如果我想使用System.Net.HttpClient提交一个http get请求 似乎没有API来添加参数，这是正确的吗?

Yes.

是否有任何简单的api可用来构建查询字符串 不涉及构建名称值集合和url编码 然后最后把它们连接起来?

肯定的:

var query = HttpUtility.ParseQueryString(string.Empty);
query["foo"] = "bar<>&-baz";
query["bar"] = "bazinga";
string queryString = query.ToString();

会给你预期的结果:

foo=bar%3c%3e%26-baz&bar=bazinga

你可能还会发现UriBuilder类很有用:

var builder = new UriBuilder("http://example.com");
builder.Port = -1;
var query = HttpUtility.ParseQueryString(builder.Query);
query["foo"] = "bar<>&-baz";
query["bar"] = "bazinga";
builder.Query = query.ToString();
string url = builder.ToString();

会给你预期的结果:

http://example.com/?foo=bar%3c%3e%26-baz&bar=bazinga

你可以非常安全地将它提供给HttpClient。GetAsync方法。

接受答案的好部分，修改为使用UriBuilder.Uri.ParseQueryString()而不是HttpUtility.ParseQueryString():

var builder = new UriBuilder("http://example.com");
var query = builder.Uri.ParseQueryString();
query["foo"] = "bar<>&-baz";
query["bar"] = "bazinga";
builder.Query = query.ToString();
string url = builder.ToString();

HttpClient client = new HttpClient();
var uri = Environment.GetEnvironmentVariable("URL of Api");
                
var requesturi = QueryHelpers.AddQueryString(uri, "parameter_name",parameter_value);
client.BaseAddress = new Uri(requesturi);

然后你也可以添加请求头例如:

client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
client.DefaultRequestHeaders.Add("x-api-key", secretValue);

响应语法eg:

HttpResponseMessage response = client.GetAsync(requesturi).Result;

希望它对你有用。

感谢“Darin Dimitrov”，这是扩展方法。

 public static partial class Ext
{
    public static Uri GetUriWithparameters(this Uri uri,Dictionary<string,string> queryParams = null,int port = -1)
    {
        var builder = new UriBuilder(uri);
        builder.Port = port;
        if(null != queryParams && 0 < queryParams.Count)
        {
            var query = HttpUtility.ParseQueryString(builder.Query);
            foreach(var item in queryParams)
            {
                query[item.Key] = item.Value;
            }
            builder.Query = query.ToString();
        }
        return builder.Uri;
    }

    public static string GetUriWithparameters(string uri,Dictionary<string,string> queryParams = null,int port = -1)
    {
        var builder = new UriBuilder(uri);
        builder.Port = port;
        if(null != queryParams && 0 < queryParams.Count)
        {
            var query = HttpUtility.ParseQueryString(builder.Query);
            foreach(var item in queryParams)
            {
                query[item.Key] = item.Value;
            }
            builder.Query = query.ToString();
        }
        return builder.Uri.ToString();
    }
}

我正在开发的RFC 6570 URI Template库能够执行此操作。所有编码都按照RFC为您处理。在撰写本文时，beta版本已经可用，它不是稳定的1.0版本的唯一原因是文档没有完全满足我的期望(参见问题#17、#18、#32、#43)。

你可以单独构建一个查询字符串:

UriTemplate template = new UriTemplate("{?params*}");
var parameters = new Dictionary<string, string>
  {
    { "param1", "value1" },
    { "param2", "value2" },
  };
Uri relativeUri = template.BindByName(parameters);

或者你可以构建一个完整的URI:

UriTemplate template = new UriTemplate("path/to/item{?params*}");
var parameters = new Dictionary<string, string>
  {
    { "param1", "value1" },
    { "param2", "value2" },
  };
Uri baseAddress = new Uri("http://www.example.com");
Uri relativeUri = template.BindByName(baseAddress, parameters);

您可能想看看Flurl[披露:我是作者]，这是一个流畅的URL构建器，带有可选的配套库，可以将其扩展为一个成熟的REST客户机。

var result = await "https://api.com"
    // basic URL building:
    .AppendPathSegment("endpoint")
    .SetQueryParams(new {
        api_key = ConfigurationManager.AppSettings["SomeApiKey"],
        max_results = 20,
        q = "Don't worry, I'll get encoded!"
    })
    .SetQueryParams(myDictionary)
    .SetQueryParam("q", "overwrite q!")

    // extensions provided by Flurl.Http:
    .WithOAuthBearerToken("token")
    .GetJsonAsync<TResult>();

查看文档了解更多细节。完整的软件包在NuGet上可用:

PM>安装包Flurl。Http

或者只是独立的URL构建器:

PM>安装包Flurl