避免taras中描述的双重编码问题。roshko的答案，并保持容易使用查询参数的可能性，你可以使用uriBuilder.Uri.ParseQueryString()而不是HttpUtility.ParseQueryString()。

我正在开发的RFC 6570 URI Template库能够执行此操作。所有编码都按照RFC为您处理。在撰写本文时，beta版本已经可用，它不是稳定的1.0版本的唯一原因是文档没有完全满足我的期望(参见问题#17、#18、#32、#43)。

你可以单独构建一个查询字符串:

UriTemplate template = new UriTemplate("{?params*}");
var parameters = new Dictionary<string, string>
  {
    { "param1", "value1" },
    { "param2", "value2" },
  };
Uri relativeUri = template.BindByName(parameters);

或者你可以构建一个完整的URI:

UriTemplate template = new UriTemplate("path/to/item{?params*}");
var parameters = new Dictionary<string, string>
  {
    { "param1", "value1" },
    { "param2", "value2" },
  };
Uri baseAddress = new Uri("http://www.example.com");
Uri relativeUri = template.BindByName(baseAddress, parameters);

Darin提供了一个有趣而聪明的解决方案，这里有一些可能是另一个选择:

public class ParameterCollection
{
    private Dictionary<string, string> _parms = new Dictionary<string, string>();

    public void Add(string key, string val)
    {
        if (_parms.ContainsKey(key))
        {
            throw new InvalidOperationException(string.Format("The key {0} already exists.", key));
        }
        _parms.Add(key, val);
    }

    public override string ToString()
    {
        var server = HttpContext.Current.Server;
        var sb = new StringBuilder();
        foreach (var kvp in _parms)
        {
            if (sb.Length > 0) { sb.Append("&"); }
            sb.AppendFormat("{0}={1}",
                server.UrlEncode(kvp.Key),
                server.UrlEncode(kvp.Value));
        }
        return sb.ToString();
    }
}

所以当你使用它时，你可以这样做:

var parms = new ParameterCollection();
parms.Add("key", "value");

var url = ...
url += "?" + parms;

接受答案的好部分，修改为使用UriBuilder.Uri.ParseQueryString()而不是HttpUtility.ParseQueryString():

var builder = new UriBuilder("http://example.com");
var query = builder.Uri.ParseQueryString();
query["foo"] = "bar<>&-baz";
query["bar"] = "bazinga";
builder.Query = query.ToString();
string url = builder.ToString();

我找不到比创建一个扩展方法来将Dictionary转换为QueryStringFormat更好的解决方案。Waleed A.K.提出的解决方案也不错。

遵循我的解决方案:

创建扩展方法:

public static class DictionaryExt
{
    public static string ToQueryString<TKey, TValue>(this Dictionary<TKey, TValue> dictionary)
    {
        return ToQueryString<TKey, TValue>(dictionary, "?");
    }

    public static string ToQueryString<TKey, TValue>(this Dictionary<TKey, TValue> dictionary, string startupDelimiter)
    {
        string result = string.Empty;
        foreach (var item in dictionary)
        {
            if (string.IsNullOrEmpty(result))
                result += startupDelimiter; // "?";
            else
                result += "&";

            result += string.Format("{0}={1}", item.Key, item.Value);
        }
        return result;
    }
}

和他们:

var param = new Dictionary<string, string>
          {
            { "param1", "value1" },
            { "param2", "value2" },
          };
param.ToQueryString(); //By default will add (?) question mark at begining
//"?param1=value1&param2=value2"
param.ToQueryString("&"); //Will add (&)
//"&param1=value1&param2=value2"
param.ToQueryString(""); //Won't add anything
//"param1=value1&param2=value2"

感谢“Darin Dimitrov”，这是扩展方法。

 public static partial class Ext
{
    public static Uri GetUriWithparameters(this Uri uri,Dictionary<string,string> queryParams = null,int port = -1)
    {
        var builder = new UriBuilder(uri);
        builder.Port = port;
        if(null != queryParams && 0 < queryParams.Count)
        {
            var query = HttpUtility.ParseQueryString(builder.Query);
            foreach(var item in queryParams)
            {
                query[item.Key] = item.Value;
            }
            builder.Query = query.ToString();
        }
        return builder.Uri;
    }

    public static string GetUriWithparameters(string uri,Dictionary<string,string> queryParams = null,int port = -1)
    {
        var builder = new UriBuilder(uri);
        builder.Port = port;
        if(null != queryParams && 0 < queryParams.Count)
        {
            var query = HttpUtility.ParseQueryString(builder.Query);
            foreach(var item in queryParams)
            {
                query[item.Key] = item.Value;
            }
            builder.Query = query.ToString();
        }
        return builder.Uri.ToString();
    }
}