如何将字节数组转换为十六进制字符串,反之亦然?
当前回答
您可以使用BitConverter.ToString方法:
byte[] bytes = {0, 1, 2, 4, 8, 16, 32, 64, 128, 256}
Console.WriteLine( BitConverter.ToString(bytes));
输出:
00-01-02-04-08-10-20-40-80-FF
更多信息:BitConverter.ToString方法(Byte[])
其他回答
两个mashup,将两个半字节操作合并为一个。
可能非常有效的版本:
public static string ByteArrayToString2(byte[] ba)
{
char[] c = new char[ba.Length * 2];
for( int i = 0; i < ba.Length * 2; ++i)
{
byte b = (byte)((ba[i>>1] >> 4*((i&1)^1)) & 0xF);
c[i] = (char)(55 + b + (((b-10)>>31)&-7));
}
return new string( c );
}
Decadent linq与比特黑客版本:
public static string ByteArrayToString(byte[] ba)
{
return string.Concat( ba.SelectMany( b => new int[] { b >> 4, b & 0xF }).Select( b => (char)(55 + b + (((b-10)>>31)&-7))) );
}
并反转:
public static byte[] HexStringToByteArray( string s )
{
byte[] ab = new byte[s.Length>>1];
for( int i = 0; i < s.Length; i++ )
{
int b = s[i];
b = (b - '0') + ((('9' - b)>>31)&-7);
ab[i>>1] |= (byte)(b << 4*((i&1)^1));
}
return ab;
}
支持最短路径和.net核心:
public static string BytesToString(byte[] ba) =>
ba.Aggregate(new StringBuilder(32), (sb, b) => sb.Append(b.ToString("X2"))).ToString();
.NET 5已添加Convert.ToHexString方法。
对于使用旧版本.NET的用户
internal static class ByteArrayExtensions
{
public static string ToHexString(this byte[] bytes, Casing casing = Casing.Upper)
{
Span<char> result = stackalloc char[0];
if (bytes.Length > 16)
{
var array = new char[bytes.Length * 2];
result = array.AsSpan();
}
else
{
result = stackalloc char[bytes.Length * 2];
}
int pos = 0;
foreach (byte b in bytes)
{
ToCharsBuffer(b, result, pos, casing);
pos += 2;
}
return result.ToString();
}
private static void ToCharsBuffer(byte value, Span<char> buffer, int startingIndex = 0, Casing casing = Casing.Upper)
{
uint difference = (((uint)value & 0xF0U) << 4) + ((uint)value & 0x0FU) - 0x8989U;
uint packedResult = ((((uint)(-(int)difference) & 0x7070U) >> 4) + difference + 0xB9B9U) | (uint)casing;
buffer[startingIndex + 1] = (char)(packedResult & 0xFF);
buffer[startingIndex] = (char)(packedResult >> 8);
}
}
public enum Casing : uint
{
// Output [ '0' .. '9' ] and [ 'A' .. 'F' ].
Upper = 0,
// Output [ '0' .. '9' ] and [ 'a' .. 'f' ].
Lower = 0x2020U,
}
改编自.NET存储库https://github.com/dotnet/runtime/blob/v5.0.3/src/libraries/System.Private.CoreLib/src/System/Convert.cshttps://github.com/dotnet/runtime/blob/v5.0.3/src/libraries/Common/src/System/HexConverter.cs
另一种基于查找表的方法。该方法只为每个字节使用一个查找表,而不是为每个半字节使用查找表。
private static readonly uint[] _lookup32 = CreateLookup32();
private static uint[] CreateLookup32()
{
var result = new uint[256];
for (int i = 0; i < 256; i++)
{
string s=i.ToString("X2");
result[i] = ((uint)s[0]) + ((uint)s[1] << 16);
}
return result;
}
private static string ByteArrayToHexViaLookup32(byte[] bytes)
{
var lookup32 = _lookup32;
var result = new char[bytes.Length * 2];
for (int i = 0; i < bytes.Length; i++)
{
var val = lookup32[bytes[i]];
result[2*i] = (char)val;
result[2*i + 1] = (char) (val >> 16);
}
return new string(result);
}
我还使用查找表中的ushort、struct{char X1,X2}、struct{byte X1,X2}测试了这个变体。
根据编译目标(x86、X64)的不同,它们要么具有大致相同的性能,要么稍慢于此变体。
为了获得更高的性能,其不安全的兄弟:
private static readonly uint[] _lookup32Unsafe = CreateLookup32Unsafe();
private static readonly uint* _lookup32UnsafeP = (uint*)GCHandle.Alloc(_lookup32Unsafe,GCHandleType.Pinned).AddrOfPinnedObject();
private static uint[] CreateLookup32Unsafe()
{
var result = new uint[256];
for (int i = 0; i < 256; i++)
{
string s=i.ToString("X2");
if(BitConverter.IsLittleEndian)
result[i] = ((uint)s[0]) + ((uint)s[1] << 16);
else
result[i] = ((uint)s[1]) + ((uint)s[0] << 16);
}
return result;
}
public static string ByteArrayToHexViaLookup32Unsafe(byte[] bytes)
{
var lookupP = _lookup32UnsafeP;
var result = new char[bytes.Length * 2];
fixed(byte* bytesP = bytes)
fixed (char* resultP = result)
{
uint* resultP2 = (uint*)resultP;
for (int i = 0; i < bytes.Length; i++)
{
resultP2[i] = lookupP[bytesP[i]];
}
}
return new string(result);
}
或者如果您认为可以直接写入字符串:
public static string ByteArrayToHexViaLookup32UnsafeDirect(byte[] bytes)
{
var lookupP = _lookup32UnsafeP;
var result = new string((char)0, bytes.Length * 2);
fixed (byte* bytesP = bytes)
fixed (char* resultP = result)
{
uint* resultP2 = (uint*)resultP;
for (int i = 0; i < bytes.Length; i++)
{
resultP2[i] = lookupP[bytesP[i]];
}
}
return result;
}
这里不想赘述很多答案,但我发现了一个十六进制字符串解析器的相当优化(比公认的好4.5倍)、简单的实现。首先,我的测试输出(第一批是我的实现):
Give me that string:
04c63f7842740c77e545bb0b2ade90b384f119f6ab57b680b7aa575a2f40939f
Time to parse 100,000 times: 50.4192 ms
Result as base64: BMY/eEJ0DHflRbsLKt6Qs4TxGfarV7aAt6pXWi9Ak58=
BitConverter'd: 04-C6-3F-78-42-74-0C-77-E5-45-BB-0B-2A-DE-90-B3-84-F1-19-F6-AB-5
7-B6-80-B7-AA-57-5A-2F-40-93-9F
Accepted answer: (StringToByteArray)
Time to parse 100000 times: 233.1264ms
Result as base64: BMY/eEJ0DHflRbsLKt6Qs4TxGfarV7aAt6pXWi9Ak58=
BitConverter'd: 04-C6-3F-78-42-74-0C-77-E5-45-BB-0B-2A-DE-90-B3-84-F1-19-F6-AB-5
7-B6-80-B7-AA-57-5A-2F-40-93-9F
With Mono's implementation:
Time to parse 100000 times: 777.2544ms
Result as base64: BMY/eEJ0DHflRbsLKt6Qs4TxGfarV7aAt6pXWi9Ak58=
BitConverter'd: 04-C6-3F-78-42-74-0C-77-E5-45-BB-0B-2A-DE-90-B3-84-F1-19-F6-AB-5
7-B6-80-B7-AA-57-5A-2F-40-93-9F
With SoapHexBinary:
Time to parse 100000 times: 845.1456ms
Result as base64: BMY/eEJ0DHflRbsLKt6Qs4TxGfarV7aAt6pXWi9Ak58=
BitConverter'd: 04-C6-3F-78-42-74-0C-77-E5-45-BB-0B-2A-DE-90-B3-84-F1-19-F6-AB-5
7-B6-80-B7-AA-57-5A-2F-40-93-9F
base64和“BitConverter'd”行用于测试正确性。请注意,它们是相等的。
实施:
public static byte[] ToByteArrayFromHex(string hexString)
{
if (hexString.Length % 2 != 0) throw new ArgumentException("String must have an even length");
var array = new byte[hexString.Length / 2];
for (int i = 0; i < hexString.Length; i += 2)
{
array[i/2] = ByteFromTwoChars(hexString[i], hexString[i + 1]);
}
return array;
}
private static byte ByteFromTwoChars(char p, char p_2)
{
byte ret;
if (p <= '9' && p >= '0')
{
ret = (byte) ((p - '0') << 4);
}
else if (p <= 'f' && p >= 'a')
{
ret = (byte) ((p - 'a' + 10) << 4);
}
else if (p <= 'F' && p >= 'A')
{
ret = (byte) ((p - 'A' + 10) << 4);
} else throw new ArgumentException("Char is not a hex digit: " + p,"p");
if (p_2 <= '9' && p_2 >= '0')
{
ret |= (byte) ((p_2 - '0'));
}
else if (p_2 <= 'f' && p_2 >= 'a')
{
ret |= (byte) ((p_2 - 'a' + 10));
}
else if (p_2 <= 'F' && p_2 >= 'A')
{
ret |= (byte) ((p_2 - 'A' + 10));
} else throw new ArgumentException("Char is not a hex digit: " + p_2, "p_2");
return ret;
}
我尝试了一些不安全的东西,并将(显然是冗余的)字符移动到另一个方法来蚕食if序列,但这是最快的。
(我承认这回答了一半的问题。我觉得字符串->字节[]转换不足,而字节[]->字符串角度似乎被很好地覆盖了。因此,这个答案。)