如何将颜色在RGB格式转换为十六进制格式,反之亦然?
例如,将'#0080C0'转换为(0,128,192)。
如何将颜色在RGB格式转换为十六进制格式,反之亦然?
例如,将'#0080C0'转换为(0,128,192)。
当前回答
这个代码片段将十六进制转换为rgb, rgb转换为十六进制。
视图演示
function hexToRgb(str) {
if ( /^#([0-9a-f]{3}|[0-9a-f]{6})$/ig.test(str) ) {
var hex = str.substr(1);
hex = hex.length == 3 ? hex.replace(/(.)/g, '$1$1') : hex;
var rgb = parseInt(hex, 16);
return 'rgb(' + [(rgb >> 16) & 255, (rgb >> 8) & 255, rgb & 255].join(',') + ')';
}
return false;
}
function rgbToHex(red, green, blue) {
var out = '#';
for (var i = 0; i < 3; ++i) {
var n = typeof arguments[i] == 'number' ? arguments[i] : parseInt(arguments[i]);
if (isNaN(n) || n < 0 || n > 255) {
return false;
}
out += (n < 16 ? '0' : '') + n.toString(16);
}
return out
}
其他回答
RGB转十六进制
使用padStart ()
你可以使用padStart()来使用这个在线程序:
RGB = (r, g, b) => { 返回' #${[r, g, b].map((x) => x. tostring(16)。padStart(“0”)). join (" ")} '; }
另外,它在传统浏览器上不受支持,请在这里检查它的兼容性。
没有padStart ()
如果你不想使用padStart(),你可以实现这个函数:
RGB = (r, g, b) => { 返回' #${[r, g, b] . map ((n) = > n.toString(16)。长度=== 1 ?“0”+ n.toString(16): n.toString(16) ) . join (" ")} '; };
参数验证
如果你不确定谁将使用你的函数,你必须使用参数验证,即值是有效的(0到255之间),要做到这一点,在每次返回之前添加这些条件:
If (r > 255) r = 255;if (r < 0) r = 0; If (g > 255) g = 255;if (g < 0) g = 0; If (b > 255) b = 255;如果(b < 0) b = 0;
所以上面两个例子就变成了:
const rgb = (r, g, b) => { if (r > 255) r = 255; else if (r < 0) r = 0; if (g > 255) g = 255; else if (g < 0) g = 0; if (b > 255) b = 255; else if (b < 0) b = 0; return `#${[r, g, b].map((x) => x.toString(16).padStart(2, "0")).join("")}`; }; const rgb2 = (r, g, b) => { if (r > 255) r = 255; else if (r < 0) r = 0; if (g > 255) g = 255; else if (g < 0) g = 0; if (b > 255) b = 255; else if (b < 0) b = 0; return `#${[r, g, b] .map((n) => n.toString(16).length === 1 ? "0" + n.toString(16) : n.toString(16) ) .join("")}`; };
十六进制到RGB
为此,我们将使用一些RegEx:
Const hex = (h) => { 返回h .replace ( / ^ # ? (\ d] [a - f) (\ d] [a - f) (\ d] [a - f) /我美元, (_, r, g, b) => "#" + r + r + g + g + b + b ) .substring (1) .match (/ {2} / g)。 .map((x) => parseInt(x, 16)); };
My example =) color: { toHex: function(num){ var str = num.toString(16); return (str.length<6?'#00'+str:'#'+str); }, toNum: function(hex){ return parseInt(hex.replace('#',''), 16); }, rgbToHex: function(color) { color = color.replace(/\s/g,""); var aRGB = color.match(/^rgb\((\d{1,3}[%]?),(\d{1,3}[%]?),(\d{1,3}[%]?)\)$/i); if(aRGB) { color = ''; for (var i=1; i<=3; i++) color += Math.round((aRGB[i][aRGB[i].length-1]=="%"?2.55:1)*parseInt(aRGB[i])).toString(16).replace(/^(.)$/,'0$1'); } else color = color.replace(/^#?([\da-f])([\da-f])([\da-f])$/i, '$1$1$2$2$3$3'); return '#'+color; }
哇。这些答案都不能处理分数的边缘情况,等等。当r, g, b为零时,位移版本也不起作用。
这是一个可以处理r g b是小数的版本。它对颜色之间的插值很有用,所以我也包括了这段代码。但它仍然不能处理r, g, b在0-255范围之外的情况
/**
* Operates with colors.
* @class Q.Colors
*/
Q.Color = {
/**
* Get a color somewhere between startColor and endColor
* @method toHex
* @static
* @param {String|Number} startColor
* @param {String|Number} endColor
* @param {String|Number} fraction
* @returns {String} a color as a hex string without '#' in front
*/
toHex: function (r, g, b) {
return [r, g, b].map(x => {
const hex = Math.round(x).toString(16)
return hex.length === 1 ? '0' + hex : hex
}).join('');
},
/**
* Get a color somewhere between startColor and endColor
* @method between
* @static
* @param {String|Number} startColor
* @param {String|Number} endColor
* @param {String|Number} fraction
* @returns {String} a color as a hex string without '#' in front
*/
between: function(startColor, endColor, fraction) {
if (typeof startColor === 'string') {
startColor = parseInt(startColor.replace('#', '0x'), 16);
}
if (typeof endColor === 'string') {
endColor = parseInt(endColor.replace('#', '0x'), 16);
}
var startRed = (startColor >> 16) & 0xFF;
var startGreen = (startColor >> 8) & 0xFF;
var startBlue = startColor & 0xFF;
var endRed = (endColor >> 16) & 0xFF;
var endGreen = (endColor >> 8) & 0xFF;
var endBlue = endColor & 0xFF;
var newRed = startRed + fraction * (endRed - startRed);
var newGreen = startGreen + fraction * (endGreen - startGreen);
var newBlue = startBlue + fraction * (endBlue - startBlue);
return Q.Color.toHex(newRed, newGreen, newBlue);
},
/**
* Sets a new theme-color on the window
* @method setWindowTheme
* @static
* @param {String} color in any CSS format, such as "#aabbcc"
* @return {String} the previous color
*/
setWindowTheme: function (color) {
var meta = document.querySelector('meta[name="theme-color"]');
var prevColor = null;
if (meta) {
prevColor = meta.getAttribute('content');
}
if (color) {
if (!meta) {
meta = document.createElement('meta');
meta.setAttribute('name', 'theme-color');
}
meta.setAttribute('content', color);
}
return prevColor;
},
/**
* Gets the current window theme color
* @method getWindowTheme
* @static
* @param {String} color in any CSS format, such as "#aabbcc"
* @return {String} the previous color
*/
getWindowTheme: function () {
var meta = document.querySelector('meta[name="theme-color"]');
return meta.getAttribute('content');
}
}
我正在使用XAML数据,具有十六进制格式的#AARRGGBB (Alpha,红色,绿色,蓝色)。利用上面的答案,以下是我的解决方案:
function hexToRgba(hex) {
var bigint, r, g, b, a;
//Remove # character
var re = /^#?/;
var aRgb = hex.replace(re, '');
bigint = parseInt(aRgb, 16);
//If in #FFF format
if (aRgb.length == 3) {
r = (bigint >> 4) & 255;
g = (bigint >> 2) & 255;
b = bigint & 255;
return "rgba(" + r + "," + g + "," + b + ",1)";
}
//If in #RRGGBB format
if (aRgb.length >= 6) {
r = (bigint >> 16) & 255;
g = (bigint >> 8) & 255;
b = bigint & 255;
var rgb = r + "," + g + "," + b;
//If in #AARRBBGG format
if (aRgb.length == 8) {
a = ((bigint >> 24) & 255) / 255;
return "rgba(" + rgb + "," + a.toFixed(1) + ")";
}
}
return "rgba(" + rgb + ",1)";
}
http://jsfiddle.net/kvLyscs3/
对于直接从jQuery转换,您可以尝试:
function rgbToHex(color) {
var bg = color.match(/^rgb\((\d+),\s*(\d+),\s*(\d+)\)$/);
function hex(x) {
return ("0" + parseInt(x).toString(16)).slice(-2);
}
return "#" + hex(bg[1]) + hex(bg[2]) + hex(bg[3]);
}
rgbToHex($('.col-tab-bar .col-tab span').css('color'))