我如何获得一个人类可读的文件大小字节缩写使用。net ?

例子: 输入7,326,629,显示6.98 MB


当前回答

所有溶液的混合:-)

    /// <summary>
    /// Converts a numeric value into a string that represents the number expressed as a size value in bytes,
    /// kilobytes, megabytes, or gigabytes, depending on the size.
    /// </summary>
    /// <param name="fileSize">The numeric value to be converted.</param>
    /// <returns>The converted string.</returns>
    public static string FormatByteSize(double fileSize)
    {
        FileSizeUnit unit = FileSizeUnit.B;
        while (fileSize >= 1024 && unit < FileSizeUnit.YB)
        {
            fileSize = fileSize / 1024;
            unit++;
        }
        return string.Format("{0:0.##} {1}", fileSize, unit);
    }

    /// <summary>
    /// Converts a numeric value into a string that represents the number expressed as a size value in bytes,
    /// kilobytes, megabytes, or gigabytes, depending on the size.
    /// </summary>
    /// <param name="fileInfo"></param>
    /// <returns>The converted string.</returns>
    public static string FormatByteSize(FileInfo fileInfo)
    {
        return FormatByteSize(fileInfo.Length);
    }
}

public enum FileSizeUnit : byte
{
    B,
    KB,
    MB,
    GB,
    TB,
    PB,
    EB,
    ZB,
    YB
}

其他回答

int size = new FileInfo( filePath ).Length / 1024;
string humanKBSize = string.Format( "{0} KB", size );
string humanMBSize = string.Format( "{0} MB", size / 1024 );
string humanGBSize = string.Format( "{0} GB", size / 1024 / 1024 );

这是我编的,效果很好。

public string[] DetermineDigitalSize(string filename)
        {
            string[] result = new string[2];
            string[] sizes = { "B", "KB", "MB", "GB", "GB" };
            double len = new FileInfo(filename).Length;
             double adjustedSize = len;
            double testSize = 0;
            int order = 0;
            while (order< sizes.Length-1)
            {
                testSize = adjustedSize / 1024;
                if (testSize >= 1) { adjustedSize = testSize; order++; }
                else { break; }
            }
            result[0] = $"{adjustedSize:f2}";
            result[1] = sizes[order];
            return result;
        }

1-liner(加上前缀常量)

const String prefixes = " KMGTPEY";
/// <summary> Returns the human-readable file size for an arbitrary, 64-bit file size. </summary>
public static String HumanSize(UInt64 bytes)
    => Enumerable
    .Range(0, prefixes.Length)
    .Where(i => bytes < 1024U<<(i*10))
    .Select(i => $"{(bytes>>(10*i-10))/1024:0.###} {prefixes[i]}B")
    .First();

或者,如果你想减少LINQ对象的分配,使用相同的for循环变量:

/// <summary>
/// Returns the human-readable file size for an arbitrary, 64-bit file size.
/// </summary>
public static String HumanSize(UInt64 bytes)
{
    const String prefixes = " KMGTPEY";
    for (var i = 0; i < prefixes.Length; i++)
        if (bytes < 1024U<<(i*10))
            return $"{(bytes>>(10*i-10))/1024:0.###} {prefixes[i]}B";

    throw new ArgumentOutOfRangeException(nameof(bytes));
}

这可能不是最有效或最优化的方法,但如果您不熟悉对数数学,它更容易阅读,并且对于大多数情况来说应该足够快。

string[] sizes = { "B", "KB", "MB", "GB", "TB" };
double len = new FileInfo(filename).Length;
int order = 0;
while (len >= 1024 && order < sizes.Length - 1) {
    order++;
    len = len/1024;
}

// Adjust the format string to your preferences. For example "{0:0.#}{1}" would
// show a single decimal place, and no space.
string result = String.Format("{0:0.##} {1}", len, sizes[order]);

又多了一种方法,不管怎样。我喜欢上面提到的@humbads优化解决方案,所以复制了原理,但我实现了一点不同。

我认为它是否应该是一个扩展方法是有争议的(因为不是所有的long都必须是字节大小),但我喜欢它们,当我下次需要它时,我可以在某个地方找到它!

关于单位,我想我从来没有说过“Kibibyte”或“Mebibyte”,虽然我对这种强制而非进化的标准持怀疑态度,但我认为从长远来看,这将避免混淆。

public static class LongExtensions
{
    private static readonly long[] numberOfBytesInUnit;
    private static readonly Func<long, string>[] bytesToUnitConverters;

    static LongExtensions()
    {
        numberOfBytesInUnit = new long[6]    
        {
            1L << 10,    // Bytes in a Kibibyte
            1L << 20,    // Bytes in a Mebibyte
            1L << 30,    // Bytes in a Gibibyte
            1L << 40,    // Bytes in a Tebibyte
            1L << 50,    // Bytes in a Pebibyte
            1L << 60     // Bytes in a Exbibyte
        };

        // Shift the long (integer) down to 1024 times its number of units, convert to a double (real number), 
        // then divide to get the final number of units (units will be in the range 1 to 1023.999)
        Func<long, int, string> FormatAsProportionOfUnit = (bytes, shift) => (((double)(bytes >> shift)) / 1024).ToString("0.###");

        bytesToUnitConverters = new Func<long,string>[7]
        {
            bytes => bytes.ToString() + " B",
            bytes => FormatAsProportionOfUnit(bytes, 0) + " KiB",
            bytes => FormatAsProportionOfUnit(bytes, 10) + " MiB",
            bytes => FormatAsProportionOfUnit(bytes, 20) + " GiB",
            bytes => FormatAsProportionOfUnit(bytes, 30) + " TiB",
            bytes => FormatAsProportionOfUnit(bytes, 40) + " PiB",
            bytes => FormatAsProportionOfUnit(bytes, 50) + " EiB",
        };
    }

    public static string ToReadableByteSizeString(this long bytes)
    {
        if (bytes < 0)
            return "-" + Math.Abs(bytes).ToReadableByteSizeString();

        int counter = 0;
        while (counter < numberOfBytesInUnit.Length)
        {
            if (bytes < numberOfBytesInUnit[counter])
                return bytesToUnitConverters[counter](bytes);
            counter++;
        }
        return bytesToUnitConverters[counter](bytes);
    }
}