假设你在问为什么你不能这样做:

public interface IFoo {
    void Bar();
}

public class Foo: IFoo {
    public static void Bar() {}
}

This doesn't make sense to me, semantically. Methods specified on an interface should be there to specify the contract for interacting with an object. Static methods do not allow you to interact with an object - if you find yourself in the position where your implementation could be made static, you may need to ask yourself if that method really belongs in the interface. To implement your example, I would give Animal a const property, which would still allow it to be accessed from a static context, and return that value in the implementation.

public class Animal: IListItem {
    /* Can be tough to come up with a different, yet meaningful name!
     * A different casing convention, like Java has, would help here.
     */
    public const string AnimalScreenName = "Animal";
    public string ScreenName(){ return AnimalScreenName; }
}

对于更复杂的情况，您总是可以声明另一个静态方法并委托给它。在尝试给出一个例子的过程中，我想不出您在静态和实例上下文中都要做一些非平凡的事情的任何理由，因此我将给您一个FooBar blob，并将其作为它可能不是一个好主意的指示。

因为接口的目的是允许多态性，能够传递任意数量的已定义类的实例，这些类都已定义，以实现已定义的接口……确保在多态调用中，代码能够找到您正在调用的方法。允许静态方法实现接口是没有意义的，

你怎么称呼它??

public interface MyInterface { void MyMethod(); }
public class MyClass: MyInterface
{
    public static void MyMethod() { //Do Something; }
}

 // inside of some other class ...  
 // How would you call the method on the interface ???
    MyClass.MyMethod();  // this calls the method normally 
                         // not through the interface...

    // This next fails you can't cast a classname to a different type... 
    // Only instances can be Cast to a different type...
    MyInterface myItf = MyClass as MyInterface;  

供您参考:您可以通过为接口创建扩展方法来获得与您想要的类似的行为。扩展方法将是一个共享的、不可覆盖的静态行为。然而，不幸的是，这个静态方法不是契约的一部分。

I think the question is getting at the fact that C# needs another keyword, for precisely this sort of situation. You want a method whose return value depends only on the type on which it is called. You can't call it "static" if said type is unknown. But once the type becomes known, it will become static. "Unresolved static" is the idea -- it's not static yet, but once we know the receiving type, it will be. This is a perfectly good concept, which is why programmers keep asking for it. But it didn't quite fit into the way the designers thought about the language.

因为它不可用，所以我采用如下所示的方式使用非静态方法。虽然不太理想，但至少对我来说，我找不到比这更有意义的方法了。

public interface IZeroWrapper<TNumber> {
  TNumber Zero {get;}
}

public class DoubleWrapper: IZeroWrapper<double> {
  public double Zero { get { return 0; } }
}

举一个例子，我既没有接口方法的静态实现，也没有Mark Brackett介绍的“所谓的类型方法”:

当从数据库存储中读取数据时，我们有一个通用的DataTable类来处理从任何结构的表中读取数据。所有特定于表的信息都放在每个表的一个类中，每个表还保存来自DB的一行的数据，并且必须实现IDataRow接口。IDataRow中包含了要从数据库中读取的表的结构描述。DataTable在从DB中读取数据之前必须向IDataRow请求数据结构。目前看起来是这样的:

interface IDataRow {
  string GetDataSTructre();  // How to read data from the DB
  void Read(IDBDataRow);     // How to populate this datarow from DB data
}

public class DataTable<T> : List<T> where T : IDataRow {

  public string GetDataStructure()
    // Desired: Static or Type method:
    // return (T.GetDataStructure());
    // Required: Instantiate a new class:
    return (new T().GetDataStructure());
  }

}

每个表只需要读取一次GetDataStructure，实例化一个实例的开销是最小的。但是，在这种情况下它会很好。

您可以将类的静态方法和非静态方法看作是不同的接口。调用时，静态方法解析为单例静态类对象，而非静态方法解析为所处理的类的实例。所以，如果你在一个接口中使用静态和非静态方法，你实际上是在声明两个接口，而实际上我们想要接口被用来访问一个内聚的东西。