添加一对新的哈希,我做:

{:a => 1, :b => 2}.merge!({:c => 3})   #=> {:a => 1, :b => 2, :c => 3}

是否有类似的方法从哈希中删除键?

如此:

{:a => 1, :b => 2}.reject! { |k| k == :a }   #=> {:b => 2}

但我希望有这样的东西:

{:a => 1, :b => 2}.delete!(:a)   #=> {:b => 2}

重要的是,返回值将是剩余的散列,所以我可以这样做:

foo(my_hash.reject! { |k| k == my_key })

在一行里。


当前回答

如果delete返回哈希的delete对,那就太好了。 我这样做:

hash = {a: 1, b: 2, c: 3}
{b: hash.delete(:b)} # => {:b=>2}
hash  # => {:a=>1, :c=>3} 

其他回答

有许多方法可以从散列中删除键并在Ruby中获取剩余的散列。

.slice => It will return selected keys and not delete them from the original hash. Use slice! if you want to remove the keys permanently else use simple slice. 2.2.2 :074 > hash = {"one"=>1, "two"=>2, "three"=>3} => {"one"=>1, "two"=>2, "three"=>3} 2.2.2 :075 > hash.slice("one","two") => {"one"=>1, "two"=>2} 2.2.2 :076 > hash => {"one"=>1, "two"=>2, "three"=>3} .delete => It will delete the selected keys from the original hash(it can accept only one key and not more than one). 2.2.2 :094 > hash = {"one"=>1, "two"=>2, "three"=>3} => {"one"=>1, "two"=>2, "three"=>3} 2.2.2 :095 > hash.delete("one") => 1 2.2.2 :096 > hash => {"two"=>2, "three"=>3} .except => It will return the remaining keys but not delete anything from the original hash. Use except! if you want to remove the keys permanently else use simple except. 2.2.2 :097 > hash = {"one"=>1, "two"=>2, "three"=>3} => {"one"=>1, "two"=>2, "three"=>3} 2.2.2 :098 > hash.except("one","two") => {"three"=>3} 2.2.2 :099 > hash => {"one"=>1, "two"=>2, "three"=>3} .delete_if => In case you need to remove a key based on a value. It will obviously remove the matching keys from the original hash. 2.2.2 :115 > hash = {"one"=>1, "two"=>2, "three"=>3, "one_again"=>1} => {"one"=>1, "two"=>2, "three"=>3, "one_again"=>1} 2.2.2 :116 > value = 1 => 1 2.2.2 :117 > hash.delete_if { |k,v| v == value } => {"two"=>2, "three"=>3} 2.2.2 :118 > hash => {"two"=>2, "three"=>3} .compact => It is used to remove all nil values from the hash. Use compact! if you want to remove the nil values permanently else use simple compact. 2.2.2 :119 > hash = {"one"=>1, "two"=>2, "three"=>3, "nothing"=>nil, "no_value"=>nil} => {"one"=>1, "two"=>2, "three"=>3, "nothing"=>nil, "no_value"=>nil} 2.2.2 :120 > hash.compact => {"one"=>1, "two"=>2, "three"=>3}

基于Ruby 2.2.2的结果。

onlineer普通红宝石,它只适用于红宝石> 1.9.x:

1.9.3p0 :002 > h = {:a => 1, :b => 2}
 => {:a=>1, :b=>2} 
1.9.3p0 :003 > h.tap { |hs| hs.delete(:a) }
 => {:b=>2} 

方法总是返回被调用的对象…

否则,如果你需要active_support/core_ext/hash(这在每个Rails应用程序中都是自动需要的),你可以根据需要使用以下方法之一:

➜  ~  irb
1.9.3p125 :001 > require 'active_support/core_ext/hash' => true 
1.9.3p125 :002 > h = {:a => 1, :b => 2, :c => 3}
 => {:a=>1, :b=>2, :c=>3} 
1.9.3p125 :003 > h.except(:a)
 => {:b=>2, :c=>3} 
1.9.3p125 :004 > h.slice(:a)
 => {:a=>1} 

Except使用黑名单方法,因此它删除了所有作为参数列出的键,而slice使用白名单方法,因此它删除了所有没有作为参数列出的键。这些方法也存在bang版本(除了!和slice!),它们修改给定的哈希,但它们的返回值不同,它们都返回哈希。它代表slice删除的键!还有为except保留的钥匙!:

1.9.3p125 :011 > {:a => 1, :b => 2, :c => 3}.except!(:a)
 => {:b=>2, :c=>3} 
1.9.3p125 :012 > {:a => 1, :b => 2, :c => 3}.slice!(:a)
 => {:b=>2, :c=>3} 

为什么不直接使用:

hash.delete(key)

哈希现在是您正在寻找的“剩余哈希”。

如果你想使用纯Ruby(没有Rails),不想创建扩展方法(也许你只需要在一两个地方使用扩展方法,不想用大量的方法污染命名空间),不想在适当的地方编辑散列(也就是说,你像我一样是函数式编程的粉丝),你可以“选择”:

>> x = {:a => 1, :b => 2, :c => 3}
=> {:a=>1, :b=>2, :c=>3}
>> x.select{|x| x != :a}
=> {:b=>2, :c=>3}
>> x.select{|x| ![:a, :b].include?(x)}
=> {:c=>3}
>> x
=> {:a=>1, :b=>2, :c=>3}
#in lib/core_extensions.rb
class Hash
  #pass single or array of keys, which will be removed, returning the remaining hash
  def remove!(*keys)
    keys.each{|key| self.delete(key) }
    self
  end

  #non-destructive version
  def remove(*keys)
    self.dup.remove!(*keys)
  end
end

#in config/initializers/app_environment.rb (or anywhere in config/initializers)
require 'core_extensions'

我已经设置好了,所以.remove返回一个删除键的散列副本,而remove!修改哈希本身。这与ruby的约定是一致的。从控制台

>> hash = {:a => 1, :b => 2}
=> {:b=>2, :a=>1}
>> hash.remove(:a)
=> {:b=>2}
>> hash
=> {:b=>2, :a=>1}
>> hash.remove!(:a)
=> {:b=>2}
>> hash
=> {:b=>2}
>> hash.remove!(:a, :b)
=> {}