如何将字节数组转换为十六进制字符串,反之亦然?
当前回答
具有扩展支持的基本解决方案
public static class Utils
{
public static byte[] ToBin(this string hex)
{
int NumberChars = hex.Length;
byte[] bytes = new byte[NumberChars / 2];
for (int i = 0; i < NumberChars; i += 2)
bytes[i / 2] = Convert.ToByte(hex.Substring(i, 2), 16);
return bytes;
}
public static string ToHex(this byte[] ba)
{
return BitConverter.ToString(ba).Replace("-", "");
}
}
并像下面那样使用这个类
byte[] arr1 = new byte[] { 1, 2, 3 };
string hex1 = arr1.ToHex();
byte[] arr2 = hex1.ToBin();
其他回答
具有扩展支持的基本解决方案
public static class Utils
{
public static byte[] ToBin(this string hex)
{
int NumberChars = hex.Length;
byte[] bytes = new byte[NumberChars / 2];
for (int i = 0; i < NumberChars; i += 2)
bytes[i / 2] = Convert.ToByte(hex.Substring(i, 2), 16);
return bytes;
}
public static string ToHex(this byte[] ba)
{
return BitConverter.ToString(ba).Replace("-", "");
}
}
并像下面那样使用这个类
byte[] arr1 = new byte[] { 1, 2, 3 };
string hex1 = arr1.ToHex();
byte[] arr2 = hex1.ToBin();
另一种方法是使用stackaloc来降低GC内存压力:
static string ByteToHexBitFiddle(byte[] bytes)
{
var c = stackalloc char[bytes.Length * 2 + 1];
int b;
for (int i = 0; i < bytes.Length; ++i)
{
b = bytes[i] >> 4;
c[i * 2] = (char)(55 + b + (((b - 10) >> 31) & -7));
b = bytes[i] & 0xF;
c[i * 2 + 1] = (char)(55 + b + (((b - 10) >> 31) & -7));
}
c[bytes.Length * 2 ] = '\0';
return new string(c);
}
扩展方法(免责声明:完全未经测试的代码,BTW…):
public static class ByteExtensions
{
public static string ToHexString(this byte[] ba)
{
StringBuilder hex = new StringBuilder(ba.Length * 2);
foreach (byte b in ba)
{
hex.AppendFormat("{0:x2}", b);
}
return hex.ToString();
}
}
使用Tomalak的三种解决方案之一(最后一种是字符串上的扩展方法)。
为了方便以后复制和粘贴,将几个答案合并到一个类中:
/// <summary>
/// Extension methods to quickly convert byte array to string and back.
/// </summary>
public static class HexConverter
{
/// <summary>
/// Map values to hex digits
/// </summary>
private static readonly char[] HexDigits =
{
'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'
};
/// <summary>
/// Map 56 characters between ['0', 'F'] to their hex equivalents, and set invalid characters
/// such that they will overflow byte to fail conversion.
/// </summary>
private static readonly ushort[] HexValues =
{
0x0000, 0x0001, 0x0002, 0x0003, 0x0004, 0x0005, 0x0006, 0x0007, 0x0008, 0x0009, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100,
0x000A, 0x000B, 0x000C, 0x000D, 0x000E, 0x000F, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100,
0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x0100, 0x000A, 0x000B,
0x000C, 0x000D, 0x000E, 0x000F
};
/// <summary>
/// Empty byte array
/// </summary>
private static readonly byte[] Empty = new byte[0];
/// <summary>
/// Convert a byte array to a hexadecimal string.
/// </summary>
/// <param name="bytes">
/// The input byte array.
/// </param>
/// <returns>
/// A string of hexadecimal digits.
/// </returns>
public static string ToHexString(this byte[] bytes)
{
var c = new char[bytes.Length * 2];
for (int i = 0, j = 0; i < bytes.Length; i++)
{
c[j++] = HexDigits[bytes[i] >> 4];
c[j++] = HexDigits[bytes[i] & 0x0F];
}
return new string(c);
}
/// <summary>
/// Parse a string of hexadecimal digits into a byte array.
/// </summary>
/// <param name="hexadecimalString">
/// The hexadecimal string.
/// </param>
/// <returns>
/// The parsed <see cref="byte[]"/> array.
/// </returns>
/// <exception cref="ArgumentException">
/// The input string either contained invalid characters, or was of an odd length.
/// </exception>
public static byte[] ToByteArray(string hexadecimalString)
{
if (!TryParse(hexadecimalString, out var value))
{
throw new ArgumentException("Invalid hexadecimal string", nameof(hexadecimalString));
}
return value;
}
/// <summary>
/// Parse a hexadecimal string to bytes
/// </summary>
/// <param name="hexadecimalString">
/// The hexadecimal string, which must be an even number of characters.
/// </param>
/// <param name="value">
/// The parsed value if successful.
/// </param>
/// <returns>
/// True if successful.
/// </returns>
public static bool TryParse(string hexadecimalString, out byte[] value)
{
if (hexadecimalString.Length == 0)
{
value = Empty;
return true;
}
if (hexadecimalString.Length % 2 != 0)
{
value = Empty;
return false;
}
try
{
value = new byte[hexadecimalString.Length / 2];
for (int i = 0, j = 0; j < hexadecimalString.Length; i++)
{
value[i] = (byte)((HexValues[hexadecimalString[j++] - '0'] << 4)
| HexValues[hexadecimalString[j++] - '0']);
}
return true;
}
catch (OverflowException)
{
value = Empty;
return false;
}
}
}
下面还通过允许本机小写选项扩展了这里的优秀答案,并且还处理null或空输入,并使其成为扩展方法。
/// <summary>
/// Converts the byte array to a hex string very fast. Excellent job
/// with code lightly adapted from 'community wiki' here: https://stackoverflow.com/a/14333437/264031
/// (the function was originally named: ByteToHexBitFiddle). Now allows a native lowerCase option
/// to be input and allows null or empty inputs (null returns null, empty returns empty).
/// </summary>
public static string ToHexString(this byte[] bytes, bool lowerCase = false)
{
if (bytes == null)
return null;
else if (bytes.Length == 0)
return "";
char[] c = new char[bytes.Length * 2];
int b;
int xAddToAlpha = lowerCase ? 87 : 55;
int xAddToDigit = lowerCase ? -39 : -7;
for (int i = 0; i < bytes.Length; i++) {
b = bytes[i] >> 4;
c[i * 2] = (char)(xAddToAlpha + b + (((b - 10) >> 31) & xAddToDigit));
b = bytes[i] & 0xF;
c[i * 2 + 1] = (char)(xAddToAlpha + b + (((b - 10) >> 31) & xAddToDigit));
}
string val = new string(c);
return val;
}
public static string ToHexString(this IEnumerable<byte> bytes, bool lowerCase = false)
{
if (bytes == null)
return null;
byte[] arr = bytes.ToArray();
return arr.ToHexString(lowerCase);
}
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