只是为了增加这里的噪音，你可以创建一个扩展方法:

public static bool IsWithin(this int value, int minimum, int maximum)
{
    return value >= minimum && value <= maximum;
}

这样你就能做…

int val = 15;

bool foo = val.IsWithin(5,20);

话虽如此，当检查本身只有一行时，这样做似乎是一件愚蠢的事情。

编辑:提供了新的答案。 当我写这个问题的第一个答案时，我刚刚开始使用c#，事后我意识到我的“解决方案”是幼稚和低效的。

我最初的回答是: 我会选择更简单的版本:

' if(Enumerable.Range(1100).Contains(intInQuestion)){…DoStuff;} '

更好的方法

因为我还没有看到任何其他更有效的解决方案(至少根据我的测试)，我将再试一次。

新的和更好的方法，也适用于负范围:

// Returns true if x is in range [min..max], else false 
bool inRange(int x, int min=1, int max=100) => ((x - max)*(x - min) <= 0);

这可以用于正负范围，并且默认为

1 . . 100(包括)并使用x作为数字来检查，然后是由min和max定义的可选范围。

为好的措施添加例子

示例1:

// Returns true if x is in range [min..max], else false 
bool inRange(int x, int min=1, int max=100) => ((x - max)*(x - min) <= 0);

Console.WriteLine(inRange(25));
Console.WriteLine(inRange(1));
Console.WriteLine(inRange(100));
Console.WriteLine(inRange(25, 30, 150));
Console.WriteLine(inRange(-25, -50, 0));

返回:

True
True
True
False
True

示例2: 使用100000个1到150之间的随机整数的列表

// Returns true if x is in range [min..max], else false 
bool inRange(int x, int min=1, int max=100) => ((x - max)*(x - min) <= 0);

// Generate 100000 ints between 1 and 150
var intsToCheck = new List<int>();
var randGen = new Random();
for(int i = 0; i < 100000; ++i){
    intsToCheck.Add(randGen.Next(150) + 1);
}

var counter = 0;
foreach(int n in intsToCheck) {
    if(inRange(n)) ++counter;
}

Console.WriteLine("{0} ints found in range 1..100", counter);

返回:

66660 ints found in range 1..100

Execution Time: 0.016 second(s)

如果你想写更多的代码而不是简单的If，也许你可以: 创建一个名为IsBetween的扩展方法

public static class NumberExtensionMethods
{
    public static bool IsBetween(this long value, long Min, long Max)
    {
        // return (value >= Min && value <= Max);
        if (value >= Min && value <= Max) return true;
        else return false;
    }
}

...

// Checks if this number is between 1 and 100.
long MyNumber = 99;
MessageBox.Show(MyNumber.IsBetween(1, 100).ToString());

Addendum: it's worth noting that in practice you very rarely "just check for equality" (or <, >) in a codebase. (Other than in the most trivial situations.) Purely as an example, any game programmer would use categories something like the following in every project, as a basic matter. Note that in this example it (happens to be) using a function (Mathf.Approximately) which is built in to that environment; in practice you typically have to carefully develop your own concepts of what comparisons means for computer representations of real numbers, for the type of situation you are engineering. (Don't even mention that if you're doing something like, perhaps a controller, a PID controller or the like, the whole issue becomes central and very difficult, it becomes the nature of the project.) BY no means is the OP question here a trivial or unimportant question.

private bool FloatLessThan(float a, float b)
    {
    if ( Mathf.Approximately(a,b) ) return false;
    if (a<b) return true;
    return false;
    }

private bool FloatLessThanZero(float a)
    {
    if ( Mathf.Approximately(a,0f) ) return false;
    if (a<0f) return true;
    return false;
    }

private bool FloatLessThanOrEqualToZero(float a)
    {
    if ( Mathf.Approximately(a,0f) ) return true;
    if (a<0f) return true;
    return false;
    }

if (value > 1 && value < 100)
{
    // do work
}
else
{
    // handle outside of range logic
}

好吧，我会配合的。已经有这么多答案了，但也许还有一些其他新奇的空间:

(显然你根本不用这些)

    var num = 7;
    const int min = 5;
    const int max = 10;
    var inRange = Math.Clamp(num, min, max) == num;

Or

    var num = 7;
    const int min = 5;
    const int max = 10;
    var inRange = num switch { < min => false, > max => false, _ => true };

Or

    var num = 7;
    const int min = 5;
    const int max = 10;
    var inRange = num is >= min and <= max;

好吧，也许你可以用最后一个。

好的，再来一个

    var num = 7;
    const int min = 5;
    const int max = 10;
    var inRange = Enumerable.Range(min, max-min).Contains(num);

优雅是因为它不需要确定两个边界值中哪个先大。它也不包含分支。

public static bool InRange(float val, float a, float b)
{
    // Determine if val lies between a and b without first asking which is larger (a or b)
    return ( a <= val & val < b ) | ( b <= val & val < a );
}