     SELECT MIN(id) FROM table1 
     GROUP BY col1, col2, col3 
     -- could add a WHERE clause here to further filter
     HAVING count(*) > 1
--)

alter table MyTable add sno int identity(1,1)
    delete from MyTable where sno in
    (
    select sno from (
    select *,
    RANK() OVER ( PARTITION BY RowID,Col3 ORDER BY sno DESC )rank
    From MyTable
    )T
    where rank>1
    )

    alter table MyTable 
    drop  column sno

我想提一下这种方法，它可能是有帮助的，并且适用于所有SQL服务器: 通常只有一到两个副本，副本的id和数量是已知的。在这种情况下:

SET ROWCOUNT 1 -- or set to number of rows to be deleted
delete from myTable where RowId = DuplicatedID
SET ROWCOUNT 0

现在让我们看看elasticalsearch表，这个表有重复的行，Id是相同的uniq字段。我们知道如果某个id存在于某个组条件下，那么我们可以删除该组作用域之外的其他行。我的举止表明了这一标准。

很多情况下，这个线程是在类似的状态，我。只需根据删除重复(重复)行的情况更改目标组条件。

DELETE 
FROM elasticalsearch
WHERE Id NOT IN 
               (SELECT min(Id)
                     FROM elasticalsearch
                     GROUP BY FirmId,FilterSearchString
                     ) 

干杯