我如何获得一个人类可读的文件大小字节缩写使用。net ?
例子: 输入7,326,629,显示6.98 MB
我如何获得一个人类可读的文件大小字节缩写使用。net ?
例子: 输入7,326,629,显示6.98 MB
当前回答
这是我编的,效果很好。
public string[] DetermineDigitalSize(string filename)
{
string[] result = new string[2];
string[] sizes = { "B", "KB", "MB", "GB", "GB" };
double len = new FileInfo(filename).Length;
double adjustedSize = len;
double testSize = 0;
int order = 0;
while (order< sizes.Length-1)
{
testSize = adjustedSize / 1024;
if (testSize >= 1) { adjustedSize = testSize; order++; }
else { break; }
}
result[0] = $"{adjustedSize:f2}";
result[1] = sizes[order];
return result;
}
其他回答
有一个开源项目可以做到这一点,甚至更多。
7.Bits().ToString(); // 7 b
8.Bits().ToString(); // 1 B
(.5).Kilobytes().Humanize(); // 512 B
(1000).Kilobytes().ToString(); // 1000 KB
(1024).Kilobytes().Humanize(); // 1 MB
(.5).Gigabytes().Humanize(); // 512 MB
(1024).Gigabytes().ToString(); // 1 TB
http://humanizr.net/#bytesize
https://github.com/MehdiK/Humanizer
另一种皮肤的方法,没有任何类型的循环和负大小支持(对文件大小增量有意义):
public static class Format
{
static string[] sizeSuffixes = {
"B", "KB", "MB", "GB", "TB", "PB", "EB", "ZB", "YB" };
public static string ByteSize(long size)
{
Debug.Assert(sizeSuffixes.Length > 0);
const string formatTemplate = "{0}{1:0.#} {2}";
if (size == 0)
{
return string.Format(formatTemplate, null, 0, sizeSuffixes[0]);
}
var absSize = Math.Abs((double)size);
var fpPower = Math.Log(absSize, 1000);
var intPower = (int)fpPower;
var iUnit = intPower >= sizeSuffixes.Length
? sizeSuffixes.Length - 1
: intPower;
var normSize = absSize / Math.Pow(1000, iUnit);
return string.Format(
formatTemplate,
size < 0 ? "-" : null, normSize, sizeSuffixes[iUnit]);
}
}
下面是测试套件:
[TestFixture] public class ByteSize
{
[TestCase(0, Result="0 B")]
[TestCase(1, Result = "1 B")]
[TestCase(1000, Result = "1 KB")]
[TestCase(1500000, Result = "1.5 MB")]
[TestCase(-1000, Result = "-1 KB")]
[TestCase(int.MaxValue, Result = "2.1 GB")]
[TestCase(int.MinValue, Result = "-2.1 GB")]
[TestCase(long.MaxValue, Result = "9.2 EB")]
[TestCase(long.MinValue, Result = "-9.2 EB")]
public string Format_byte_size(long size)
{
return Format.ByteSize(size);
}
}
int size = new FileInfo( filePath ).Length / 1024;
string humanKBSize = string.Format( "{0} KB", size );
string humanMBSize = string.Format( "{0} MB", size / 1024 );
string humanGBSize = string.Format( "{0} GB", size / 1024 / 1024 );
又多了一种方法,不管怎样。我喜欢上面提到的@humbads优化解决方案,所以复制了原理,但我实现了一点不同。
我认为它是否应该是一个扩展方法是有争议的(因为不是所有的long都必须是字节大小),但我喜欢它们,当我下次需要它时,我可以在某个地方找到它!
关于单位,我想我从来没有说过“Kibibyte”或“Mebibyte”,虽然我对这种强制而非进化的标准持怀疑态度,但我认为从长远来看,这将避免混淆。
public static class LongExtensions
{
private static readonly long[] numberOfBytesInUnit;
private static readonly Func<long, string>[] bytesToUnitConverters;
static LongExtensions()
{
numberOfBytesInUnit = new long[6]
{
1L << 10, // Bytes in a Kibibyte
1L << 20, // Bytes in a Mebibyte
1L << 30, // Bytes in a Gibibyte
1L << 40, // Bytes in a Tebibyte
1L << 50, // Bytes in a Pebibyte
1L << 60 // Bytes in a Exbibyte
};
// Shift the long (integer) down to 1024 times its number of units, convert to a double (real number),
// then divide to get the final number of units (units will be in the range 1 to 1023.999)
Func<long, int, string> FormatAsProportionOfUnit = (bytes, shift) => (((double)(bytes >> shift)) / 1024).ToString("0.###");
bytesToUnitConverters = new Func<long,string>[7]
{
bytes => bytes.ToString() + " B",
bytes => FormatAsProportionOfUnit(bytes, 0) + " KiB",
bytes => FormatAsProportionOfUnit(bytes, 10) + " MiB",
bytes => FormatAsProportionOfUnit(bytes, 20) + " GiB",
bytes => FormatAsProportionOfUnit(bytes, 30) + " TiB",
bytes => FormatAsProportionOfUnit(bytes, 40) + " PiB",
bytes => FormatAsProportionOfUnit(bytes, 50) + " EiB",
};
}
public static string ToReadableByteSizeString(this long bytes)
{
if (bytes < 0)
return "-" + Math.Abs(bytes).ToReadableByteSizeString();
int counter = 0;
while (counter < numberOfBytesInUnit.Length)
{
if (bytes < numberOfBytesInUnit[counter])
return bytesToUnitConverters[counter](bytes);
counter++;
}
return bytesToUnitConverters[counter](bytes);
}
}
使用日志解决问题....
static String BytesToString(long byteCount)
{
string[] suf = { "B", "KB", "MB", "GB", "TB", "PB", "EB" }; //Longs run out around EB
if (byteCount == 0)
return "0" + suf[0];
long bytes = Math.Abs(byteCount);
int place = Convert.ToInt32(Math.Floor(Math.Log(bytes, 1024)));
double num = Math.Round(bytes / Math.Pow(1024, place), 1);
return (Math.Sign(byteCount) * num).ToString() + suf[place];
}
同样是在c#中,但是转换起来应该很简单。为了便于阅读,我还四舍五入到小数点后1位。
基本上确定以1024为基数的小数位数,然后除以1024^小数位。
以及一些使用和输出的示例:
Console.WriteLine(BytesToString(9223372036854775807)); //Results in 8EB
Console.WriteLine(BytesToString(0)); //Results in 0B
Console.WriteLine(BytesToString(1024)); //Results in 1KB
Console.WriteLine(BytesToString(2000000)); //Results in 1.9MB
Console.WriteLine(BytesToString(-9023372036854775807)); //Results in -7.8EB
编辑: 有人指出我漏了一门数学课。地板,所以我把它合并了。(转换。ToInt32使用舍入,而不是截断,这就是为什么需要使用Floor。)谢谢你的帮助。
Edit2: 有一些关于负大小和0字节大小的注释,所以我更新以处理这些情况。