function getRandomColor()
{
    var color = "#";

    for (var i = 0; i < 3; i++)
    {
        var part = Math.round(Math.random() * 255).toString(16);

        color += (part.length > 1) ? part : "0" + part;
    }

    return color;
}

使用getRandomColor()代替“#0000FF”:

function getRandomColor() { var letters = '0123456789ABCDEF'; var color = '#'; for (var i = 0; i < 6; i++) { color += letters[Math.floor(Math.random() * 16)]; } return color; } function setRandomColor() { $("#colorpad").css("background-color", getRandomColor()); } <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div id="colorpad" style="width:300px;height:300px;background-color:#000"> </div> <button onclick="setRandomColor()">Random Color</button>

一个工作的单行解决方案(前导零填充):

var color = "#" + "colors".split("").map(function(){return parseInt(Math.random()*0x10).toString(16);}).join("");

下面是@Anatoliy提供的解决方案。

我只需要生成浅色(作为背景)，所以我使用了三个字母(#AAA)格式:

function get_random_color() {
    var letters = 'ABCDE'.split('');
    var color = '#';
    for (var i=0; i<3; i++ ) {
        color += letters[Math.floor(Math.random() * letters.length)];
    }
    return color;
}

function randomColor(format = 'hex') {
    const rnd = Math.random().toString(16).slice(-6);
    if (format === 'hex') {
        return '#' + rnd;
    }
    if (format === 'rgb') {
        const [r, g, b] = rnd.match(/.{2}/g).map(c=>parseInt(c, 16));
        return `rgb(${r}, ${g}, ${b})`;
    }
}

var html = '';
var red;
var green;
var blue;
var rgbColor;

for ( var i = 1; i <= 100; i += 1) {
  red = Math.floor(Math.random() * 256 );
  green = Math.floor(Math.random() * 256 );
  blue = Math.floor(Math.random() * 256 );
  rgbColor = 'rgb(' + red + ',' + green + ',' + blue + ')';
  html += '<div style="background-color:' + rgbColor + '"></div>';  
}

document.write(html);