为什么不直接使用:

hash.delete(key)

哈希现在是您正在寻找的“剩余哈希”。

#in lib/core_extensions.rb
class Hash
  #pass single or array of keys, which will be removed, returning the remaining hash
  def remove!(*keys)
    keys.each{|key| self.delete(key) }
    self
  end

  #non-destructive version
  def remove(*keys)
    self.dup.remove!(*keys)
  end
end

#in config/initializers/app_environment.rb (or anywhere in config/initializers)
require 'core_extensions'

我已经设置好了，所以.remove返回一个删除键的散列副本，而remove!修改哈希本身。这与ruby的约定是一致的。从控制台

>> hash = {:a => 1, :b => 2}
=> {:b=>2, :a=>1}
>> hash.remove(:a)
=> {:b=>2}
>> hash
=> {:b=>2, :a=>1}
>> hash.remove!(:a)
=> {:b=>2}
>> hash
=> {:b=>2}
>> hash.remove!(:a, :b)
=> {}

你可以用except!来自facets gem:

>> require 'facets' # or require 'facets/hash/except'
=> true
>> {:a => 1, :b => 2}.except(:a)
=> {:b=>2}

原来的哈希值不会改变。

编辑:正如Russel所说，facets有一些隐藏的问题，并且与ActiveSupport不完全兼容api。另一方面，ActiveSupport不像facet那样完整。最后，我将使用AS，并让边界情况出现在代码中。

onlineer普通红宝石，它只适用于红宝石> 1.9.x:

1.9.3p0 :002 > h = {:a => 1, :b => 2}
 => {:a=>1, :b=>2} 
1.9.3p0 :003 > h.tap { |hs| hs.delete(:a) }
 => {:b=>2} 

方法总是返回被调用的对象…

否则，如果你需要active_support/core_ext/hash(这在每个Rails应用程序中都是自动需要的)，你可以根据需要使用以下方法之一:

➜  ~  irb
1.9.3p125 :001 > require 'active_support/core_ext/hash' => true 
1.9.3p125 :002 > h = {:a => 1, :b => 2, :c => 3}
 => {:a=>1, :b=>2, :c=>3} 
1.9.3p125 :003 > h.except(:a)
 => {:b=>2, :c=>3} 
1.9.3p125 :004 > h.slice(:a)
 => {:a=>1} 

Except使用黑名单方法，因此它删除了所有作为参数列出的键，而slice使用白名单方法，因此它删除了所有没有作为参数列出的键。这些方法也存在bang版本(除了!和slice!)，它们修改给定的哈希，但它们的返回值不同，它们都返回哈希。它代表slice删除的键!还有为except保留的钥匙!：

1.9.3p125 :011 > {:a => 1, :b => 2, :c => 3}.except!(:a)
 => {:b=>2, :c=>3} 
1.9.3p125 :012 > {:a => 1, :b => 2, :c => 3}.slice!(:a)
 => {:b=>2, :c=>3} 

Rails有一个except/except!方法，该方法返回删除了这些键后的散列。如果您已经在使用Rails，就没有必要创建自己的版本。

class Hash
  # Returns a hash that includes everything but the given keys.
  #   hash = { a: true, b: false, c: nil}
  #   hash.except(:c) # => { a: true, b: false}
  #   hash # => { a: true, b: false, c: nil}
  #
  # This is useful for limiting a set of parameters to everything but a few known toggles:
  #   @person.update(params[:person].except(:admin))
  def except(*keys)
    dup.except!(*keys)
  end

  # Replaces the hash without the given keys.
  #   hash = { a: true, b: false, c: nil}
  #   hash.except!(:c) # => { a: true, b: false}
  #   hash # => { a: true, b: false }
  def except!(*keys)
    keys.each { |key| delete(key) }
    self
  end
end

在纯Ruby中:

{:a => 1, :b => 2}.tap{|x| x.delete(:a)}   # => {:b=>2}

如果你想使用纯Ruby(没有Rails)，不想创建扩展方法(也许你只需要在一两个地方使用扩展方法，不想用大量的方法污染命名空间)，不想在适当的地方编辑散列(也就是说，你像我一样是函数式编程的粉丝)，你可以“选择”:

>> x = {:a => 1, :b => 2, :c => 3}
=> {:a=>1, :b=>2, :c=>3}
>> x.select{|x| x != :a}
=> {:b=>2, :c=>3}
>> x.select{|x| ![:a, :b].include?(x)}
=> {:c=>3}
>> x
=> {:a=>1, :b=>2, :c=>3}

这是一种单行的方式，但可读性不强。建议用两行代替。

use_remaining_hash_for_something(Proc.new { hash.delete(:key); hash }.call)

这也可以工作:hash[hey] = nil

参见Ruby on Rails:删除多个散列键

hash.delete_if{ |k,| keys_to_delete.include? k }

如果你正在使用Ruby 2，你可以使用改进，而不是猴子补丁或不必要地包括大型库:

module HashExtensions
  refine Hash do
    def except!(*candidates)
      candidates.each { |candidate| delete(candidate) }
      self
    end

    def except(*candidates)
      dup.remove!(candidates)
    end
  end
end

您可以在不影响程序其他部分的情况下使用此特性，也不必包含大型外部库。

class FabulousCode
  using HashExtensions

  def incredible_stuff
    delightful_hash.except(:not_fabulous_key)
  end
end

有许多方法可以从散列中删除键并在Ruby中获取剩余的散列。

.slice => It will return selected keys and not delete them from the original hash. Use slice! if you want to remove the keys permanently else use simple slice. 2.2.2 :074 > hash = {"one"=>1, "two"=>2, "three"=>3} => {"one"=>1, "two"=>2, "three"=>3} 2.2.2 :075 > hash.slice("one","two") => {"one"=>1, "two"=>2} 2.2.2 :076 > hash => {"one"=>1, "two"=>2, "three"=>3} .delete => It will delete the selected keys from the original hash(it can accept only one key and not more than one). 2.2.2 :094 > hash = {"one"=>1, "two"=>2, "three"=>3} => {"one"=>1, "two"=>2, "three"=>3} 2.2.2 :095 > hash.delete("one") => 1 2.2.2 :096 > hash => {"two"=>2, "three"=>3} .except => It will return the remaining keys but not delete anything from the original hash. Use except! if you want to remove the keys permanently else use simple except. 2.2.2 :097 > hash = {"one"=>1, "two"=>2, "three"=>3} => {"one"=>1, "two"=>2, "three"=>3} 2.2.2 :098 > hash.except("one","two") => {"three"=>3} 2.2.2 :099 > hash => {"one"=>1, "two"=>2, "three"=>3} .delete_if => In case you need to remove a key based on a value. It will obviously remove the matching keys from the original hash. 2.2.2 :115 > hash = {"one"=>1, "two"=>2, "three"=>3, "one_again"=>1} => {"one"=>1, "two"=>2, "three"=>3, "one_again"=>1} 2.2.2 :116 > value = 1 => 1 2.2.2 :117 > hash.delete_if { |k,v| v == value } => {"two"=>2, "three"=>3} 2.2.2 :118 > hash => {"two"=>2, "three"=>3} .compact => It is used to remove all nil values from the hash. Use compact! if you want to remove the nil values permanently else use simple compact. 2.2.2 :119 > hash = {"one"=>1, "two"=>2, "three"=>3, "nothing"=>nil, "no_value"=>nil} => {"one"=>1, "two"=>2, "three"=>3, "nothing"=>nil, "no_value"=>nil} 2.2.2 :120 > hash.compact => {"one"=>1, "two"=>2, "three"=>3}

基于Ruby 2.2.2的结果。

如果delete返回哈希的delete对，那就太好了。 我这样做:

hash = {a: 1, b: 2, c: 3}
{b: hash.delete(:b)} # => {:b=>2}
hash  # => {:a=>1, :c=>3} 

在哈希中删除键的多种方法。 你可以使用下面的任何方法

hash = {a: 1, b: 2, c: 3}
hash.except!(:a) # Will remove *a* and return HASH
hash # Output :- {b: 2, c: 3}

hash = {a: 1, b: 2, c: 3}
hash.delete(:a) # will remove *a* and return 1 if *a* not present than return nil

有很多方法，你可以看看Ruby doc of Hash。

谢谢你！

Hash#except (Ruby 3.0+)

从Ruby 3.0开始，hash# except是一个内置方法。

因此，不再需要依赖ActiveSupport或编写monkey-patches来使用它。

h = { a: 1, b: 2, c: 3 }
p h.except(:a) #=> {:b=>2, :c=>3}

来源:

除了官方Ruby文档。 链接到PR。 Ruby 3.0增加了Hash#except和ENV.except。

试试except!方法。

{:a => 1, :b => 2}.except!(:a)   #=> {:b => 2}