我希望使用shell脚本调用长形式和短形式的命令行选项。
我知道可以使用getopts，但是像在Perl中一样，我不能用shell做同样的事情。
关于如何做到这一点的任何想法，这样我就可以使用如下选项:
./shell.sh --copyfile abc.pl /tmp/
./shell.sh -c abc.pl /tmp/
在上面，这两个命令对我的shell意味着同样的事情，但使用getopts，我还不能实现这些?
当前回答
我只是偶尔写一些shell脚本，但没有实践经验，所以任何反馈都很感激。
使用@Arvid Requate提出的策略，我们注意到一些用户错误。忘记包含值的用户会意外地将下一个选项的名称视为值:
./getopts_test.sh --loglevel= --toc=TRUE
将导致"loglevel"的值被视为"——toc=TRUE"。这可以 被避免的。
我从http://mwiki.wooledge.org/BashFAQ/035关于手动解析的讨论中改编了一些关于检查CLI用户错误的想法。我在处理"-"和"——"参数时插入了错误检查。
然后我开始摆弄语法，所以这里的任何错误都是我的错，而不是原始作者的错。
我的方法可以帮助那些喜欢输入带等号或不带等号的长字符的用户。也就是说，它对“——loglevel 9”的响应应该与“——loglevel=9”的响应相同。在——/space方法中，不可能确定用户是否忘记了一个参数，因此需要进行一些猜测。
如果用户使用长/等号格式(——opt=)，则=后的空格会触发错误，因为没有提供参数。 如果user有长/空格参数(——opt)，如果后面没有参数(命令结束)或参数以破折号开头，该脚本将导致失败。
In case you are starting out on this, there is an interesting difference between "--opt=value" and "--opt value" formats. With the equal sign, the command line argument is seen as "opt=value" and the work to handle that is string parsing, to separate at the "=". In contrast, with "--opt value", the name of the argument is "opt" and we have the challenge of getting the next value supplied in the command line. That's where @Arvid Requate used ${!OPTIND}, the indirect reference. I still don't understand that, well, at all, and comments in BashFAQ seem to warn against that style (http://mywiki.wooledge.org/BashFAQ/006). BTW, I don't think previous poster's comments about importance of OPTIND=$(( $OPTIND + 1 )) are correct. I mean to say, I see no harm from omitting it.
在该脚本的最新版本中，flag -v表示详细打印输出。
将其保存在一个名为“cli-5.sh”的文件中，使其可执行，其中任何一个都将以预期的方式工作或失败
./cli-5.sh -v --loglevel=44 --toc TRUE
./cli-5.sh -v --loglevel=44 --toc=TRUE
./cli-5.sh --loglevel 7
./cli-5.sh --loglevel=8
./cli-5.sh -l9
./cli-5.sh --toc FALSE --loglevel=77
./cli-5.sh --toc=FALSE --loglevel=77
./cli-5.sh -l99 -t yyy
./cli-5.sh -l 99 -t yyy
下面是对用户intpu进行错误检查的示例输出
$ ./cli-5.sh --toc --loglevel=77
ERROR: toc value must not have dash at beginning
$ ./cli-5.sh --toc= --loglevel=77
ERROR: value for toc undefined
您应该考虑打开-v，因为它会打印OPTIND和OPTARG的内部内容
#/usr/bin/env bash
## Paul Johnson
## 20171016
##
## Combines ideas from
## https://stackoverflow.com/questions/402377/using-getopts-in-bash-shell-script-to-get-long-and-short-command-line-options
## by @Arvid Requate, and http://mwiki.wooledge.org/BashFAQ/035
# What I don't understand yet:
# In @Arvid REquate's answer, we have
# val="${!OPTIND}"; OPTIND=$(( $OPTIND + 1 ))
# this works, but I don't understand it!
die() {
printf '%s\n' "$1" >&2
exit 1
}
printparse(){
if [ ${VERBOSE} -gt 0 ]; then
printf 'Parse: %s%s%s\n' "$1" "$2" "$3" >&2;
fi
}
showme(){
if [ ${VERBOSE} -gt 0 ]; then
printf 'VERBOSE: %s\n' "$1" >&2;
fi
}
VERBOSE=0
loglevel=0
toc="TRUE"
optspec=":vhl:t:-:"
while getopts "$optspec" OPTCHAR; do
showme "OPTARG: ${OPTARG[*]}"
showme "OPTIND: ${OPTIND[*]}"
case "${OPTCHAR}" in
-)
case "${OPTARG}" in
loglevel) #argument has no equal sign
opt=${OPTARG}
val="${!OPTIND}"
## check value. If negative, assume user forgot value
showme "OPTIND is {$OPTIND} {!OPTIND} has value \"${!OPTIND}\""
if [[ "$val" == -* ]]; then
die "ERROR: $opt value must not have dash at beginning"
fi
## OPTIND=$(( $OPTIND + 1 )) # CAUTION! no effect?
printparse "--${OPTARG}" " " "${val}"
loglevel="${val}"
shift
;;
loglevel=*) #argument has equal sign
opt=${OPTARG%=*}
val=${OPTARG#*=}
if [ "${OPTARG#*=}" ]; then
printparse "--${opt}" "=" "${val}"
loglevel="${val}"
## shift CAUTION don't shift this, fails othewise
else
die "ERROR: $opt value must be supplied"
fi
;;
toc) #argument has no equal sign
opt=${OPTARG}
val="${!OPTIND}"
## check value. If negative, assume user forgot value
showme "OPTIND is {$OPTIND} {!OPTIND} has value \"${!OPTIND}\""
if [[ "$val" == -* ]]; then
die "ERROR: $opt value must not have dash at beginning"
fi
## OPTIND=$(( $OPTIND + 1 )) #??
printparse "--${opt}" " " "${val}"
toc="${val}"
shift
;;
toc=*) #argument has equal sign
opt=${OPTARG%=*}
val=${OPTARG#*=}
if [ "${OPTARG#*=}" ]; then
toc=${val}
printparse "--$opt" " -> " "$toc"
##shift ## NO! dont shift this
else
die "ERROR: value for $opt undefined"
fi
;;
help)
echo "usage: $0 [-v] [--loglevel[=]<value>] [--toc[=]<TRUE,FALSE>]" >&2
exit 2
;;
*)
if [ "$OPTERR" = 1 ] && [ "${optspec:0:1}" != ":" ]; then
echo "Unknown option --${OPTARG}" >&2
fi
;;
esac;;
h|-\?|--help)
## must rewrite this for all of the arguments
echo "usage: $0 [-v] [--loglevel[=]<value>] [--toc[=]<TRUE,FALSE>]" >&2
exit 2
;;
l)
loglevel=${OPTARG}
printparse "-l" " " "${loglevel}"
;;
t)
toc=${OPTARG}
;;
v)
VERBOSE=1
;;
*)
if [ "$OPTERR" != 1 ] || [ "${optspec:0:1}" = ":" ]; then
echo "Non-option argument: '-${OPTARG}'" >&2
fi
;;
esac
done
echo "
After Parsing values
"
echo "loglevel $loglevel"
echo "toc $toc"
其他回答
Getopts“可以用来”解析长选项，只要你不希望它们有参数……
以下是如何:
$ cat > longopt
while getopts 'e:-:' OPT; do
case $OPT in
e) echo echo: $OPTARG;;
-) #long option
case $OPTARG in
long-option) echo long option;;
*) echo long option: $OPTARG;;
esac;;
esac
done
$ bash longopt -e asd --long-option --long1 --long2 -e test
echo: asd
long option
long option: long1
long option: long2
echo: test
如果尝试使用OPTIND获取长选项的参数，getopts将把它作为第一个不可选的位置参数，并停止解析任何其他参数。 在这种情况下，您最好使用简单的case语句手动处理它。
这将“总是”工作:
$ cat >longopt2
while (($#)); do
OPT=$1
shift
case $OPT in
--*) case ${OPT:2} in
long1) echo long1 option;;
complex) echo comples with argument $1; shift;;
esac;;
-*) case ${OPT:1} in
a) echo short option a;;
b) echo short option b with parameter $1; shift;;
esac;;
esac
done
$ bash longopt2 --complex abc -a --long -b test
comples with argument abc
short option a
short option b with parameter test
尽管它不像getopts那么灵活，而且你必须在用例实例中自己做很多错误检查代码……
但这是一种选择。
另一种方式…
# translate long options to short
for arg
do
delim=""
case "$arg" in
--help) args="${args}-h ";;
--verbose) args="${args}-v ";;
--config) args="${args}-c ";;
# pass through anything else
*) [[ "${arg:0:1}" == "-" ]] || delim="\""
args="${args}${delim}${arg}${delim} ";;
esac
done
# reset the translated args
eval set -- $args
# now we can process with getopt
while getopts ":hvc:" opt; do
case $opt in
h) usage ;;
v) VERBOSE=true ;;
c) source $OPTARG ;;
\?) usage ;;
:)
echo "option -$OPTARG requires an argument"
usage
;;
esac
done
如果你不想要getopt依赖，你可以这样做:
while test $# -gt 0
do
case $1 in
# Normal option processing
-h | --help)
# usage and help
;;
-v | --version)
# version info
;;
# ...
# Special cases
--)
break
;;
--*)
# error unknown (long) option $1
;;
-?)
# error unknown (short) option $1
;;
# FUN STUFF HERE:
# Split apart combined short options
-*)
split=$1
shift
set -- $(echo "$split" | cut -c 2- | sed 's/./-& /g') "$@"
continue
;;
# Done with options
*)
break
;;
esac
# for testing purposes:
echo "$1"
shift
done
当然，这样你就不能使用长样式选项。如果你想添加缩短的版本(例如——verbos而不是——verbose)，那么你需要手动添加这些。
但是如果您希望获得getopts功能和长选项，这是一种简单的方法。
我也把这个片段作为一个主旨。
例如，如果所有长选项都有唯一且匹配的首字符作为短选项
./slamm --chaos 23 --plenty test -quiet
和
./slamm -c 23 -p test -q
你可以在getopts重写$args之前使用它:
# change long options to short options
for arg; do
[[ "${arg:0:1}" == "-" ]] && delim="" || delim="\""
if [ "${arg:0:2}" == "--" ];
then args="${args} -${arg:2:1}"
else args="${args} ${delim}${arg}${delim}"
fi
done
# reset the incoming args
eval set -- $args
# proceed as usual
while getopts ":b:la:h" OPTION; do
.....
谢谢mtvee的灵感;-)
下面是一个实际使用长选项的getopt的示例:
aflag=no
bflag=no
cargument=none
# options may be followed by one colon to indicate they have a required argument
if ! options=$(getopt -o abc: -l along,blong,clong: -- "$@")
then
# something went wrong, getopt will put out an error message for us
exit 1
fi
set -- $options
while [ $# -gt 0 ]
do
case $1 in
-a|--along) aflag="yes" ;;
-b|--blong) bflag="yes" ;;
# for options with required arguments, an additional shift is required
-c|--clong) cargument="$2" ; shift;;
(--) shift; break;;
(-*) echo "$0: error - unrecognized option $1" 1>&2; exit 1;;
(*) break;;
esac
shift
done
