如何迭代由空格分隔的单词组成的字符串中的单词?

注意,我对C字符串函数或那种字符操作/访问不感兴趣。比起效率,我更喜欢优雅。我当前的解决方案:

#include <iostream>
#include <sstream>
#include <string>

using namespace std;

int main() {
    string s = "Somewhere down the road";
    istringstream iss(s);

    do {
        string subs;
        iss >> subs;
        cout << "Substring: " << subs << endl;
    } while (iss);
}

当前回答

这是我解决这个问题的方法:

vector<string> get_tokens(string str) {
    vector<string> dt;
    stringstream ss;
    string tmp; 
    ss << str;
    for (size_t i; !ss.eof(); ++i) {
        ss >> tmp;
        dt.push_back(tmp);
    }
    return dt;
}

此函数返回字符串向量。

其他回答

#include <iostream>
#include <string>
#include <sstream>
#include <algorithm>
#include <iterator>
#include <vector>

int main() {
    using namespace std;
   int n=8;
    string sentence = "10 20 30 40 5 6 7 8";
    istringstream iss(sentence);

  vector<string> tokens;
copy(istream_iterator<string>(iss),
     istream_iterator<string>(),
     back_inserter(tokens));

     for(int i=0;i<n;i++){
        cout<<tokens.at(i);
     }


}
#include <iostream>
#include <string>
#include <deque>

std::deque<std::string> split(
    const std::string& line, 
    std::string::value_type delimiter,
    bool skipEmpty = false
) {
    std::deque<std::string> parts{};

    if (!skipEmpty && !line.empty() && delimiter == line.at(0)) {
        parts.push_back({});
    }

    for (const std::string::value_type& c : line) {
        if (
            (
                c == delimiter 
                &&
                (skipEmpty ? (!parts.empty() && !parts.back().empty()) : true)
            )
            ||
            (c != delimiter && parts.empty())
        ) {
            parts.push_back({});
        }

        if (c != delimiter) {
            parts.back().push_back(c);
        }
    }

    if (skipEmpty && !parts.empty() && parts.back().empty()) {
        parts.pop_back();
    }

    return parts;
}

void test(const std::string& line) {
    std::cout << line << std::endl;

    std::cout << "skipEmpty=0 |";
    for (const std::string& part : split(line, ':')) {
        std::cout << part << '|';
    }
    std::cout << std::endl;

    std::cout << "skipEmpty=1 |";
    for (const std::string& part : split(line, ':', true)) {
        std::cout << part << '|';
    }
    std::cout << std::endl;

    std::cout << std::endl;
}

int main() {
    test("foo:bar:::baz");
    test("");
    test("foo");
    test(":");
    test("::");
    test(":foo");
    test("::foo");
    test(":foo:");
    test(":foo::");

    return 0;
}

输出:

foo:bar:::baz
skipEmpty=0 |foo|bar|||baz|
skipEmpty=1 |foo|bar|baz|


skipEmpty=0 |
skipEmpty=1 |

foo
skipEmpty=0 |foo|
skipEmpty=1 |foo|

:
skipEmpty=0 |||
skipEmpty=1 |

::
skipEmpty=0 ||||
skipEmpty=1 |

:foo
skipEmpty=0 ||foo|
skipEmpty=1 |foo|

::foo
skipEmpty=0 |||foo|
skipEmpty=1 |foo|

:foo:
skipEmpty=0 ||foo||
skipEmpty=1 |foo|

:foo::
skipEmpty=0 ||foo|||
skipEmpty=1 |foo|

我无法相信这些答案有多复杂。为什么没有人提出这么简单的建议?

#include <iostream>
#include <sstream>

std::string input = "This is a sentence to read";
std::istringstream ss(input);
std::string token;

while(std::getline(ss, token, ' ')) {
    std::cout << token << endl;
}

有一种更简单的方法可以做到这一点!!

#include <vector>
#include <string>
std::vector<std::string> splitby(std::string string, char splitter) {
    int splits = 0;
    std::vector<std::string> result = {};
    std::string locresult = "";
    for (unsigned int i = 0; i < string.size(); i++) {
        if ((char)string.at(i) != splitter) {
            locresult += string.at(i);
        }
        else {
            result.push_back(locresult);
            locresult = "";
        }
    }
    if (splits == 0) {
        result.push_back(locresult);
    }
    return result;
}

void printvector(std::vector<std::string> v) {
    std::cout << '{';
    for (unsigned int i = 0; i < v.size(); i++) {
        if (i < v.size() - 1) {
            std::cout << '"' << v.at(i) << "\",";
        }
        else {
            std::cout << '"' << v.at(i) << "\"";
        }
    }
    std::cout << "}\n";
}

作为一个业余爱好者,这是我想到的第一个解决方案。我有点好奇,为什么我还没有在这里看到类似的解决方案,是不是我的做法有根本问题?

#include <iostream>
#include <string>
#include <vector>

std::vector<std::string> split(const std::string &s, const std::string &delims)
{
    std::vector<std::string> result;
    std::string::size_type pos = 0;
    while (std::string::npos != (pos = s.find_first_not_of(delims, pos))) {
        auto pos2 = s.find_first_of(delims, pos);
        result.emplace_back(s.substr(pos, std::string::npos == pos2 ? pos2 : pos2 - pos));
        pos = pos2;
    }
    return result;
}

int main()
{
    std::string text{"And then I said: \"I don't get it, why would you even do that!?\""};
    std::string delims{" :;\".,?!"};
    auto words = split(text, delims);
    std::cout << "\nSentence:\n  " << text << "\n\nWords:";
    for (const auto &w : words) {
        std::cout << "\n  " << w;
    }
    return 0;
}

http://cpp.sh/7wmzy