我尝试着创造一款带有骰子的游戏，我需要在其中添加一些随机数字(游戏邦注:即模拟骰子的边缘)。我知道如何在1到6之间
#include <cstdlib>
#include <ctime>
#include <iostream>
using namespace std;
int main()
{
srand((unsigned)time(0));
int i;
i = (rand()%6)+1;
cout << i << "\n";
}
并不是很好地工作，因为当我运行程序几次，这是我得到的输出:
6
1
1
1
1
1
2
2
2
2
5
2
所以我想要一个每次生成不同随机数的命令，而不是连续5次生成相同的随机数。是否有这样的命令?
当前回答
这是一个简单的随机生成器。在0附近产生正负值的概率相等:
int getNextRandom(const size_t lim)
{
int nextRand = rand() % lim;
int nextSign = rand() % lim;
if (nextSign < lim / 2)
return -nextRand;
return nextRand;
}
int main()
{
srand(time(NULL));
int r = getNextRandom(100);
cout << r << endl;
return 0;
}
其他回答
这里有一个解决方案。创建一个返回随机数的函数并放置它 在main函数之外，使其具有全局性。希望这能有所帮助
#include <iostream>
#include <cstdlib>
#include <ctime>
int rollDie();
using std::cout;
int main (){
srand((unsigned)time(0));
int die1;
int die2;
for (int n=10; n>0; n--){
die1 = rollDie();
die2 = rollDie();
cout << die1 << " + " << die2 << " = " << die1 + die2 << "\n";
}
system("pause");
return 0;
}
int rollDie(){
return (rand()%6)+1;
}
#include <iostream>
#include <cstdlib>
#include <ctime>
int main() {
srand(time(NULL));
int random_number = std::rand(); // rand() return a number between 0 and RAND_MAX
std::cout << random_number;
return 0;
}
http://en.cppreference.com/w/cpp/numeric/random/rand
以下是我的5美分:
// System includes
#include <iostream>
#include <algorithm>
#include <chrono>
#include <random>
// Application includes
// Namespace
using namespace std;
// Constants
#define A_UNUSED(inVariable) (void)inVariable;
int main(int inCounter, char* inArguments[]) {
A_UNUSED(inCounter);
A_UNUSED(inArguments);
std::random_device oRandomDevice;
mt19937_64 oNumber;
std::mt19937_64::result_type oSeed;
std::mt19937_64::result_type oValue1;
std::mt19937_64::result_type oValue2;
for (int i = 0; i < 20; i++) {
oValue1 = (std::mt19937_64::result_type) std::chrono::duration_cast<std::chrono::seconds>(
std::chrono::system_clock::now().time_since_epoch()
).count();
oValue2 = (std::mt19937_64::result_type) std::chrono::duration_cast<std::chrono::microseconds>(
std::chrono::system_clock::now().time_since_epoch()
).count();
oSeed = oRandomDevice() ^ (oValue1 + oValue2);
oNumber.seed(oSeed);
cout << "oNumber: " << oNumber << "\n";
cout << "oNumber.default_seed: " << oNumber.default_seed << "\n";
cout << "oNumber.initialization_multiplier: " << oNumber.initialization_multiplier << "\n";
cout << "oNumber.mask_bits: " << oNumber.mask_bits << "\n";
cout << "oNumber.max(): " << oNumber.max() << "\n";
cout << "oNumber.min(): " << oNumber.min() << "\n";
cout << "oNumber.shift_size: " << oNumber.shift_size << "\n";
cout << "oNumber.state_size: " << oNumber.state_size << "\n";
cout << "oNumber.tempering_b: " << oNumber.tempering_b << "\n";
cout << "oNumber.tempering_c: " << oNumber.tempering_c << "\n";
cout << "oNumber.tempering_d: " << oNumber.tempering_d << "\n";
cout << "oNumber.tempering_l: " << oNumber.tempering_l << "\n";
cout << "oNumber.tempering_s: " << oNumber.tempering_s << "\n";
cout << "oNumber.tempering_t: " << oNumber.tempering_t << "\n";
cout << "oNumber.tempering_u: " << oNumber.tempering_u << "\n";
cout << "oNumber.word_size: " << oNumber.word_size << "\n";
cout << "oNumber.xor_mask: " << oNumber.xor_mask << "\n";
cout << "oNumber._Max: " << oNumber._Max << "\n";
cout << "oNumber._Min: " << oNumber._Min << "\n";
}
cout << "Random v2" << endl;
return 0;
}
为每个RUN文件随机
size_t randomGenerator(size_t min, size_t max) {
std::mt19937 rng;
rng.seed(std::random_device()());
//rng.seed(std::chrono::high_resolution_clock::now().time_since_epoch().count());
std::uniform_int_distribution<std::mt19937::result_type> dist(min, max);
return dist(rng);
}
我知道如何在c++中生成随机数，而不使用任何标头，编译器intrinsic或任何东西。
#include <cstdio> // Just for printf
int main() {
auto val = new char[0x10000];
auto num = reinterpret_cast<unsigned long long>(val);
delete[] val;
num = num / 0x1000 % 10;
printf("%llu\n", num);
}
在运行一段时间后，我得到了以下数据:
0: 5268
1: 5284
2: 5279
3: 5242
4: 5191
5: 5135
6: 5183
7: 5236
8: 5372
9: 5343
看起来是随机的。
工作原理:
现代编译器使用ASLR(地址空间布局随机化)防止缓冲区溢出。 你可以不使用任何库生成一些随机数，这只是为了好玩。不要那样使用ASLR。
