如果程序被指定像这样运行,那么在c++中解析命令行参数的最佳方式是什么:
prog [-abc] [input [output]]
是否有某种方法可以在标准库中实现这一点,或者我需要自己编写代码?
相关:
在unicode c++应用程序中解析命令行参数
如果程序被指定像这样运行,那么在c++中解析命令行参数的最佳方式是什么:
prog [-abc] [input [output]]
是否有某种方法可以在标准库中实现这一点,或者我需要自己编写代码?
相关:
在unicode c++应用程序中解析命令行参数
当前回答
有很多好的库可用。
Boost Program Options是一个相当重量级的解决方案,因为将它添加到项目中需要构建Boost,而且语法有点令人困惑(在我看来)。但是,它几乎可以做任何事情,包括让命令行选项覆盖配置文件中设置的选项。
SimpleOpt是一个相当全面但简单的命令行处理器。它是一个单一的文件,具有简单的结构,但只处理将命令行解析为选项,您必须进行所有的类型和范围检查。它适用于Windows和Unix,并且还附带了一个适用于Windows的glob版本。
getopt在Windows上可用。它与Unix机器上的相同,但它通常是一个GPL库。
其他回答
您可以使用GNU GetOpt (LGPL)或各种c++端口之一,例如getoptpp (GPL)。
一个简单的例子使用GetOpt你想要的东西(prog [-ab] input)如下:
// C Libraries:
#include <string>
#include <iostream>
#include <unistd.h>
// Namespaces:
using namespace std;
int main(int argc, char** argv) {
int opt;
string input = "";
bool flagA = false;
bool flagB = false;
// Retrieve the (non-option) argument:
if ( (argc <= 1) || (argv[argc-1] == NULL) || (argv[argc-1][0] == '-') ) { // there is NO input...
cerr << "No argument provided!" << endl;
//return 1;
}
else { // there is an input...
input = argv[argc-1];
}
// Debug:
cout << "input = " << input << endl;
// Shut GetOpt error messages down (return '?'):
opterr = 0;
// Retrieve the options:
while ( (opt = getopt(argc, argv, "ab")) != -1 ) { // for each option...
switch ( opt ) {
case 'a':
flagA = true;
break;
case 'b':
flagB = true;
break;
case '?': // unknown option...
cerr << "Unknown option: '" << char(optopt) << "'!" << endl;
break;
}
}
// Debug:
cout << "flagA = " << flagA << endl;
cout << "flagB = " << flagB << endl;
return 0;
}
你可以试试我的小选项头(166 loc很容易被黑客)options.hpp。它是一个单头实现,应该按您的要求执行。它还会自动打印帮助页面。
我可以建议使用模板化的c++命令行解析器库(GitHub上的一些分支是可用的),API非常直接并且(引用自网站):
该库完全在头文件中实现,因此很容易 与其他软件一起使用和分发。它是MIT授权的 无后顾之忧的发行许可证。
这是手册中的一个例子,为了简单起见,这里有颜色:
#include <string>
#include <iostream>
#include <algorithm>
#include <tclap/CmdLine.h>
int main(int argc, char** argv)
{
// Wrap everything in a try block. Do this every time,
// because exceptions will be thrown for problems.
try {
// Define the command line object, and insert a message
// that describes the program. The "Command description message"
// is printed last in the help text. The second argument is the
// delimiter (usually space) and the last one is the version number.
// The CmdLine object parses the argv array based on the Arg objects
// that it contains.
TCLAP::CmdLine cmd("Command description message", ' ', "0.9");
// Define a value argument and add it to the command line.
// A value arg defines a flag and a type of value that it expects,
// such as "-n Bishop".
TCLAP::ValueArg<std::string> nameArg("n","name","Name to print",true,"homer","string");
// Add the argument nameArg to the CmdLine object. The CmdLine object
// uses this Arg to parse the command line.
cmd.add( nameArg );
// Define a switch and add it to the command line.
// A switch arg is a boolean argument and only defines a flag that
// indicates true or false. In this example the SwitchArg adds itself
// to the CmdLine object as part of the constructor. This eliminates
// the need to call the cmd.add() method. All args have support in
// their constructors to add themselves directly to the CmdLine object.
// It doesn't matter which idiom you choose, they accomplish the same thing.
TCLAP::SwitchArg reverseSwitch("r","reverse","Print name backwards", cmd, false);
// Parse the argv array.
cmd.parse( argc, argv );
// Get the value parsed by each arg.
std::string name = nameArg.getValue();
bool reverseName = reverseSwitch.getValue();
// Do what you intend.
if ( reverseName )
{
std::reverse(name.begin(),name.end());
std::cout << "My name (spelled backwards) is: " << name << std::endl;
}
else
std::cout << "My name is: " << name << std::endl;
} catch (TCLAP::ArgException &e) // catch any exceptions
{ std::cerr << "error: " << e.error() << " for arg " << e.argId() << std::endl; }
}
Following from my comment and from rbaleksandar's answer, the arguments passed to any program in C are string values. You are provided the argument count (argc) which gives you the argument indexes zero-based beginning with the name of the program currently being run (which is always argv[0]). That leaves all arguments between 1 - argc as the user supplied arguments for your program. Each will be a string that is contained in the argument vector (which is a pointer to an array of strings you will seen written as char *argv[], or equivalently as a function parameter char **argv) Each of the strings argv[1] to argv[argc-1] are available to you, you simply need to test which argument is which.
这将允许您分离,并使它们可用为命令(cmd),选项(opt)和最后的参数(arg)到您的cmd。
Now it is worth noting, that the rules of your shell (bash, etc..) apply to the arguments passed to your program, word-splitting, pathname and variable expansion apply before your code gets the arguments. So you must consider whether single or more commongly double-quoting will be required around any of your arguments to prevent the normal shell splitting that would otherwise apply (e.g. ls -al my file.txt would results in 4 user-supplied arguments to your code, while ls -al "my file.txt" or ls -al my\ file.txt which would result in the 3 your were expecting.
把所有这些放在一起,您的简短解析可以像下面这样完成。(你也可以自由地做你喜欢的,使用一个开关而不是嵌套的if等…)
#include <stdio.h>
int main (int argc, char **argv) {
char *cmd = NULL, /* here, since you are using the arguments */
*opt = NULL, /* themselves, you can simply use a pointer */
*arg = NULL; /* or the argument itself without a copy */
/* looping using the acutal argument index & vector */
for (int i = 1; i < argc; i++) {
if (*argv[i] != '-') { /* checking if the 1st char is - */
if (!cmd) /* cmd is currently NULL, and */
cmd = argv[i]; /* no '-' it's going to be cmd */
else /* otherwise, cmd has value, so */
arg = argv[i]; /* the value will be opt */
}
else /* here the value has a leading '-', so */
opt = argv[i]; /* it will be the option */
}
printf ("\n cmd : %s\n opt : %s\n arg : %s\n\n",
cmd, opt, arg);
return 0;
}
使用/输出示例
如果你运行代码,你会发现它为参数提供了分离,并提供了单独的指针,以方便它们的使用:
$ ./bin/parse_cmd ls -la ./cs3000
cmd : ls
opt : -la
arg : ./cs3000
(需要注意的是,如果你的任务是构建一个命令字符串,你需要复制多个值来表示opt或arg,那么你不能再简单地使用指针,而需要创建存储,要么通过简单的数组声明而不是指针开始,或者你可以根据需要动态分配存储,例如malloc, calloc和/或realloc。然后,您将有可用的存储空间来复制和连接其中的值。)
如果这是你的挑战,那么在所有这些答案之间,你应该知道如何处理你的问题。如果你必须更进一步,实际上让你的程序执行带有opt和arg的cmd,那么你会想要查看fork来生成一个半独立的进程,在其中运行将执行你的cmd opt和arg,使用类似于execv或execvp的东西。祝你好运,如果你有进一步的问题,请发表评论。
我喜欢C的getopt(),但是我老了。: -)