是否有一个聪明的(即优化)方法重命名一个关键在javascript对象?
一种非优化的方式是:
o[ new_key ] = o[ old_key ];
delete o[ old_key ];
是否有一个聪明的(即优化)方法重命名一个关键在javascript对象?
一种非优化的方式是:
o[ new_key ] = o[ old_key ];
delete o[ old_key ];
当前回答
如果有人需要重命名属性列表:
function renameKeys(obj, newKeys) {
const keyValues = Object.keys(obj).map(key => {
const newKey = newKeys[key] || key;
return { [newKey]: obj[key] };
});
return Object.assign({}, ...keyValues);
}
用法:
const obj = { a: "1", b: "2" };
const newKeys = { a: "A", c: "C" };
const renamedObj = renameKeys(obj, newKeys);
console.log(renamedObj);
// {A:"1", b:"2"}
其他回答
还有一种最强大的REDUCE方法。
数据= {\ key1:“value1”,key2:“value2”,key3:“value3”}; 键文件夹= {\ key1:“firstkey”,key2:“secondkey”,key3:“thirdkey” mappedData = Object.keys . .还原((obj,k) =>对象。assign(obj, {\ [keyMap]]:数据[k]},{\}; 控制台日志(mappedData); 第一个“value1”、“secondkey”、“value2”、“thirdkey”、“value3”……
const clone = (obj) => Object.assign({}, obj);
const renameKey = (object, key, newKey) => {
const clonedObj = clone(object);
const targetKey = clonedObj[key];
delete clonedObj[key];
clonedObj[newKey] = targetKey;
return clonedObj;
};
let contact = {radiant: 11, dire: 22};
contact = renameKey(contact, 'radiant', 'aplha');
contact = renameKey(contact, 'dire', 'omega');
console.log(contact); // { aplha: 11, omega: 22 };
我的方法,改编好的@Mulhoon typescript帖子,用于更改多个键:
const renameKeys = <
TOldKey extends keyof T,
TNewkey extends string,
T extends Record<string, unknown>
>(
keys: {[ key: string]: TNewkey extends TOldKey ? never : TNewkey },
obj: T
) => Object
.keys(obj)
.reduce((acc, key) => ({
...acc,
...{ [keys[key] || key]: obj[key] }
}), {});
renameKeys({id: 'value', name: 'label'}, {id: 'toto_id', name: 'toto', age: 35});
我只想用ES6(ES2015)的方式!
我们需要跟上时代!
const old_obj = { k1: `111`, k2: `222`, k3: `333` }; console.log(`old_obj =\n`, old_obj); // {k1: "111", k2: "222", k3: "333"} /** * @author xgqfrms * @description ES6 ...spread & Destructuring Assignment */ const { k1: kA, k2: kB, k3: kC, } = {...old_obj} console.log(`kA = ${kA},`, `kB = ${kB},`, `kC = ${kC}\n`); // kA = 111, kB = 222, kC = 333 const new_obj = Object.assign( {}, { kA, kB, kC } ); console.log(`new_obj =\n`, new_obj); // {kA: "111", kB: "222", kC: "333"}
如果你想保持对象的相同顺序
changeObjectKeyName(objectToChange, oldKeyName: string, newKeyName: string){
const otherKeys = cloneDeep(objectToChange);
delete otherKeys[oldKeyName];
const changedKey = objectToChange[oldKeyName];
return {...{[newKeyName] : changedKey} , ...otherKeys};
}
使用方法:
changeObjectKeyName ( {'a' : 1}, 'a', 'A');