感谢“Darin Dimitrov”，这是扩展方法。

 public static partial class Ext
{
    public static Uri GetUriWithparameters(this Uri uri,Dictionary<string,string> queryParams = null,int port = -1)
    {
        var builder = new UriBuilder(uri);
        builder.Port = port;
        if(null != queryParams && 0 < queryParams.Count)
        {
            var query = HttpUtility.ParseQueryString(builder.Query);
            foreach(var item in queryParams)
            {
                query[item.Key] = item.Value;
            }
            builder.Query = query.ToString();
        }
        return builder.Uri;
    }

    public static string GetUriWithparameters(string uri,Dictionary<string,string> queryParams = null,int port = -1)
    {
        var builder = new UriBuilder(uri);
        builder.Port = port;
        if(null != queryParams && 0 < queryParams.Count)
        {
            var query = HttpUtility.ParseQueryString(builder.Query);
            foreach(var item in queryParams)
            {
                query[item.Key] = item.Value;
            }
            builder.Query = query.ToString();
        }
        return builder.Uri.ToString();
    }
}

避免taras中描述的双重编码问题。roshko的答案，并保持容易使用查询参数的可能性，你可以使用uriBuilder.Uri.ParseQueryString()而不是HttpUtility.ParseQueryString()。

您可能想看看Flurl[披露:我是作者]，这是一个流畅的URL构建器，带有可选的配套库，可以将其扩展为一个成熟的REST客户机。

var result = await "https://api.com"
    // basic URL building:
    .AppendPathSegment("endpoint")
    .SetQueryParams(new {
        api_key = ConfigurationManager.AppSettings["SomeApiKey"],
        max_results = 20,
        q = "Don't worry, I'll get encoded!"
    })
    .SetQueryParams(myDictionary)
    .SetQueryParam("q", "overwrite q!")

    // extensions provided by Flurl.Http:
    .WithOAuthBearerToken("token")
    .GetJsonAsync<TResult>();

查看文档了解更多细节。完整的软件包在NuGet上可用:

PM>安装包Flurl。Http

或者只是独立的URL构建器:

PM>安装包Flurl

由于我必须重用这几次，所以我提出了这个类，它只是帮助抽象查询字符串是如何组成的。

public class UriBuilderExt
{
    private NameValueCollection collection;
    private UriBuilder builder;

    public UriBuilderExt(string uri)
    {
        builder = new UriBuilder(uri);
        collection = System.Web.HttpUtility.ParseQueryString(string.Empty);
    }

    public void AddParameter(string key, string value) {
        collection.Add(key, value);
    }

    public Uri Uri{
        get
        {
            builder.Query = collection.ToString();
            return builder.Uri;
        }
    }

}

使用将被简化成这样:

var builder = new UriBuilderExt("http://example.com/");
builder.AddParameter("foo", "bar<>&-baz");
builder.AddParameter("bar", "second");
var uri = builder.Uri;

将返回uri: http://example.com/?foo=bar%3c%3e%26-baz&bar=second

与罗斯托夫的帖子一样，如果你不想包含对系统的引用。在你的项目中，你可以使用System.Net.Http.Formatting中的FormDataCollection，然后做如下的事情:

使用System.Net.Http.Formatting.FormDataCollection

var parameters = new Dictionary<string, string>()
{
    { "ham", "Glaced?" },
    { "x-men", "Wolverine + Logan" },
    { "Time", DateTime.UtcNow.ToString() },
}; 
var query = new FormDataCollection(parameters).ReadAsNameValueCollection().ToString();

或者简单地使用我的Uri扩展

Code

public static Uri AttachParameters(this Uri uri, NameValueCollection parameters)
{
    var stringBuilder = new StringBuilder();
    string str = "?";
    for (int index = 0; index < parameters.Count; ++index)
    {
        stringBuilder.Append(str + parameters.AllKeys[index] + "=" + parameters[index]);
        str = "&";
    }
    return new Uri(uri + stringBuilder.ToString());
}

使用

Uri uri = new Uri("http://www.example.com/index.php").AttachParameters(new NameValueCollection
                                                                           {
                                                                               {"Bill", "Gates"},
                                                                               {"Steve", "Jobs"}
                                                                           });

结果

http://www.example.com/index.php?Bill=Gates&Steve=Jobs