如何将字节数组转换为十六进制字符串,反之亦然?
当前回答
有一个简单的一行解决方案尚未提及,它将十六进制字符串转换为字节数组(我们不在乎这里的否定解释,因为这无关紧要):
BigInteger.Parse(str, System.Globalization.NumberStyles.HexNumber).ToByteArray().Reverse().ToArray();
其他回答
安全版本:
public static class HexHelper
{
[System.Diagnostics.Contracts.Pure]
public static string ToHex(this byte[] value)
{
if (value == null)
throw new ArgumentNullException("value");
const string hexAlphabet = @"0123456789ABCDEF";
var chars = new char[checked(value.Length * 2)];
unchecked
{
for (int i = 0; i < value.Length; i++)
{
chars[i * 2] = hexAlphabet[value[i] >> 4];
chars[i * 2 + 1] = hexAlphabet[value[i] & 0xF];
}
}
return new string(chars);
}
[System.Diagnostics.Contracts.Pure]
public static byte[] FromHex(this string value)
{
if (value == null)
throw new ArgumentNullException("value");
if (value.Length % 2 != 0)
throw new ArgumentException("Hexadecimal value length must be even.", "value");
unchecked
{
byte[] result = new byte[value.Length / 2];
for (int i = 0; i < result.Length; i++)
{
// 0(48) - 9(57) -> 0 - 9
// A(65) - F(70) -> 10 - 15
int b = value[i * 2]; // High 4 bits.
int val = ((b - '0') + ((('9' - b) >> 31) & -7)) << 4;
b = value[i * 2 + 1]; // Low 4 bits.
val += (b - '0') + ((('9' - b) >> 31) & -7);
result[i] = checked((byte)val);
}
return result;
}
}
}
不安全版本适用于那些喜欢性能且不怕不安全的人。ToHex快35%,FromHex快10%。
public static class HexUnsafeHelper
{
[System.Diagnostics.Contracts.Pure]
public static unsafe string ToHex(this byte[] value)
{
if (value == null)
throw new ArgumentNullException("value");
const string alphabet = @"0123456789ABCDEF";
string result = new string(' ', checked(value.Length * 2));
fixed (char* alphabetPtr = alphabet)
fixed (char* resultPtr = result)
{
char* ptr = resultPtr;
unchecked
{
for (int i = 0; i < value.Length; i++)
{
*ptr++ = *(alphabetPtr + (value[i] >> 4));
*ptr++ = *(alphabetPtr + (value[i] & 0xF));
}
}
}
return result;
}
[System.Diagnostics.Contracts.Pure]
public static unsafe byte[] FromHex(this string value)
{
if (value == null)
throw new ArgumentNullException("value");
if (value.Length % 2 != 0)
throw new ArgumentException("Hexadecimal value length must be even.", "value");
unchecked
{
byte[] result = new byte[value.Length / 2];
fixed (char* valuePtr = value)
{
char* valPtr = valuePtr;
for (int i = 0; i < result.Length; i++)
{
// 0(48) - 9(57) -> 0 - 9
// A(65) - F(70) -> 10 - 15
int b = *valPtr++; // High 4 bits.
int val = ((b - '0') + ((('9' - b) >> 31) & -7)) << 4;
b = *valPtr++; // Low 4 bits.
val += (b - '0') + ((('9' - b) >> 31) & -7);
result[i] = checked((byte)val);
}
}
return result;
}
}
}
顺便提一下对于每次调用的转换函数错误时初始化字母表的基准测试,字母表必须是常量(对于字符串)或静态只读(对于字符[])。然后,基于字母表的字节[]到字符串的转换变得和字节操作版本一样快。
当然,测试必须在Release中编译(带有优化),并关闭调试选项“抑制JIT优化”(如果代码必须可调试,则“仅启用我的代码”也是如此)。
扩展BigInteger方法(Gregory Morse在上面提到过)。我不能评论效率,它使用System.Linq.Reverse(),但它很小而且内置。
// To hex
byte[] bytes = System.Text.Encoding.UTF8.GetBytes("Test String!£");
string hexString = new System.Numerics.BigInteger(bytes.Reverse().ToArray()).ToString("x2");
// From hex
byte[] fromHexBytes = System.Numerics.BigInteger.Parse(hexString, System.Globalization.NumberStyles.HexNumber).ToByteArray().Reverse().ToArray();
// Unit test
CollectionAssert.AreEqual(bytes, fromHexBytes);
我将参加这个比特拨弄比赛,因为我有一个同样使用比特拨弄来解码十六进制的答案。请注意,使用字符数组可能会更快,因为调用StringBuilder方法也需要时间。
public static String ToHex (byte[] data)
{
int dataLength = data.Length;
// pre-create the stringbuilder using the length of the data * 2, precisely enough
StringBuilder sb = new StringBuilder (dataLength * 2);
for (int i = 0; i < dataLength; i++) {
int b = data [i];
// check using calculation over bits to see if first tuple is a letter
// isLetter is zero if it is a digit, 1 if it is a letter
int isLetter = (b >> 7) & ((b >> 6) | (b >> 5)) & 1;
// calculate the code using a multiplication to make up the difference between
// a digit character and an alphanumerical character
int code = '0' + ((b >> 4) & 0xF) + isLetter * ('A' - '9' - 1);
// now append the result, after casting the code point to a character
sb.Append ((Char)code);
// do the same with the lower (less significant) tuple
isLetter = (b >> 3) & ((b >> 2) | (b >> 1)) & 1;
code = '0' + (b & 0xF) + isLetter * ('A' - '9' - 1);
sb.Append ((Char)code);
}
return sb.ToString ();
}
public static byte[] FromHex (String hex)
{
// pre-create the array
int resultLength = hex.Length / 2;
byte[] result = new byte[resultLength];
// set validity = 0 (0 = valid, anything else is not valid)
int validity = 0;
int c, isLetter, value, validDigitStruct, validDigit, validLetterStruct, validLetter;
for (int i = 0, hexOffset = 0; i < resultLength; i++, hexOffset += 2) {
c = hex [hexOffset];
// check using calculation over bits to see if first char is a letter
// isLetter is zero if it is a digit, 1 if it is a letter (upper & lowercase)
isLetter = (c >> 6) & 1;
// calculate the tuple value using a multiplication to make up the difference between
// a digit character and an alphanumerical character
// minus 1 for the fact that the letters are not zero based
value = ((c & 0xF) + isLetter * (-1 + 10)) << 4;
// check validity of all the other bits
validity |= c >> 7; // changed to >>, maybe not OK, use UInt?
validDigitStruct = (c & 0x30) ^ 0x30;
validDigit = ((c & 0x8) >> 3) * (c & 0x6);
validity |= (isLetter ^ 1) * (validDigitStruct | validDigit);
validLetterStruct = c & 0x18;
validLetter = (((c - 1) & 0x4) >> 2) * ((c - 1) & 0x2);
validity |= isLetter * (validLetterStruct | validLetter);
// do the same with the lower (less significant) tuple
c = hex [hexOffset + 1];
isLetter = (c >> 6) & 1;
value ^= (c & 0xF) + isLetter * (-1 + 10);
result [i] = (byte)value;
// check validity of all the other bits
validity |= c >> 7; // changed to >>, maybe not OK, use UInt?
validDigitStruct = (c & 0x30) ^ 0x30;
validDigit = ((c & 0x8) >> 3) * (c & 0x6);
validity |= (isLetter ^ 1) * (validDigitStruct | validDigit);
validLetterStruct = c & 0x18;
validLetter = (((c - 1) & 0x4) >> 2) * ((c - 1) & 0x2);
validity |= isLetter * (validLetterStruct | validLetter);
}
if (validity != 0) {
throw new ArgumentException ("Hexadecimal encoding incorrect for input " + hex);
}
return result;
}
从Java代码转换而来。
具有扩展支持的基本解决方案
public static class Utils
{
public static byte[] ToBin(this string hex)
{
int NumberChars = hex.Length;
byte[] bytes = new byte[NumberChars / 2];
for (int i = 0; i < NumberChars; i += 2)
bytes[i / 2] = Convert.ToByte(hex.Substring(i, 2), 16);
return bytes;
}
public static string ToHex(this byte[] ba)
{
return BitConverter.ToString(ba).Replace("-", "");
}
}
并像下面那样使用这个类
byte[] arr1 = new byte[] { 1, 2, 3 };
string hex1 = arr1.ToHex();
byte[] arr2 = hex1.ToBin();
对于Java 8,我们可以使用Byte.toUnsignedInt
public static String convertBytesToHex(byte[] bytes) {
StringBuilder result = new StringBuilder();
for (byte byt : bytes) {
int decimal = Byte.toUnsignedInt(byt);
String hex = Integer.toHexString(decimal);
result.append(hex);
}
return result.toString();
}
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