const clone = (obj) => Object.assign({}, obj);

const renameKey = (object, key, newKey) => {

    const clonedObj = clone(object);
  
    const targetKey = clonedObj[key];
  
  
  
    delete clonedObj[key];
  
    clonedObj[newKey] = targetKey;
  
    return clonedObj;
     };

  let contact = {radiant: 11, dire: 22};





contact = renameKey(contact, 'radiant', 'aplha');

contact = renameKey(contact, 'dire', 'omega');



console.log(contact); // { aplha: 11, omega: 22 };

在我看来，你的方法是最优化的。但你最终会得到重新排序的密钥。新创建的密钥将附加在末尾。我知道你不应该依赖键的顺序，但如果你需要保存它，你将需要遍历所有键并一个接一个地构造新对象，在这个过程中替换有问题的键。

是这样的:

var new_o={};
for (var i in o)
{
   if (i==old_key) new_o[new_key]=o[old_key];
   else new_o[i]=o[i];
}
o=new_o;

在您最喜欢的编辑器中尝试一下

const obj = {1: 'a', 2: 'b', 3: 'c'}

const OLD_KEY = 1
const NEW_KEY = 10

const { [OLD_KEY]: replaceByKey, ...rest } = obj
const new_obj = {
  ...rest,
  [NEW_KEY]: replaceByKey
}

您可以将工作包装在一个函数中，并将其分配给Object原型。也许可以使用流畅的界面样式使多个重命名流动。

Object.prototype.renameProperty = function (oldName, newName) {
     // Do nothing if the names are the same
     if (oldName === newName) {
         return this;
     }
    // Check for the old property name to avoid a ReferenceError in strict mode.
    if (this.hasOwnProperty(oldName)) {
        this[newName] = this[oldName];
        delete this[oldName];
    }
    return this;
};

ECMAScript 5 Specific

我希望语法不是这么复杂，但它肯定是很好的有更多的控制。

Object.defineProperty(
    Object.prototype, 
    'renameProperty',
    {
        writable : false, // Cannot alter this property
        enumerable : false, // Will not show up in a for-in loop.
        configurable : false, // Cannot be deleted via the delete operator
        value : function (oldName, newName) {
            // Do nothing if the names are the same
            if (oldName === newName) {
                return this;
            }
            // Check for the old property name to 
            // avoid a ReferenceError in strict mode.
            if (this.hasOwnProperty(oldName)) {
                this[newName] = this[oldName];
                delete this[oldName];
            }
            return this;
        }
    }
);

如果你想保留迭代顺序(插入的顺序)，这里有一个建议:

const renameObjectKey = (object, oldName, newName) => {

  const updatedObject = {}

  for(let key in object) {
      if (key === oldName) {
          newObject[newName] = object[key]
      } else {
          newObject[key] = object[key]
      }
  }

  object = updatedObject
}

还有一种最强大的REDUCE方法。

数据= {\ key1:“value1”，key2:“value2”，key3:“value3”}; 键文件夹= {\ key1:“firstkey”，key2:“secondkey”，key3:“thirdkey” mappedData = Object.keys . .还原((obj,k) =>对象。assign(obj， {\ [keyMap]]:数据[k]}，{\}; 控制台日志(mappedData); 第一个“value1”、“secondkey”、“value2”、“thirdkey”、“value3”……