重命名对象键的另一种方法:

让我们考虑这个对象:

let obj = {"name": "John", "id": 1, "last_name": "Doe"}

让我们重命名name key为first_name:

let { name: first_name, ...rest } = obj;
obj = { first_name, ...rest }

现在对象是:

{"first_name": "John", "id": 1, "last_name": "Doe"}

下面是创建具有重命名键的新对象的示例。

let x = { id: "checkout", name: "git checkout", description: "checkout repository" };

let renamed = Object.entries(x).reduce((u, [n, v]) => {
  u[`__${n}`] = v;
  return u;
}, {});

我的方法，改编好的@Mulhoon typescript帖子，用于更改多个键:

const renameKeys = <
    TOldKey extends keyof T,
    TNewkey extends string,
    T extends Record<string, unknown>
>(
  keys:  {[ key: string]: TNewkey extends TOldKey ? never : TNewkey },
  obj: T
) => Object
    .keys(obj)
    .reduce((acc, key) => ({
        ...acc,
        ...{ [keys[key] || key]: obj[key] }
    }), {});

renameKeys({id: 'value', name: 'label'}, {id: 'toto_id', name: 'toto', age: 35});

如果有人需要重命名object的键:

const renameKeyObject = （obj， oldKey， newKey） => { 如果 （旧键 === 新键） 返回 volj; Object.keys（obj）.forEach（（key） => { if （key === oldKey） { obj[newKey] = obj[key]; 删除 obj[键]; } else if （obj[key] ！== null &&; typeof obj[key] === “object”） { obj[key] = renameKeyObject（obj[key]， oldKey， newKey）; } }); 返回卷; };

我只想用ES6(ES2015)的方式!

我们需要跟上时代!

const old_obj = { k1: `111`, k2: `222`, k3: `333` }; console.log(`old_obj =\n`, old_obj); // {k1: "111", k2: "222", k3: "333"} /** * @author xgqfrms * @description ES6 ...spread & Destructuring Assignment */ const { k1: kA, k2: kB, k3: kC, } = {...old_obj} console.log(`kA = ${kA},`, `kB = ${kB},`, `kC = ${kC}\n`); // kA = 111, kB = 222, kC = 333 const new_obj = Object.assign( {}, { kA, kB, kC } ); console.log(`new_obj =\n`, new_obj); // {kA: "111", kB: "222", kC: "333"}

使用对象解构和展开运算符的变体:

const old_obj = {
    k1: `111`,
    k2: `222`,
    k3: `333`
};    

// destructuring, with renaming. The variable 'rest' will hold those values not assigned to kA, kB, or kC.
const {
    k1: kA, 
    k2: kB, 
    k3: kC,
    ...rest
} = old_obj;
    

// now create a new object, with the renamed properties kA, kB, kC; 
// spread the remaining original properties in the 'rest' variable
const newObj = {kA, kB, kC, ...rest};

对于一个键，这可以很简单:

const { k1: kA, ...rest } = old_obj;
const new_obj = { kA, ...rest }

你也可能喜欢更“传统”的风格:

const { k1, ...rest } = old_obj
const new_obj = { kA: k1, ...rest}