有人能告诉我是否有一种方法可以用泛型将泛型类型参数T限制为:

Int16 Int32 Int64 UInt16 UInt32 UInt64

我知道哪里关键字,但不能找到只有这些类型的接口,

喜欢的东西:

static bool IntegerFunction<T>(T value) where T : INumeric 

当前回答

. net数字基元类型不共享任何允许它们用于计算的公共接口。可以定义自己的接口(例如ISignedWholeNumber)来执行这样的操作,定义包含单个Int16、Int32等的结构并实现这些接口,然后有方法接受受ISignedWholeNumber约束的泛型类型,但是必须将数值转换为你的结构类型可能是一个麻烦。

An alternative approach would be to define static class Int64Converter<T> with a static property bool Available {get;}; and static delegates for Int64 GetInt64(T value), T FromInt64(Int64 value), bool TryStoreInt64(Int64 value, ref T dest). The class constructor could use be hard-coded to load delegates for known types, and possibly use Reflection to test whether type T implements methods with the proper names and signatures (in case it's something like a struct which contains an Int64 and represents a number, but has a custom ToString() method). This approach would lose the advantages associated with compile-time type-checking, but would still manage to avoid boxing operations and each type would only have to be "checked" once. After that, operations associated with that type would be replaced with a delegate dispatch.

其他回答

我会使用一个通用的,你可以处理外部…

/// <summary>
/// Generic object copy of the same type
/// </summary>
/// <typeparam name="T">The type of object to copy</typeparam>
/// <param name="ObjectSource">The source object to copy</param>
public T CopyObject<T>(T ObjectSource)
{
    T NewObject = System.Activator.CreateInstance<T>();

    foreach (PropertyInfo p in ObjectSource.GetType().GetProperties())
        NewObject.GetType().GetProperty(p.Name).SetValue(NewObject, p.GetValue(ObjectSource, null), null);

    return NewObject;
}

我想知道和samjudson一样,为什么只对整数有效?如果是这样的话,你可能想要创建一个helper类或者类似的东西来保存你想要的所有类型。

如果你想要的只是整数,不要使用泛型,那不是泛型;或者更好的是,通过检查其类型来拒绝任何其他类型。

这个约束存在于。net 7中。

查看这篇。net博客文章和实际文档。

从。net 7开始,你可以使用接口如INumber和IFloatingPoint来创建程序,例如:

using System.Numerics;

Console.WriteLine(Sum(1, 2, 3, 4, 5));
Console.WriteLine(Sum(10.541, 2.645));
Console.WriteLine(Sum(1.55f, 5, 9.41f, 7));

static T Sum<T>(params T[] numbers) where T : INumber<T>
{
    T result = T.Zero;

    foreach (T item in numbers)
    {
        result += item;
    }

    return result;
}

innumber在系统中。数字名称空间。

还有诸如IAdditionOperators和IComparisonOperators这样的接口,因此您可以通用地使用特定的操作符。

使用策略的解决方案:

interface INumericPolicy<T>
{
    T Zero();
    T Add(T a, T b);
    // add more functions here, such as multiplication etc.
}

struct NumericPolicies:
    INumericPolicy<int>,
    INumericPolicy<long>
    // add more INumericPolicy<> for different numeric types.
{
    int INumericPolicy<int>.Zero() { return 0; }
    long INumericPolicy<long>.Zero() { return 0; }
    int INumericPolicy<int>.Add(int a, int b) { return a + b; }
    long INumericPolicy<long>.Add(long a, long b) { return a + b; }
    // implement all functions from INumericPolicy<> interfaces.

    public static NumericPolicies Instance = new NumericPolicies();
}

算法:

static class Algorithms
{
    public static T Sum<P, T>(this P p, params T[] a)
        where P: INumericPolicy<T>
    {
        var r = p.Zero();
        foreach(var i in a)
        {
            r = p.Add(r, i);
        }
        return r;
    }

}

用法:

int i = NumericPolicies.Instance.Sum(1, 2, 3, 4, 5);
long l = NumericPolicies.Instance.Sum(1L, 2, 3, 4, 5);
NumericPolicies.Instance.Sum("www", "") // compile-time error.

该解决方案是编译时安全的。CityLizard框架提供了。net 4.0的编译版本。文件名为“lib/NETFramework4.0/ citylizad . policy .dll”。

它也可以在Nuget: https://www.nuget.org/packages/CityLizard/。参见CityLizard.Policy.I结构。

没有办法将模板限制为类型,但是可以根据类型定义不同的操作。作为泛型数值包的一部分,我需要一个泛型类来添加两个值。

    class Something<TCell>
    {
        internal static TCell Sum(TCell first, TCell second)
        {
            if (typeof(TCell) == typeof(int))
                return (TCell)((object)(((int)((object)first)) + ((int)((object)second))));

            if (typeof(TCell) == typeof(double))
                return (TCell)((object)(((double)((object)first)) + ((double)((object)second))));

            return second;
        }
    }

请注意,typeofs是在编译时计算的,因此if语句将被编译器删除。编译器还会删除虚假的类型转换。因此,在编译器中会解析为

        internal static int Sum(int first, int second)
        {
            return first + second;
        }