或者简单地使用我的Uri扩展

Code

public static Uri AttachParameters(this Uri uri, NameValueCollection parameters)
{
    var stringBuilder = new StringBuilder();
    string str = "?";
    for (int index = 0; index < parameters.Count; ++index)
    {
        stringBuilder.Append(str + parameters.AllKeys[index] + "=" + parameters[index]);
        str = "&";
    }
    return new Uri(uri + stringBuilder.ToString());
}

使用

Uri uri = new Uri("http://www.example.com/index.php").AttachParameters(new NameValueCollection
                                                                           {
                                                                               {"Bill", "Gates"},
                                                                               {"Steve", "Jobs"}
                                                                           });

结果

http://www.example.com/index.php?Bill=Gates&Steve=Jobs

Darin提供了一个有趣而聪明的解决方案，这里有一些可能是另一个选择:

public class ParameterCollection
{
    private Dictionary<string, string> _parms = new Dictionary<string, string>();

    public void Add(string key, string val)
    {
        if (_parms.ContainsKey(key))
        {
            throw new InvalidOperationException(string.Format("The key {0} already exists.", key));
        }
        _parms.Add(key, val);
    }

    public override string ToString()
    {
        var server = HttpContext.Current.Server;
        var sb = new StringBuilder();
        foreach (var kvp in _parms)
        {
            if (sb.Length > 0) { sb.Append("&"); }
            sb.AppendFormat("{0}={1}",
                server.UrlEncode(kvp.Key),
                server.UrlEncode(kvp.Value));
        }
        return sb.ToString();
    }
}

所以当你使用它时，你可以这样做:

var parms = new ParameterCollection();
parms.Add("key", "value");

var url = ...
url += "?" + parms;

由于我必须重用这几次，所以我提出了这个类，它只是帮助抽象查询字符串是如何组成的。

public class UriBuilderExt
{
    private NameValueCollection collection;
    private UriBuilder builder;

    public UriBuilderExt(string uri)
    {
        builder = new UriBuilder(uri);
        collection = System.Web.HttpUtility.ParseQueryString(string.Empty);
    }

    public void AddParameter(string key, string value) {
        collection.Add(key, value);
    }

    public Uri Uri{
        get
        {
            builder.Query = collection.ToString();
            return builder.Uri;
        }
    }

}

使用将被简化成这样:

var builder = new UriBuilderExt("http://example.com/");
builder.AddParameter("foo", "bar<>&-baz");
builder.AddParameter("bar", "second");
var uri = builder.Uri;

将返回uri: http://example.com/?foo=bar%3c%3e%26-baz&bar=second

避免taras中描述的双重编码问题。roshko的答案，并保持容易使用查询参数的可能性，你可以使用uriBuilder.Uri.ParseQueryString()而不是HttpUtility.ParseQueryString()。

我找不到比创建一个扩展方法来将Dictionary转换为QueryStringFormat更好的解决方案。Waleed A.K.提出的解决方案也不错。

遵循我的解决方案:

创建扩展方法:

public static class DictionaryExt
{
    public static string ToQueryString<TKey, TValue>(this Dictionary<TKey, TValue> dictionary)
    {
        return ToQueryString<TKey, TValue>(dictionary, "?");
    }

    public static string ToQueryString<TKey, TValue>(this Dictionary<TKey, TValue> dictionary, string startupDelimiter)
    {
        string result = string.Empty;
        foreach (var item in dictionary)
        {
            if (string.IsNullOrEmpty(result))
                result += startupDelimiter; // "?";
            else
                result += "&";

            result += string.Format("{0}={1}", item.Key, item.Value);
        }
        return result;
    }
}

和他们:

var param = new Dictionary<string, string>
          {
            { "param1", "value1" },
            { "param2", "value2" },
          };
param.ToQueryString(); //By default will add (?) question mark at begining
//"?param1=value1&param2=value2"
param.ToQueryString("&"); //Will add (&)
//"&param1=value1&param2=value2"
param.ToQueryString(""); //Won't add anything
//"param1=value1&param2=value2"

接受答案的好部分，修改为使用UriBuilder.Uri.ParseQueryString()而不是HttpUtility.ParseQueryString():

var builder = new UriBuilder("http://example.com");
var query = builder.Uri.ParseQueryString();
query["foo"] = "bar<>&-baz";
query["bar"] = "bazinga";
builder.Query = query.ToString();
string url = builder.ToString();